#! /usr/bin/lua

-- by Michael Anderson at
-- https://stackoverflow.com/questions/8722620/comparing-two-index-tables-by-index-value-in-lua
function recursive_compare(t1,t2)
  -- Use usual comparison first.
  if t1==t2 then return true end
  -- We only support non-default behavior for tables
  if (type(t1)~="table") then return false end
  -- They better have the same metatables
  local mt1 = getmetatable(t1)
  local mt2 = getmetatable(t2)
  if( not recursive_compare(mt1,mt2) ) then return false end

  -- Check each key-value pair
  -- We have to do this both ways in case we miss some.
  -- TODO: Could probably be smarter and not check those we've 
  -- already checked though!
  for k1,v1 in pairs(t1) do
    local v2 = t2[k1]
    if( not recursive_compare(v1,v2) ) then return false end
  end
  for k2,v2 in pairs(t2) do
    local v1 = t1[k2]
    if( not recursive_compare(v1,v2) ) then return false end
  end

  return true  
end

function n2tab(n)
   local a = {}
   string.gsub(tostring(n), ".", function(c) table.insert(a,c) end)
   table.sort(a)
   return a
end

function permutable()
   local n = 0
   while true do
      n = n + 1
      local base = n2tab(n)
      local q = true
      for k = 2,6 do
         local tt = n2tab(n * k)
         if not recursive_compare(base, tt) then
            q = false
            break
         end
      end
      if q then
         return n
      end
   end
end

if permutable() == 142857 then
   io.write("Pass")
else
   io.write("FAIL")
end
print("")