From c51f9bd979dbd79f20cb0abd543dc9b4df9f4e84 Mon Sep 17 00:00:00 2001
From: Paulo Custodio <pauloscustodio@gmail.com>
Date: Tue, 9 Mar 2021 20:01:18 +0000
Subject: Remove tabs

---
 challenge-101/paulo-custodio/lua/ch-1.lua | 18 +++++++++---------
 challenge-101/paulo-custodio/lua/ch-2.lua | 10 +++++-----
 2 files changed, 14 insertions(+), 14 deletions(-)

(limited to 'challenge-101/paulo-custodio/lua')

diff --git a/challenge-101/paulo-custodio/lua/ch-1.lua b/challenge-101/paulo-custodio/lua/ch-1.lua
index 7eac6f60f5..602143d1ee 100644
--- a/challenge-101/paulo-custodio/lua/ch-1.lua
+++ b/challenge-101/paulo-custodio/lua/ch-1.lua
@@ -8,10 +8,10 @@ Submitted by: Stuart Little
 
 You are given an array @A of items (integers say, but they can be anything).
 
-Your task is to pack that array into an MxN matrix spirally counterclockwise, 
+Your task is to pack that array into an MxN matrix spirally counterclockwise,
 as tightly as possible.
 
-‘Tightly’ means the absolute value |M-N| of the difference has to be as small 
+‘Tightly’ means the absolute value |M-N| of the difference has to be as small
 as possible.
 --]]
 
@@ -44,7 +44,7 @@ function build_empty_rectangle(m, n)
     local rect = {}
     for r=1, m do
         rect[r] = {}
-        for c=1, n do 
+        for c=1, n do
             rect[r][c] = ""
         end
     end
@@ -67,7 +67,7 @@ function spiral(numbers)
             i = i + 1
             c = c + 1
         end
-        c = c - 1 
+        c = c - 1
         r = r - 1
         -- go North
         while r >= 1 do
@@ -77,7 +77,7 @@ function spiral(numbers)
             i = i + 1
             r = r - 1
         end
-        r = r + 1 
+        r = r + 1
         c = c - 1
         -- go West
         while c >= 1 do
@@ -87,7 +87,7 @@ function spiral(numbers)
             i = i + 1
             c = c - 1
         end
-        c = c + 1 
+        c = c + 1
         r = r + 1
         -- go South
         while r <= m do
@@ -97,13 +97,13 @@ function spiral(numbers)
             i = i + 1
             r = r + 1
         end
-        r = r - 1 
+        r = r - 1
         c = c + 1
     end
-    
+
     -- print result
     for r=1, m do
-        for c=1, n do 
+        for c=1, n do
             io.write(rect[r][c])
         end
         io.write("\n")
diff --git a/challenge-101/paulo-custodio/lua/ch-2.lua b/challenge-101/paulo-custodio/lua/ch-2.lua
index 47a12b657e..54b02aa59d 100644
--- a/challenge-101/paulo-custodio/lua/ch-2.lua
+++ b/challenge-101/paulo-custodio/lua/ch-2.lua
@@ -5,10 +5,10 @@ Challenge 101
 
 TASK #2 › Origin-containing Triangle
 Submitted by: Stuart Little
-You are given three points in the plane, as a list of six co-ordinates: 
+You are given three points in the plane, as a list of six co-ordinates:
 A=(x1,y1), B=(x2,y2) and C=(x3,y3).
 
-Write a script to find out if the triangle formed by the given three 
+Write a script to find out if the triangle formed by the given three
 co-ordinates contain origin (0,0).
 
 Print 1 if found otherwise 0.
@@ -24,12 +24,12 @@ function point_in_triangle(xp,yp, x1,y1,x2,y2,x3,y3)
     local d3 = sign(xp,yp, x3,y3, x1,y1)
 
     local has_neg
-    if (d1 < 0) or (d2 < 0) or (d3 < 0) then 
+    if (d1 < 0) or (d2 < 0) or (d3 < 0) then
         has_neg = true
     else
         has_neg = false
     end
-    
+
     local has_neg = (d1 < 0) or (d2 < 0) or (d3 < 0)
     local has_pos = (d1 > 0) or (d2 > 0) or (d3 > 0)
 
@@ -40,7 +40,7 @@ function point_in_triangle(xp,yp, x1,y1,x2,y2,x3,y3)
     end
 end
 
-io.write(point_in_triangle(0,0, 
+io.write(point_in_triangle(0,0,
                            tonumber(arg[1]), tonumber(arg[2]),
                            tonumber(arg[3]), tonumber(arg[4]),
                            tonumber(arg[5]), tonumber(arg[6])), "\n")
-- 
cgit