From 2b419446ab484d93efadd0271caa060960fe08c8 Mon Sep 17 00:00:00 2001 From: Packy Anderson Date: Wed, 4 Oct 2023 11:44:27 -0400 Subject: Challenge 237 solutions by Packy Anderson Solutions in: * Perl * Raku * Python * Java One blog post. --- challenge-237/packy-anderson/java/Ch2.java | 121 +++++++++++++++++++++++++++++ 1 file changed, 121 insertions(+) create mode 100644 challenge-237/packy-anderson/java/Ch2.java (limited to 'challenge-237/packy-anderson/java/Ch2.java') diff --git a/challenge-237/packy-anderson/java/Ch2.java b/challenge-237/packy-anderson/java/Ch2.java new file mode 100644 index 0000000000..4768d8d7ec --- /dev/null +++ b/challenge-237/packy-anderson/java/Ch2.java @@ -0,0 +1,121 @@ +import java.util.ArrayList; +import java.util.Arrays; +import java.util.Collections; +import java.util.HashMap; +import java.util.List; +import java.util.stream.Collectors; + +public class Ch2 { + public static String joined(int[] ints) { + // we're using it more than once, make it a method + return Arrays.stream(ints) + .mapToObj(String::valueOf) + .collect(Collectors.joining(", ")); + } + + public static int greatness(int[] nums, int[] perm) { + // determine the "greatness" of a permutation + // relative to the original array; accepts two + // arrays to do the comparison + int greatness_num = 0; + for (int i = 0; i < nums.length; i++) { + if (nums[i] < perm[i]) { + greatness_num++; + } + } + return greatness_num; + } + + public static int[] greatestPermutation(int[] nums) { + // first, count up how many of each num we have + HashMap num_count = + new HashMap(); + for (int i = 0; i < nums.length; i++) { + num_count.put( + nums[i], + num_count.getOrDefault(nums[i], 0) + 1 + ); + } + + // make a list of the available numbers + // to put in a permutation + List available = + new ArrayList<>(num_count.keySet()); + Collections.sort(available); + + // now, build a permutation that maximizes "greatness" + List perm = new ArrayList<>(); + for (Integer num : nums) { + // default to the smallest available number + int num_to_add = available.get(0); + for (int i = 0; i < available.size(); i++) { + int this_num = available.get(i); + if (num < this_num) { + num_to_add = this_num; + break; + } + } + perm.add(num_to_add); + + // decrement the count of that number available + num_count.put( + num_to_add, + num_count.get(num_to_add) - 1 + ); + + // if there are no more of that number, remove it + // from available list + if ( num_count.get(num_to_add) == 0 ) { + // filter array to not include $num + int size = available.size(); + for (int i = 1; i < size; i++) { + int this_num = available.get(i); + if (num_to_add == this_num) { + available.remove(i); + break; + } + } + } + } + + // because we built the permutations in a List, + // convert the list to an int array for return + int[] perm_return = new int[perm.size()]; + for (int i = 0; i < perm.size(); i++) { + perm_return[i] = perm.get(i); + } + return perm_return; + } + + public static void solution(int[] nums) { + System.out.println(String.format( + "Input: @nums = (%s)", joined(nums) + )); + int[] greatest = greatestPermutation(nums); + int greatness_num = greatness(nums, greatest); + System.out.println(String.format( + "Output: %d", greatness_num + )); + System.out.println(String.format( + "\nOne possible permutation: (%s)", joined(greatest) + )); + System.out.println(String.format( + "which returns %d greatness as below:", greatness_num + )); + for (int i = 0; i < nums.length; i++) { + if (nums[i] < greatest[i]) { + System.out.println(String.format( + "nums[%d] < perm[%d]", i, i + )); + } + } + } + + public static void main(String[] args) { + System.out.println("Example 1:"); + solution(new int[] {1, 3, 5, 2, 1, 3, 1}); + + System.out.println("\nExample 2:"); + solution(new int[] {1, 2, 3, 4}); + } +} -- cgit