From d5d9907992a2d62978c0b511d0afb18b4013cf8d Mon Sep 17 00:00:00 2001 From: Paulo Custodio Date: Sat, 19 Jun 2021 21:14:03 +0100 Subject: Add C and C++ solution to challenge 005 --- challenge-005/paulo-custodio/cpp/ch-2.cpp | 66 +++++++++++++++++++++++++++++++ 1 file changed, 66 insertions(+) create mode 100644 challenge-005/paulo-custodio/cpp/ch-2.cpp (limited to 'challenge-005/paulo-custodio/cpp/ch-2.cpp') diff --git a/challenge-005/paulo-custodio/cpp/ch-2.cpp b/challenge-005/paulo-custodio/cpp/ch-2.cpp new file mode 100644 index 0000000000..7741b01977 --- /dev/null +++ b/challenge-005/paulo-custodio/cpp/ch-2.cpp @@ -0,0 +1,66 @@ +/* +Challenge 005 + +Challenge #2 +Write a program to find the sequence of characters that has the most anagrams. + +create a hash of all words in dictionary where key is sorted list of letters +therefore two anagrams have the same key +*/ + +#include +#include +#include +#include +#include +#include +using namespace std; + +map anagrams; + +void strtolower(string& str) { + for (size_t i = 0; i < str.size(); i++) + str[i] = tolower(str[i]); +} + +void word_key(string& key, const string& word) { + key = word; + sort(key.begin(), key.end()); +} + +int main() { + int max_anagrams = 0; + string key, line; + + ifstream ifs("words.txt"); + if (!ifs.is_open()) return EXIT_FAILURE; + + // collect anagram keys and count occurrences + while (getline(ifs, line)) { + strtolower(line); + word_key(key, line); + + auto found = anagrams.find(key); + if (found == anagrams.end()) { + anagrams[key] = 1; + + if (max_anagrams < 1) + max_anagrams = 1; + } + else { + found->second++; + + if (max_anagrams < found->second) + max_anagrams = found->second; + } + } + + // list anagrams + cout << "Maximum of " << max_anagrams << " anagrams" << endl; + for (auto& it : anagrams) { + if (it.second == max_anagrams) + cout << it.first << endl; + } + + return EXIT_SUCCESS; +} -- cgit