#! /usr/bin/lua

-- by Michael Anderson at
-- https://stackoverflow.com/questions/8722620/comparing-two-index-tables-by-index-value-in-lua
function recursive_compare(t1,t2)
  -- Use usual comparison first.
  if t1==t2 then return true end
  -- We only support non-default behavior for tables
  if (type(t1)~="table") then return false end
  -- They better have the same metatables
  local mt1 = getmetatable(t1)
  local mt2 = getmetatable(t2)
  if( not recursive_compare(mt1,mt2) ) then return false end

  -- Check each key-value pair
  -- We have to do this both ways in case we miss some.
  -- TODO: Could probably be smarter and not check those we've 
  -- already checked though!
  for k1,v1 in pairs(t1) do
    local v2 = t2[k1]
    if( not recursive_compare(v1,v2) ) then return false end
  end
  for k2,v2 in pairs(t2) do
    local v1 = t1[k2]
    if( not recursive_compare(v1,v2) ) then return false end
 end

  return true  
end

function sequencenumber(list)
   local nn = 0
   local out = {}
   for i, ins in ipairs(list) do
      table.insert(out, string.format("%02d%4s", nn, string.sub(ins, 3, 6)))
      nn = nn + 1
   end
   return out
end

if recursive_compare(sequencenumber({"ab1234", "cd5678", "ef1342"}),
                     {"001234", "015678", "021342"}) then
   io.write("Pass")
else
   io.write("FAIL")
end
io.write(" ")

if recursive_compare(sequencenumber({"pq1122", "rs3334"}),
                     {"001122", "013334"}) then
   io.write("Pass")
else
   io.write("FAIL")
end
print("")