#!/usr/bin/python3
# https://theweeklychallenge.org/blog/perl-weekly-challenge-258/#TASK1
#
# Task 1: Count Even Digits Number
# ================================
#
# You are given a array of positive integers, @ints.
#
# Write a script to find out how many integers have even number of digits.
#
## Example 1
##
## Input: @ints = (10, 1, 111, 24, 1000)
## Output: 3
##
## There are 3 integers having even digits i.e. 10, 24 and 1000.
#
## Example 2
##
## Input: @ints = (111, 1, 11111)
## Output: 0
#
## Example 3
##
## Input: @ints = (2, 8, 1024, 256)
## Output: 1
#
############################################################
##
## discussion
##
############################################################
#
# Just calculate the length of each integer an check if it is
# even, then in the end tell how many those were.

def count_even_digits_number(ints: list):
    print("Input: (", ", ".join(str(x) for x in ints), ")", sep="")
    result = 0
    for number in ints:
        if len(str(number)) % 2 == 0:
            result += 1
    print(f"Output: {result}")

count_even_digits_number([10, 1, 111, 24, 1000]);
count_even_digits_number([111, 1, 11111]);
count_even_digits_number([2, 8, 1024, 256]);