From 1801e66819957b886808c2e98508ca190d2b2432 Mon Sep 17 00:00:00 2001
From: Abigail <abigail@abigail.be>
Date: Tue, 15 Sep 2020 14:30:58 +0200
Subject: JavaScript solutions.

---
 challenge-078/abigail/Part2/solution.js | 33 +++++++++++++++++++++++++++++++++
 1 file changed, 33 insertions(+)
 create mode 100644 challenge-078/abigail/Part2/solution.js

(limited to 'challenge-078/abigail/Part2/solution.js')

diff --git a/challenge-078/abigail/Part2/solution.js b/challenge-078/abigail/Part2/solution.js
new file mode 100644
index 0000000000..6d76c9aa91
--- /dev/null
+++ b/challenge-078/abigail/Part2/solution.js
@@ -0,0 +1,33 @@
+//
+// Exercise:
+// 
+//   You are given array @A containing positive numbers and @B containing
+//   one or more indices from the array @A.
+//   Write a script to left rotate @A so that the number at the first index
+//   of @B becomes the first element in the array. Similary, left rotate @A
+//   again so that the number at the second index of @B becomes the first
+//   element in the array.
+//
+// We will be reading the arrays from STDIN -- @A is one the first
+// line, @B is on the second line.
+//
+
+//
+// Read two lines from STDIN, turn it into a string, strip off the
+// trailing newline (and any leading or trailing whitespace),
+// and then split in on spaces. Store the result into an arrays A and B.
+//
+let fs    = require ("fs");
+let lines = fs . readFileSync (0) . toString () . split ("\n");
+let A     = lines [0] . trim () . split (" ");
+let B     = lines [1] . trim () . split (" ");
+
+
+//
+// Iterate over the array B, and print the slices of A.
+//
+for (let i = 0; i < B . length; i ++) {
+    let index = +B [i];
+    console . log (A . slice (   index) . join (" ") + " " +
+                   A . slice (0, index) . join (" "));
+}
-- 
cgit