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-rw-r--r--challenge-341/pokgopun/python/ch-1.py74
-rw-r--r--challenge-341/pokgopun/python/ch-2.py71
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diff --git a/challenge-341/pokgopun/python/ch-1.py b/challenge-341/pokgopun/python/ch-1.py
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+++ b/challenge-341/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-341/
+"""
+
+Task 1: Broken Keyboard
+
+Submitted by: [39]Mohammad Sajid Anwar
+ __________________________________________________________________
+
+ You are given a string containing English letters only and also you are
+ given broken keys.
+
+ Write a script to return the total words in the given sentence can be
+ typed completely.
+
+Example 1
+
+Input: $str = 'Hello World', @keys = ('d')
+Output: 1
+
+With broken key 'd', we can only type the word 'Hello'.
+
+Example 2
+
+Input: $str = 'apple banana cherry', @keys = ('a', 'e')
+Output: 0
+
+Example 3
+
+Input: $str = 'Coding is fun', @keys = ()
+Output: 3
+
+No keys broken.
+
+Example 4
+
+Input: $str = 'The Weekly Challenge', @keys = ('a','b')
+Output: 2
+
+Example 5
+
+Input: $str = 'Perl and Python', @keys = ('p')
+Output: 1
+
+Task 2: Reverse Prefix
+"""
+### solution by pokgopun@gmail.com
+
+def bk(string: str, keys: tuple[str]) -> int:
+ cnt = 0
+ string = string.lower()
+ for w in string.split(" "):
+ for k in keys:
+ #print(w,k)
+ if w.find(k) != -1:
+ break
+ else:
+ cnt += 1
+ return cnt
+
+import unittest
+
+class TestBk(unittest.TestCase):
+ def test(self):
+ for (string, keys), otpt in {
+ ('Hello World', ('d')): 1,
+ ('apple banana cherry', ('a', 'e')): 0,
+ ('Coding is fun', ()): 3,
+ ('The Weekly Challenge', ('a','b')): 2,
+ ('Perl and Python', ('p')): 1,
+ }.items():
+ #print(string,keys)
+ self.assertEqual(bk(string,keys),otpt)
+
+unittest.main()
diff --git a/challenge-341/pokgopun/python/ch-2.py b/challenge-341/pokgopun/python/ch-2.py
new file mode 100644
index 0000000000..621c8b3776
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+++ b/challenge-341/pokgopun/python/ch-2.py
@@ -0,0 +1,71 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-341/
+"""
+
+Task 2: Reverse Prefix
+
+Submitted by: [40]Mohammad Sajid Anwar
+ __________________________________________________________________
+
+ You are given a string, $str and a character in the given string,
+ $char.
+
+ Write a script to reverse the prefix upto the first occurrence of the
+ given $char in the given string $str and return the new string.
+
+Example 1
+
+Input: $str = "programming", $char = "g"
+Output: "gorpramming"
+
+Reverse of prefix "prog" is "gorp".
+
+Example 2
+
+Input: $str = "hello", $char = "h"
+Output: "hello"
+
+Example 3
+
+Input: $str = "abcdefghij", $char = "h"
+Output: "hgfedcbaij"
+
+Example 4
+
+Input: $str = "reverse", $char = "s"
+Output: "srevere"
+
+Example 5
+
+Input: $str = "perl", $char = "r"
+Output: "repl"
+ __________________________________________________________________
+
+ Last date to submit the solution 23:59 (UK Time) Sunday 5th October
+ 2025.
+ __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def rp(string: str, char: str) -> str:
+ string
+ i = string.find(char)
+ if i == -1:
+ return string
+ return "".join(reversed(string[:i+1])) + string[i+1:]
+
+import unittest
+
+class TestRp(unittest.TestCase):
+ def test(self):
+ for (string,char), otpt in {
+ ("programming", "g"): "gorpramming",
+ ("hello", "h"): "hello",
+ ("abcdefghij", "h"): "hgfedcbaij",
+ ("reverse", "s"): "srevere",
+ ("perl", "r"): "repl",
+ }.items():
+ self.assertEqual(rp(string,char),otpt)
+
+unittest.main()