#! /usr/bin/lua

-- by Michael Anderson at
-- https://stackoverflow.com/questions/8722620/comparing-two-index-tables-by-index-value-in-lua
-- modified by Roger
function recursive_compare(t1,t2)
  -- Use usual comparison first.
  if t1==t2 then return true end
  -- We only support non-default behavior for tables
  if (type(t1)~="table") then return false end
  -- They better have the same metatables
  local mt1 = getmetatable(t1)
  local mt2 = getmetatable(t2)
  if( not recursive_compare(mt1,mt2) ) then return false end
  -- Build list of all keys
  local kk = {}
  for k1, _ in pairs(t1) do
     kk[k1] = true
  end
  for k2, _ in pairs(t2) do
     kk[k2] = true
  end
  -- Check each key that exists in at least one table
  for _, k in ipairs(kk) do
     if (not recursive_compare(t1[k], t2[k])) then
        return false
     end
  end
  return true
end

function keys(t)
   local a = {}
   for k, v in pairs(t) do
      table.insert(a, k)
   end
   return a
end

function rankarray(a)
   local k = {}
   for _, c in ipairs(a) do
      k[c] = true
   end
   local b = keys(k)
   table.sort(b)
   local c = {}
   for i, n in ipairs(b) do
      c[n] = i
   end
   local out = {}
   for _, v in ipairs(a) do
      table.insert(out, c[v])
   end
   return out
end

if recursive_compare(rankarray({55, 22, 44, 33}), {4, 1, 3, 2}) then
  io.write("Pass")
else
  io.write("FAIL")
end
io.write(" ")

if recursive_compare(rankarray({10, 10, 10}), {1, 1, 1}) then
  io.write("Pass")
else
  io.write("FAIL")
end
io.write(" ")

if recursive_compare(rankarray({5, 1, 1, 4, 3}), {4, 1, 1, 3, 2}) then
  io.write("Pass")
else
  io.write("FAIL")
end
print("")