From f00547cd9eb3f1cd8cd132e2a410b5bd5d2c5b7b Mon Sep 17 00:00:00 2001
From: Paulo Custodio <pauloscustodio@gmail.com>
Date: Mon, 27 Mar 2023 16:47:37 +0100
Subject: Add C++ solution

---
 challenge-194/paulo-custodio/cpp/ch-1.cpp | 54 ++++++++++++++++++++++++
 challenge-194/paulo-custodio/cpp/ch-2.cpp | 68 +++++++++++++++++++++++++++++++
 2 files changed, 122 insertions(+)
 create mode 100644 challenge-194/paulo-custodio/cpp/ch-1.cpp
 create mode 100644 challenge-194/paulo-custodio/cpp/ch-2.cpp

diff --git a/challenge-194/paulo-custodio/cpp/ch-1.cpp b/challenge-194/paulo-custodio/cpp/ch-1.cpp
new file mode 100644
index 0000000000..f4b8a6c537
--- /dev/null
+++ b/challenge-194/paulo-custodio/cpp/ch-1.cpp
@@ -0,0 +1,54 @@
+/*
+Challenge 194
+
+Task 1: Digital Clock
+Submitted by: Mohammad S Anwar
+You are given time in the format hh:mm with one missing digit.
+
+Write a script to find the highest digit between 0-9 that makes it valid time.
+
+Example 1
+Input: $time = '?5:00'
+Output: 1
+
+Since 05:00 and 15:00 are valid time and no other digits can fit in the missing place.
+Example 2
+Input: $time = '?3:00'
+Output: 2
+Example 3
+Input: $time = '1?:00'
+Output: 9
+Example 4
+Input: $time = '2?:00'
+Output: 3
+Example 5
+Input: $time = '12:?5'
+Output: 5
+Example 6
+Input: $time =  '12:5?'
+Output: 9
+*/
+
+#include <iostream>
+#include <string>
+
+int missing_digit(const std::string& clock) {
+    if (clock.size()!=5) return -1;
+    if (clock[0]=='?' && clock[1]<='3') return 2;
+    if (clock[0]=='?') return 1;
+    if (clock[0]<='1' && clock[1]=='?') return 9;
+    if (clock[1]=='?') return 3;
+    if (clock[3]=='?') return 5;
+    if (clock[4]=='?') return 9;
+    return -1;
+}
+
+int main(int argc, char* argv[]) {
+    argv++; argc--;
+    if (argc != 1) {
+        std::cerr << "usage: ch-1 hh:mm" << std::endl;
+        return EXIT_FAILURE;
+    }
+
+    std::cout << missing_digit(argv[0]) << std::endl;
+}
diff --git a/challenge-194/paulo-custodio/cpp/ch-2.cpp b/challenge-194/paulo-custodio/cpp/ch-2.cpp
new file mode 100644
index 0000000000..437629244c
--- /dev/null
+++ b/challenge-194/paulo-custodio/cpp/ch-2.cpp
@@ -0,0 +1,68 @@
+/*
+Challenge 194
+
+Task 2: Frequency Equalizer
+Submitted by: Mohammad S Anwar
+You are given a string made of alphabetic characters only, a-z.
+
+Write a script to determine whether removing only one character can make the
+frequency of the remaining characters the same.
+
+Example 1:
+Input: $s = 'abbc'
+Output: 1 since removing one alphabet 'b' will give us 'abc' where each
+alphabet frequency is the same.
+Example 2:
+Input: $s = 'xyzyyxz'
+Output: 1 since removing 'y' will give us 'xzyyxz'.
+Example 3:
+Input: $s = 'xzxz'
+Output: 0 since removing any one alphabet would not give us string with same
+frequency alphabet.
+*/
+
+#include <iostream>
+#include <string>
+#include <vector>
+#include <cctype>
+
+const int LETTERS = ('z'-'a'+1);
+
+int freq_equalizer(const std::string& s) {
+    std::vector<int> freq;
+    freq.resize(LETTERS);
+
+    if (s.empty()) return 0;
+    for (auto& c : s) {
+        if (isalpha(c))
+            freq[tolower(c)-'a']++;
+    }
+
+    int min=0, max=0;
+    for (auto& f : freq) {
+        if (f) {
+            if (min==0) min=max=f;
+            if (min>f) min=f;
+            if (max<f) max=f;
+        }
+    }
+
+    if (min+1!=max) return 0;
+
+    int count=0;
+    for (auto& f : freq) {
+        if (f==max) count++;
+    }
+
+    return count==1 ? 1 : 0;
+}
+
+int main(int argc, char* argv[]) {
+    argv++; argc--;
+    if (argc != 1) {
+        std::cerr << "usage: ch-1 string" << std::endl;
+        return EXIT_FAILURE;
+    }
+
+    std::cout << freq_equalizer(argv[0]) << std::endl;
+}
-- 
cgit