LK: Perl and Python solutions for Challenge 307

4 files changed, 233 insertions, 0 deletions

diff --git a/challenge-307/lubos-kolouch/perl/ch-1.pl b/challenge-307/lubos-kolouch/perl/ch-1.pl
new file mode 100644
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+++ b/challenge-307/lubos-kolouch/perl/ch-1.pl
@@ -0,0 +1,58 @@
+#!/usr/bin/perl
+use strict;
+use warnings;
+use Test::More tests => 4;
+
+=head1 NAME
+
+check_order.pl - Rearrange an array in increasing order and return differing indices
+
+=head1 SYNOPSIS
+
+  perl check_order.pl
+
+=head1 DESCRIPTION
+
+This script defines a function that accepts an array reference of integers.
+It sorts the array in increasing order and returns the indices where the sorted array
+differs from the original.
+
+=head2 check_order
+
+  my $diff_indices_ref = check_order($ints_ref);
+
+This function takes an array reference of integers and returns an array reference
+containing the indices at which the sorted array differs from the original.
+
+=cut
+
+sub check_order {
+    my ($ints_ref) = @_;
+    my @original   = @$ints_ref;
+    my @sorted     = sort { $a <=> $b } @original;
+    my @diff_indices;
+    for my $i ( 0 .. $#original ) {
+        if ( $original[$i] != $sorted[$i] ) {
+            push @diff_indices, $i;
+        }
+    }
+    return \@diff_indices;
+}
+
+# Unit tests
+
+my $result;
+
+$result = check_order( [ 5, 2, 4, 3, 1 ] );
+is_deeply( $result, [ 0, 2, 3, 4 ], 'Test example 1' );
+
+$result = check_order( [ 1, 2, 1, 1, 3 ] );
+is_deeply( $result, [ 1, 3 ], 'Test example 2' );
+
+$result = check_order( [ 3, 1, 3, 2, 3 ] );
+is_deeply( $result, [ 0, 1, 3 ], 'Test example 3' );
+
+$result = check_order( [ 1, 2, 3, 4, 5 ] );
+is_deeply( $result, [], 'Test already sorted' );
+
+done_testing();
diff --git a/challenge-307/lubos-kolouch/perl/ch-2.pl b/challenge-307/lubos-kolouch/perl/ch-2.pl
new file mode 100644
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--- /dev/null
+++ b/challenge-307/lubos-kolouch/perl/ch-2.pl
@@ -0,0 +1,62 @@
+#!/usr/bin/perl
+use strict;
+use warnings;
+use Test::More tests => 4;
+
+=head1 NAME
+
+find_anagrams.pl - Drop consecutive anagrams and return the count of the final list
+
+=head1 DESCRIPTION
+
+This script applies the rule: whenever two consecutive words are anagrams,
+drop the first word and keep the second. This is repeated until no such pair exists.
+According to this rule, any contiguous block of anagrams will collapse to a single word.
+
+=head2 sorted_word
+
+  my $sorted = sorted_word($word);
+
+Returns the characters of the word sorted in increasing order.
+
+=head2 find_anagrams
+
+  my $final_count = find_anagrams(\@words);
+
+Processes the list iteratively and returns the count of words remaining.
+=cut
+
+sub sorted_word {
+    my ($word) = @_;
+    return join '', sort split //, $word;
+}
+
+sub find_anagrams {
+    my ($words_ref) = @_;
+    my @list        = @$words_ref;
+    my $changed     = 1;
+    while ($changed) {
+        $changed = 0;
+        for ( my $i = 0 ; $i < @list - 1 ; $i++ ) {
+            if ( sorted_word( $list[$i] ) eq sorted_word( $list[ $i + 1 ] ) ) {
+
+                # drop the first word of the pair
+                splice( @list, $i, 1 );
+                $changed = 1;
+                last;    # restart scanning from beginning
+            }
+        }
+    }
+    return scalar @list;
+}
+
+# Unit tests for the iterative (fully applied) rule:
+is( find_anagrams( [ "acca", "dog", "god", "perl", "repl" ] ),
+    3, 'Test example 1' );
+is( find_anagrams( [ "abba", "baba", "aabb", "ab", "ab" ] ),
+    2, 'Test example 2' );
+is( find_anagrams( [ "abc", "cab", "bca" ] ), 1, 'Test simple chain' );
+is( find_anagrams( [ "word", "drow", "word", "word" ] ),
+    1, 'Test repeating words' );
+
+done_testing();
diff --git a/challenge-307/lubos-kolouch/python/ch-1.py b/challenge-307/lubos-kolouch/python/ch-1.py
new file mode 100644
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--- /dev/null
+++ b/challenge-307/lubos-kolouch/python/ch-1.py
@@ -0,0 +1,56 @@
+#!/usr/bin/env python3
+"""
+Module to check the order of an integer list.
+"""
+
+import unittest
+
+IntList = list[int]
+
+
+def check_order(ints: IntList) -> list[int]:
+    """
+    Rearranges the list in increasing order and returns the indices where the sorted list
+    differs from the original list.
+
+    Args:
+        ints (List[int]): The list of integers.
+
+    Returns:
+        List[int]: A list of indices where the sorted list differs from the original.
+    """
+    sorted_ints = sorted(ints)
+    differences: list[int] = []
+    for i, (orig, sorted_val) in enumerate(zip(ints, sorted_ints)):
+        if orig != sorted_val:
+            differences.append(i)
+    return differences
+
+
+if __name__ == "__main__":
+
+    class TestCheckOrder(unittest.TestCase):
+
+        def test_example1(self):
+            input_list = [5, 2, 4, 3, 1]
+            expected = [0, 2, 3, 4]
+            self.assertEqual(check_order(input_list), expected)
+
+        def test_example2(self):
+            input_list = [1, 2, 1, 1, 3]
+            expected = [1, 3]
+            self.assertEqual(check_order(input_list), expected)
+
+        def test_example3(self):
+            input_list = [3, 1, 3, 2, 3]
+            expected = [0, 1, 3]
+            self.assertEqual(check_order(input_list), expected)
+
+        def test_already_sorted(self):
+            input_list = [1, 2, 3, 4, 5]
+            expected = []
+            self.assertEqual(check_order(input_list), expected)
+
+
+if __name__ == "__main__":
+    unittest.main()
diff --git a/challenge-307/lubos-kolouch/python/ch-2.py b/challenge-307/lubos-kolouch/python/ch-2.py
new file mode 100644
index 0000000000..a7124d14d6
--- /dev/null
+++ b/challenge-307/lubos-kolouch/python/ch-2.py
@@ -0,0 +1,57 @@
+#!/usr/bin/env python3
+"""
+Module to process a list of words by dropping consecutive anagrams.
+Applies the rule iteratively:
+if two consecutive words are anagrams, drop the first word.
+A contiguous block of anagrams will collapse to a single word.
+"""
+
+import unittest
+
+
+def sorted_word(word: str) -> str:
+    return ''.join(sorted(word))
+
+
+def find_anagrams(words: list[str]) -> int:
+    """
+    Iteratively remove the first word from any consecutive pair of anagrams.
+
+    Args:
+        words (List[str]): The list of words.
+
+    Returns:
+        int: The count of words remaining after processing.
+    """
+    lst = words[:]  # work on a copy
+    changed = True
+    while changed:
+        changed = False
+        for i in range(len(lst) - 1):
+            if sorted_word(lst[i]) == sorted_word(lst[i + 1]):
+                lst.pop(i)
+                changed = True
+                break  # restart from beginning
+    return len(lst)
+
+
+if __name__ == "__main__":
+
+    class TestFindAnagrams(unittest.TestCase):
+
+        def test_example1(self):
+            self.assertEqual(
+                find_anagrams(["acca", "dog", "god", "perl", "repl"]), 3)
+
+        def test_example2(self):
+            self.assertEqual(
+                find_anagrams(["abba", "baba", "aabb", "ab", "ab"]), 2)
+
+        def test_simple_chain(self):
+            self.assertEqual(find_anagrams(["abc", "cab", "bca"]), 1)
+
+        def test_repeating_words(self):
+            self.assertEqual(find_anagrams(["word", "drow", "word", "word"]),
+                             1)
+
+    unittest.main()