Add C solution

1 files changed, 33 insertions, 0 deletions

diff --git a/challenge-026/paulo-custodio/c/ch-1.c b/challenge-026/paulo-custodio/c/ch-1.c
new file mode 100644
index 0000000000..26e85e147a
--- /dev/null
+++ b/challenge-026/paulo-custodio/c/ch-1.c
@@ -0,0 +1,33 @@
+/*
+Challenge 026
+
+Task #1
+Create a script that accepts two strings, let us call it, "stones" and
+"jewels". It should print the count of "alphabet" from the string "stones"
+found in the string "jewels". For example, if your stones is "chancellor" and
+"jewels" is "chocolate", then the script should print "8". To keep it simple,
+only A-Z,a-z characters are acceptable. Also make the comparison case
+sensitive.
+*/
+
+#include <stdio.h>
+#include <stdlib.h>
+#include <string.h>
+
+int count_alphabet(const char* stones, const char* jewels) {
+    int count = 0;
+    for (const char* p = stones; *p; p++) {
+        if (strchr(jewels, *p))
+            count++;
+    }
+    return count;
+}
+
+int main(int argc, char* argv[]) {
+    if (argc != 3) {
+        fputs("Usage: ch-1 stones jewels\n", stderr);
+        return EXIT_FAILURE;
+    }
+
+    printf("%d\n", count_alphabet(argv[1], argv[2]));
+}