- Added Python solution to "Middle 3-digits" task of week 135.

1 files changed, 58 insertions, 0 deletions

diff --git a/challenge-135/mohammad-anwar/python/ch-1.py b/challenge-135/mohammad-anwar/python/ch-1.py
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+++ b/challenge-135/mohammad-anwar/python/ch-1.py
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+#!/usr/bin/python3
+
+'''
+
+Week 135:
+
+    https://theweeklychallenge.org/blog/perl-weekly-challenge-135
+
+Task #1: Middle 3-digits
+
+    You are given an integer.
+
+    Write a script find out the middle 3-digits of the given integer, if possible otherwise throw sensible error.
+
+'''
+
+import sys, math, re, getopt
+
+def main(argv):
+    try:
+        opts, arg = getopt.getopt(argv, "hn:", ["number="])
+    except getopt.GetoptError:
+        print('ch-1.py -n <number>')
+        sys.exit(2)
+
+    for opt, arg in opts:
+        if opt == '-h':
+            print('ch-1.py -n <number>')
+            sys.exit()
+        elif opt in ("-n", "--number"):
+            number = arg
+
+    valid = re.compile('^\-?\d+$')
+    if valid.match(number):
+        num  = abs(int(number))
+        size = int_size(num)
+
+        if size == 1:
+            print('ERROR: Too short')
+            sys.exit()
+
+        if size % 2 == 0:
+            print('ERROR: Even number of digits.')
+            sys.exit()
+
+        i = int(size / 2) - 1
+        s = str(num)
+
+        print(s[i:i+3])
+
+    else:
+        print('Invalid number')
+
+def int_size(n):
+    return 1 + math.floor(math.log10(n))
+
+if __name__ == "__main__":
+    main(sys.argv[1:])