From 08a76ad16ee62b2cbb2cda3508445047f2ff9cf1 Mon Sep 17 00:00:00 2001
From: Mohammad S Anwar <mohammad.anwar@yahoo.com>
Date: Tue, 11 Jan 2022 17:56:41 +0000
Subject: - Added guest contributions by Eric Cheung.

---
 challenge-147/eric-cheung/python/ch-2.py | 45 ++++++++++++++++++++++++++++++++
 1 file changed, 45 insertions(+)
 create mode 100755 challenge-147/eric-cheung/python/ch-2.py

(limited to 'challenge-147/eric-cheung/python/ch-2.py')

diff --git a/challenge-147/eric-cheung/python/ch-2.py b/challenge-147/eric-cheung/python/ch-2.py
new file mode 100755
index 0000000000..6a716b2ddd
--- /dev/null
+++ b/challenge-147/eric-cheung/python/ch-2.py
@@ -0,0 +1,45 @@
+## Remarks
+## https://www.mathblog.dk/project-euler-44-smallest-pair-pentagonal-numbers/
+## https://radiusofcircle.blogspot.com/2016/06/problem-44-project-euler-solution-with-python.html
+## http://radiusofcircle.blogspot.com
+
+## Time Module for Calculating Execution Time
+import time
+
+## Time At The Start of Program Execution
+dStartTime = time.time()
+
+def is_pentagonal(nInput):
+    ## Function To Check If The Number is Pentagonal Number or Not
+    if (1 + (24 * nInput + 1) ** 0.5) % 6 == 0:
+        return True
+    return False
+
+## Flag To Check If The Number Is Found Or Not
+bFlag = True
+
+# While Loop Iterator
+nLoop = 1
+
+# While Loop
+while bFlag:
+    nNum_01 = nLoop * (3 * nLoop - 1) / 2
+    for nSubLoop in range(1, nLoop):
+        nNum_02 = nSubLoop * (3 * nSubLoop - 1) / 2
+        if is_pentagonal(nNum_01 + nNum_02) and is_pentagonal(nNum_01 - nNum_02):
+            print ("nLoop = " + str(nLoop) + ", nSubLoop = " + str(nSubLoop))
+            bFlag = False
+            break
+    nLoop = nLoop + 1
+
+# Time At The End of Program Execution
+dEndTime = time.time()
+
+# Printing The Total Time For Execution
+print ("Time Needed: " + str(dEndTime - dStartTime))
+
+
+## Result
+## nLoop = 2167, nSubLoop = 1020
+## Time Needed: 1.1174473762512207
+
-- 
cgit