{
 "cells": [
  {
   "cell_type": "markdown",
   "id": "0898b4b4",
   "metadata": {},
   "source": [
    "# Task 1: MAC Address\n",
    "\n",
    "You are given MAC address in the form i.e. hhhh.hhhh.hhhh.\n",
    "\n",
    "Write a script to convert the address in the form hh:hh:hh:hh:hh:hh.\n",
    "\n",
    "Example 1\n",
    "```\n",
    "Input:  1ac2.34f0.b1c2\n",
    "Output: 1a:c2:34:f0:b1:c2\n",
    "```\n",
    "Example 2\n",
    "```\n",
    "Input:  abc1.20f1.345a\n",
    "Output: ab:c1:20:f1:34:5a\n",
    "```"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "id": "6cafcb43",
   "metadata": {},
   "outputs": [],
   "source": [
    "import re"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "id": "86a7b3f6",
   "metadata": {},
   "outputs": [],
   "source": [
    "ex1 = \"1ac2.34f0.b1c2\"\n",
    "ex2 = \"abc1.20f1.345a\""
   ]
  },
  {
   "cell_type": "markdown",
   "id": "8ac1ec54",
   "metadata": {},
   "source": [
    "Work out a regular expressions to break up the mac address and capture groups.  It's pretty long, I'm sure there is a more consise way to express it."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "id": "a8094e85",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "'1a:c2:34:f0:b1:c2'"
      ]
     },
     "execution_count": 3,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "result = re.search(r'([\\w]{2})([\\w]{2})\\.([\\w]{2})([\\w]{2})\\.([\\w]{2})([\\w]{2})', ex1)\n",
    "\":\".join(result.groups())"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "ff372d91",
   "metadata": {},
   "source": [
    "Put this into function for reuse and test the examples above:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "id": "cfa8172d",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1a:c2:34:f0:b1:c2\n"
     ]
    }
   ],
   "source": [
    "def convert_mac(mac):\n",
    "    result = re.search(r'([\\w]{2})([\\w]{2})\\.([\\w]{2})([\\w]{2})\\.([\\w]{2})([\\w]{2})', mac)\n",
    "    return \":\".join(result.groups())\n",
    "\n",
    "print(convert_mac(ex1))"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "id": "dcbe6934",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "ab:c1:20:f1:34:5a\n"
     ]
    }
   ],
   "source": [
    "print(convert_mac(ex2))"
   ]
  }
 ],
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   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
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  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
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   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
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