#! /usr/bin/lua -- by Michael Anderson at -- https://stackoverflow.com/questions/8722620/comparing-two-index-tables-by-index-value-in-lua -- modified by Roger function recursive_compare(t1,t2) -- Use usual comparison first. if t1==t2 then return true end -- We only support non-default behavior for tables if (type(t1)~="table") then return false end -- They better have the same metatables local mt1 = getmetatable(t1) local mt2 = getmetatable(t2) if( not recursive_compare(mt1,mt2) ) then return false end -- Build list of all keys local kk = {} for k1, _ in pairs(t1) do kk[k1] = true end for k2, _ in pairs(t2) do kk[k2] = true end -- Check each key that exists in at least one table for _, k in ipairs(kk) do if (not recursive_compare(t1[k], t2[k])) then return false end end return true end function permute(a) local out = {} local n = #a local c = {} for i = 1,n do table.insert(c, 1) end table.insert(out, deepcopy(a)) local i=1 while true do if i > n then break end if c[i] < i then if i % 2 == 1 then a[1],a[i] = a[i],a[1] else a[c[i]],a[i] = a[i],a[c[i]] end table.insert(out, deepcopy(a)) c[i] = c[i]+1 i = 1 else c[i] = 1 i = i+1 end end return out end function deepcopy(src) local dst = {} for k, v in pairs(src) do if type(v) == "table" then v = deepcopy(v) end dst[k] = v end return dst end function listcmp(a, b) local ix = 1 while true do if ix > #a and ix > #b then return false end if ix <= #a and ix > #b then return true end if ix > #a and ix <= #b then return false end if a[ix] ~= b[ix] then return a[ix] < b[ix] end ix = ix + 1 end end function nextpermutation(a) local b = deepcopy(a) table.sort(b) local flag = false local out = {} local pp = permute(b) table.sort(pp, listcmp) for _, px in ipairs(pp) do if #out == 0 then out = px end if flag then out = px end if recursive_compare(px, a) then flag = true end end return out end if recursive_compare(nextpermutation({1, 2, 3}), {1, 3, 2}) then io.write("Pass") else io.write("FAIL") end io.write(" ") if recursive_compare(nextpermutation({2, 1, 3}), {2, 3, 1}) then io.write("Pass") else io.write("FAIL") end io.write(" ") if recursive_compare(nextpermutation({3, 1, 2}), {3, 2, 1}) then io.write("Pass") else io.write("FAIL") end print("")