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   "cell_type": "markdown",
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   "metadata": {},
   "source": [
    "# Task 1: Zip List\n",
    "\n",
    "You are given two list @a and @b of same size.\n",
    "\n",
    "Create a subroutine sub zip(@a, @b) that merge the two list as shown in the example below.\n",
    "Example\n",
    "```\n",
    "Input:  @a = qw/1 2 3/; @b = qw/a b c/;\n",
    "Output: zip(@a, @b) should return qw/1 a 2 b 3 c/;\n",
    "        zip(@b, @a) should return qw/a 1 b 2 c 3/;\n",
    "```"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "4ca2c151",
   "metadata": {},
   "source": [
    "There is a python builtin function called zip which doesn't do exactly what we are looking for.  It produces a list of tuples paired by position and truncated to the shortest list."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "id": "04fd3afe",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "<zip at 0x7f88e83c8440>"
      ]
     },
     "execution_count": 1,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "a = [1, 2, 3]\n",
    "b = ['a', 'b', 'c']\n",
    "\n",
    "zip(a, b)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "id": "d62a76f9",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[(1, 'a'), (2, 'b'), (3, 'c')]"
      ]
     },
     "execution_count": 2,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "list(zip(a, b))"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "94604825",
   "metadata": {},
   "source": [
    "Defining my own zip function but using the builtin zip function within it I can convert a list of tuples into a list:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "id": "1e8b38dd",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[1, 'a', 2, 'b', 3, 'c']"
      ]
     },
     "execution_count": 3,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "import itertools\n",
    "\n",
    "def zip(a, b):\n",
    "    zipped = __builtin__.zip(a, b)\n",
    "    return list(itertools.chain(*zipped))\n",
    "\n",
    "zip(a, b)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "def9f2bf",
   "metadata": {},
   "source": [
    "Test with the arguments reversed:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "id": "fa9a665b",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "['a', 1, 'b', 2, 'c', 3]"
      ]
     },
     "execution_count": 4,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "zip(b, a)"
   ]
  }
 ],
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