/*
Task 1: Smaller than Current
Submitted by: Mohammad Sajid Anwar

You are given a array of integers, @ints.
Write a script to find out how many integers are smaller than current i.e. foreach ints[i], count ints[j] < ints[i] where i != j.

Example 1
Input: @ints = (5, 2, 1, 6)
Output: (2, 1, 0, 3)

For $ints[0] = 5, there are two integers (2,1) smaller than 5.
For $ints[1] = 2, there is one integer (1) smaller than 2.
For $ints[2] = 1, there is none integer smaller than 1.
For $ints[3] = 6, there are three integers (5,2,1) smaller than 6.

Example 2
Input: @ints = (1, 2, 0, 3)
Output: (1, 2, 0, 3)

Example 3
Input: @ints = (0, 1)
Output: (0, 1)

Example 4
Input: @ints = (9, 4, 9, 2)
Output: (2, 1, 2, 0)
*/

package main

import (
    "fmt"
)

func smaller_than_current(arrInts []int) {
    arrSmaller := make([]int, 0)
    for i := 0; i < len(arrInts); i++ {
        smaller := 0
        for j := 0; j < len(arrInts); j++ {
            if arrInts[j] < arrInts[i] {
                smaller++
            }
        }
        arrSmaller = append(arrSmaller, smaller)
    }
    fmt.Printf("%v -> %v\n", arrInts, arrSmaller)
}

func main() {
    arrInts := []int{5, 2, 1, 6}
    smaller_than_current(arrInts)

    arrInts = []int{1, 2, 0, 3}
    smaller_than_current(arrInts)

    arrInts = []int{0, 1}
    smaller_than_current(arrInts)

    arrInts = []int{9, 4, 9, 2}
    smaller_than_current(arrInts)
}