From d2aa2ab951a00427037aaf214b0e20e0d41a8b28 Mon Sep 17 00:00:00 2001 From: Mohammad S Anwar Date: Wed, 26 Jul 2023 00:42:23 +0100 Subject: - Added solutions by Robert DiCicco. - Added solutions by Mark Anderson. - Added solutions by Andrew Shitov. - Added solutions by Simon Proctor. - Added solutions by Luca Ferrari. - Added solutions by David Ferrone. - Added solutions by Thomas Kohler. - Added solutions by Robbie Hatley. - Added solutions by Ali Moradi. - Added solutions by W. Luis Mochan. - Added solutions by E. Choroba. - Added solutions by Roger Bell_West. - Added solutions by Peter Campbell Smith. --- challenge-227/robert-dicicco/python/ch-1.py | 52 +++++++++++++++++++++++++++++ 1 file changed, 52 insertions(+) create mode 100644 challenge-227/robert-dicicco/python/ch-1.py (limited to 'challenge-227/robert-dicicco/python/ch-1.py') diff --git a/challenge-227/robert-dicicco/python/ch-1.py b/challenge-227/robert-dicicco/python/ch-1.py new file mode 100644 index 0000000000..20c8ed326e --- /dev/null +++ b/challenge-227/robert-dicicco/python/ch-1.py @@ -0,0 +1,52 @@ +#!/usr/bin/env python +''' +------------------------------------- +AUTHOR: Robert DiCicco +DATE : 2023-07-24 +Challenge 227 Task 1 Friday 13th ( Python ) +------------------------------------- +''' + +from datetime import date +import sys + +n = len(sys.argv) +if n == 1: + print("Please select a year between 1753 and 9999") + sys.exit(0) + +year = int(sys.argv[1]) +if year < 1753 or year > 9999: + print("Please select a year between 1753 and 9999") + sys.exit(0) + +for month in range(1,12): + d = date(year, month, 13) + wd = d.weekday() + if wd == 4: # Monday = 0, Sunday = 6 + print(f"{year} {month} 13 is a Friday") + month += 1 + +''' +------------------------------------- +SAMPLE OUTPUT +python .\Friday13.py 2023 + +2023 1 13 is a Friday +2023 10 13 is a Friday + +python .\Friday13.py 1753 + +1753 4 13 is a Friday +1753 7 13 is a Friday +------------------------------------- +''' + + + + + + + + + -- cgit