/*
Challenge 120

TASK #2 - Clock Angle
Submitted by: Mohammad S Anwar
You are given time $T in the format hh:mm.

Write a script to find the smaller angle formed by the hands of an analog
clock at a given time.

HINT: A analog clock is divided up into 12 sectors. One sector represents 30
degree (360/12 = 30).

Example
Input: $T = '03:10'
Output: 35 degree

The distance between the 2 and the 3 on the clock is 30 degree.
For the 10 minutes i.e. 1/6 of an hour that have passed.
The hour hand has also moved 1/6 of the distance between the 3 and the 4,
which adds 5 degree (1/6 of 30).
The total measure of the angle is 35 degree.

Input: $T = '04:00'
Output: 120 degree
*/

import std.stdio;
import std.conv;
import std.array : split;
import std.math : abs;

bool parse_time(string hhmm, int* hh, int* mm) {
    string[] a = hhmm.split(":");
    if (a.length != 2) return false;
    *hh = to!int(a[0]);
    *mm = to!int(a[1]);
    return true;
}

int clock_angle(int hh, int mm) {
    int mm_angle = mm*360/60;
    int hh_angle = (hh % 12)*360/12 + mm_angle/12;
    int angle = abs(hh_angle - mm_angle);
    if (angle > 180) { angle = 360 - angle; }
    return angle;
}

void main(string[] args) {
    if (args.length != 2) return;
    int hh, mm;
    if (!parse_time(args[1], &hh, &mm)) return;
    int angle = clock_angle(hh, mm);
    writeln(angle);
}