━━━━━━━━━━━━━━━ CHALLENGE 126 Andinus ━━━━━━━━━━━━━━━ 2021-08-19 Table of Contents ───────────────── Task 1 - Count Numbers Task 2 - Minesweeper Game Task 1 - Count Numbers ══════════════════════ You are given a positive integer `$N'. Write a script to print count of numbers from 1 to `$N' that don’t contain digit 1. Example: ┌──── │ Input: $N = 15 │ Output: 8 │ │ There are 8 numbers between 1 and 15 that don't contain digit 1. │ 2, 3, 4, 5, 6, 7, 8, 9. │ │ Input: $N = 25 │ Output: 13 │ │ There are 13 numbers between 1 and 25 that don't contain digit 1. │ 2, 3, 4, 5, 6, 7, 8, 9, 20, 22, 23, 24, 25. └──── Raku ──── • Program: Loop over `1..$N' and grep for numbers that don't have `1'. `hyper' hints the compiler that this can be run in parallel. ┌──── │ print .join: ', ' with (1..$N).hyper.grep(*.comb.grep(1).elems == 0); │ put '.'; └──── C ─ • Program: `argv' holds the input & `argc' holds the number of inputs. The input should be a single integer so `argc' should be equal to 2. After checking for that, we check if valid integer was passed. After checks, we loop over all numbers from 1 to `num' (passed value) and check if they contain digit `1'. The check is performed by converting `num' to a string and matching for '1' in the string. If we find it then we set the flag to false and don't print the number, otherwise we print it. ┌──── │ if (argc != 2) { │ puts("Usage: ./ch-1 "); │ exit(0); │ } │ │ const char *errstr; │ int num = strtonum(argv[1], 1, INT_MAX, &errstr); │ if (errstr != NULL) │ errx(1, "number is %s: %s", errstr, argv[1]); │ │ for (int idx = 1; idx <= num; idx++) { │ bool take = true; │ │ int str_size = 1 + snprintf(NULL, 0, "%d", idx); │ char *num_str = calloc(str_size, sizeof(char)); │ snprintf(num_str, str_size, "%d", idx); │ │ for (int x = 0; num_str[x] != '\0'; x++) │ if (num_str[x] == '1') take = false; │ free(num_str); │ │ if (take == true) printf("%d ", idx); │ } │ printf("\n"); └──── Task 2 - Minesweeper Game ═════════════════════════ You are given a rectangle with points marked with either x or *. Please consider the x as a land mine. Write a script to print a rectangle with numbers and x as in the Minesweeper game. A number in a square of the minesweeper game indicates the number of mines within the neighbouring squares (usually 8), also implies that there are no bombs on that square. Example: ┌──── │ Input: │ x * * * x * x x x x │ * * * * * * * * * x │ * * * * x * x * x * │ * * * x x * * * * * │ x * * * x * * * * x │ │ Output: │ x 1 0 1 x 2 x x x x │ 1 1 0 2 2 4 3 5 5 x │ 0 0 1 3 x 3 x 2 x 2 │ 1 1 1 x x 4 1 2 2 2 │ x 1 1 3 x 2 0 0 1 x └──── Raku ──── • Program: `@rect' holds the challenge grids and `@grids' holds the solution. We loop over every cell and if it's not a land mine then we loop over it's neighbors and find the number of neighboring land mines and set it's value. The neighbors is returned by `neighbors' subroutine which is adapted from `Octans::Neighbors' (projects/octans) which was adapted from my 2020 AoC day 11's solution. ┌──── │ my @rect = $input.IO.lines.map(*.words.cache); │ die "Not rectangle" unless [==] @rect.map(*.elems); │ │ my @grid; │ for 0 .. @rect.end -> $r { │ for 0 .. @rect[$r].end -> $c { │ given @rect[$r][$c] { │ when "x" { @grid[$r][$c] = @rect[$r][$c] } │ when "*" { │ @grid[$r][$c] = 0; │ for neighbors(@rect, $r, $c).List -> $pos { │ @grid[$r][$c]++ if @rect[$pos[0]][$pos[1]] eq "x"; │ } │ } │ } │ } │ } │ .put for @grid; └────