### https://theweeklychallenge.org/blog/perl-weekly-challenge-321/
"""

Task 1: Distinct Average

Submitted by: [44]Mohammad Sajid Anwar
     __________________________________________________________________

   You are given an array of numbers with even length.

   Write a script to return the count of distinct average. The average is
   calculate by removing the minimum and the maximum, then average of the
   two.

Example 1

Input: @nums = (1, 2, 4, 3, 5, 6)
Output: 1

Step 1: Min = 1, Max = 6, Avg = 3.5
Step 2: Min = 2, Max = 5, Avg = 3.5
Step 3: Min = 3, Max = 4, Avg = 3.5

The count of distinct average is 1.

Example 2

Input: @nums = (0, 2, 4, 8, 3, 5)
Output: 2

Step 1: Min = 0, Max = 8, Avg = 4
Step 2: Min = 2, Max = 5, Avg = 3.5
Step 3: Min = 3, Max = 4, Avg = 3.5

The count of distinct average is 2.

Example 3

Input: @nums = (7, 3, 1, 0, 5, 9)
Output: 2

Step 1: Min = 0, Max = 9, Avg = 4.5
Step 2: Min = 1, Max = 7, Avg = 4
Step 3: Min = 3, Max = 5, Avg = 4

The count of distinct average is 2.

Task 2: Backspace Compare
"""
### solution by pokgopun@gmail.com

def da(ints: tuple[int]) -> int:
    l = len(ints)
    lst = sorted(ints)
    avgs = []
    for i in range(int(l/2)):
        avgs.append((lst[i]+lst[l-1-i])/2)
    return len(set(avgs))

import unittest

class TestDa(unittest.TestCase):
    def test(self):
        for inpt, otpt in {
                (1, 2, 4, 3, 5, 6): 1,
                (0, 2, 4, 8, 3, 5): 2,
                (7, 3, 1, 0, 5, 9): 2,
                }.items():
            self.assertEqual(da(inpt), otpt)

unittest.main()