#! /usr/bin/lua -- by Michael Anderson at -- https://stackoverflow.com/questions/8722620/comparing-two-index-tables-by-index-value-in-lua -- modified by Roger function recursive_compare(t1,t2) -- Use usual comparison first. if t1==t2 then return true end -- We only support non-default behavior for tables if (type(t1)~="table") then return false end -- They better have the same metatables local mt1 = getmetatable(t1) local mt2 = getmetatable(t2) if( not recursive_compare(mt1,mt2) ) then return false end -- Build list of all keys local kk = {} for k1, _ in pairs(t1) do kk[k1] = true end for k2, _ in pairs(t2) do kk[k2] = true end -- Check each key that exists in at least one table for _, k in ipairs(kk) do if (not recursive_compare(t1[k], t2[k])) then return false end end return true end -- Roger's lualib function keys(t) local a = {} for k, v in pairs(t) do table.insert(a, k) end return a end function rankscore(a) local av = {} for i, s in ipairs(a) do if av[s] == nil then av[s] = 1 else av[s] = av[s] + 1 end end local kk = keys(av) table.sort(kk, function (aa, bb) return bb < aa end) local rank = 1 local tab = {} for i, k in ipairs(kk) do local siz = av[k] local r = "" if rank <= 3 then r = string.sub("GSB", rank, rank) else r = tostring(rank) end if siz > 1 then r = r .. "=" end tab[k] = r rank = rank + siz end local out = {} for i, s in ipairs(a) do table.insert(out, tab[s]) end return out end if recursive_compare(rankscore({1, 2, 4, 3, 5}), {"5", "4", "S", "B", "G"}) then io.write("Pass") else io.write("FAIL") end io.write(" ") if recursive_compare(rankscore({8, 5, 6, 7, 4}), {"G", "4", "B", "S", "5"}) then io.write("Pass") else io.write("FAIL") end io.write(" ") if recursive_compare(rankscore({3, 5, 4, 2}), {"B", "G", "S", "4"}) then io.write("Pass") else io.write("FAIL") end io.write(" ") if recursive_compare(rankscore({2, 5, 2, 1, 7, 5, 1}), {"4=", "S=", "4=", "6=", "G", "S=", "6="}) then io.write("Pass") else io.write("FAIL") end print("")