Vamsi's Perl and Python Solutions for week 193

4 files changed, 144 insertions, 0 deletions

diff --git a/challenge-193/vamsi-meenavilli/perl/ch-1.pl b/challenge-193/vamsi-meenavilli/perl/ch-1.pl
new file mode 100644
index 0000000000..ccd179a814
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+++ b/challenge-193/vamsi-meenavilli/perl/ch-1.pl
@@ -0,0 +1,37 @@
+#!/usr/bin/perl
+use strict;
+use warnings FATAL => 'all';
+
+use Test2::V0;
+
+=head1 AUTHORS
+
+Vamsi Meenavilli
+
+=head1 DESCRIPTION
+
+	https://theweeklychallenge.org/blog/perl-weekly-challenge-193
+
+    Task 1: Binary String
+    Submitted by: Mohammad S Anwar
+    You are given an integer, $n > 0.
+
+    Write a script to find all possible binary numbers of size $n.
+
+=cut
+
+is(binaryString(2), ['00', '01', '10', '11'], 'Example 1');
+is(binaryString(3), ['000', '001', '010', '011', '100', '101', '110', '111'], 'Example 2');
+
+sub binaryString {
+    my ($binary_number_size) = @_;
+
+    my @binary_strings = ();
+    for (my $i = 0; $i < 2**$binary_number_size; $i++) {
+        push(@binary_strings, sprintf("%0${binary_number_size}b", $i))
+    }
+
+    return(\@binary_strings);
+}
+
+done_testing();
\ No newline at end of file
diff --git a/challenge-193/vamsi-meenavilli/perl/ch-2.pl b/challenge-193/vamsi-meenavilli/perl/ch-2.pl
new file mode 100644
index 0000000000..e2f7cf7694
--- /dev/null
+++ b/challenge-193/vamsi-meenavilli/perl/ch-2.pl
@@ -0,0 +1,48 @@
+#!/usr/bin/perl
+use strict;
+use warnings FATAL => 'all';
+
+use Test2::V0;
+
+=head1 AUTHORS
+
+Vamsi Meenavilli
+
+=head1 DESCRIPTION
+
+    https://theweeklychallenge.org/blog/perl-weekly-challenge-193
+
+    Task 2: Odd String
+    Submitted by: Mohammad S Anwar
+    You are given a list of strings of same length, @s.
+
+    Write a script to find the odd string in the given list. Use positional value of alphabet starting with 0, i.e. a = 0, b = 1, ... z = 25.
+
+    Find the difference array for each string as shown in the example. Then pick the odd one out.
+
+=cut
+
+is(oddString("adc", "wzy", "abc"), "abc", 'Example 1');
+is(oddString("aaa", "bob", "ccc", "ddd"), "bob", 'Example 2');
+
+sub oddString {
+    my (@strings_list) = @_;
+
+    my %strings_list_diff_hash = ();
+
+    foreach my $string (@strings_list) {
+        my $diff = join(',', map {
+            ord(substr($string, $_ + 1, 1)) - ord(substr($string, $_, 1))
+        } (0..length($string) - 2));
+
+        push(@{$strings_list_diff_hash{$diff}}, $string)
+    }
+
+    foreach my $diff (keys(%strings_list_diff_hash)) {
+        if (scalar(@{$strings_list_diff_hash{$diff}}) == 1) {
+            return($strings_list_diff_hash{$diff}[0]);
+        }
+    }
+}
+
+done_testing()
diff --git a/challenge-193/vamsi-meenavilli/python/ch-1.py b/challenge-193/vamsi-meenavilli/python/ch-1.py
new file mode 100644
index 0000000000..00a3fd9ed6
--- /dev/null
+++ b/challenge-193/vamsi-meenavilli/python/ch-1.py
@@ -0,0 +1,20 @@
+"""
+ Week 192:
+
+	https://theweeklychallenge.org/blog/perl-weekly-challenge-193
+
+    Task 1: Binary String
+    Submitted by: Mohammad S Anwar
+    You are given an integer, $n > 0.
+
+    Write a script to find all possible binary numbers of size $n.
+"""
+
+def binaryString(binary_string_size):
+    return [bin(i)[2:].zfill(binary_string_size) for i in range(pow(2, binary_string_size))]
+
+def binaryStringTest():
+    assert binaryString(2) == ['00', '01', '10', '11'], 'Example 1 Failed.'
+    assert binaryString(3) == ['000', '001', '010', '011', '100', '101', '110', '111'], 'Example 2 Failed.'
+
+binaryStringTest()
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diff --git a/challenge-193/vamsi-meenavilli/python/ch-2.py b/challenge-193/vamsi-meenavilli/python/ch-2.py
new file mode 100644
index 0000000000..8ca2fc9a57
--- /dev/null
+++ b/challenge-193/vamsi-meenavilli/python/ch-2.py
@@ -0,0 +1,39 @@
+"""
+ Week 192:
+
+    https://theweeklychallenge.org/blog/perl-weekly-challenge-193
+
+    Task 2: Odd String
+    Submitted by: Mohammad S Anwar
+    You are given a list of strings of same length, @s.
+
+    Write a script to find the odd string in the given list. Use positional value of alphabet starting with 0, i.e. a = 0, b = 1, ... z = 25.
+
+    Find the difference array for each string as shown in the example. Then pick the odd one out.
+"""
+
+def oddString(strings_list):
+    strings_list_diff_map = {}
+
+    for i in strings_list:
+        diff = ','.join([str(ord(i[j + 1]) - ord(i[j])) for j in range(len(i) - 1)])
+
+        if diff in strings_list_diff_map:
+            strings_list_diff_map[diff].append(i)
+        else:
+            strings_list_diff_map[diff] = [i]
+
+    for i in strings_list_diff_map:
+        if len(strings_list_diff_map[i]) == 1:
+            return strings_list_diff_map[i][0]
+
+def oddStringTest():
+    assert oddString(["adc", "wzy", "abc"]) == "abc", 'Example 1 Failed'
+    assert oddString(["aaa", "bob", "ccc", "ddd"]) == "bob", 'Example 2 Failed'
+
+oddStringTest()
+
+
+
+
+