/* Challenge 115 TASK #2 - Largest Multiple Submitted by: Mohammad S Anwar You are given a list of positive integers (0-9), single digit. Write a script to find the largest multiple of 2 that can be formed from the list. Examples Input: @N = (1, 0, 2, 6) Output: 6210 Input: @N = (1, 4, 2, 8) Output: 8412 Input: @N = (4, 1, 7, 6) Output: 7614 */ #include #include void* check_mem(void* p) { if (!p) { fputs("out of memory", stderr); exit(EXIT_FAILURE); } return p; } int reverse_cmp(const void* a, const void* b) { return -(*(int*)a - *(int*)b); } int largest_even(int nums_size, int* nums) { // smallest even number is last digit int last_digit = 10; for (int i = 0; i < nums_size; i++) if ((nums[i] % 2) == 0 && nums[i] < last_digit) last_digit = nums[i]; if (last_digit == 10) return 0; // remove last_digit from list for (int i = 0; i < nums_size; i++) { if (nums[i] == last_digit) { nums[i] = nums[nums_size - 1]; nums_size--; break; } } // sort remaining digits in descending order qsort(nums, nums_size, sizeof(int), reverse_cmp); int result = 0; for (int i = 0; i < nums_size; i++) result = result * 10 + nums[i]; result = result * 10 + last_digit; return result; } int main(int argc, char* argv[]) { if (argc < 2) return EXIT_FAILURE; int nums_size = argc - 1; int* nums = (int*)check_mem(malloc(nums_size * sizeof(int))); for (int i = 0; i < nums_size; i++) nums[i] = atoi(argv[1 + i]); printf("%d\n", largest_even(nums_size, nums)); free(nums); }