pwc273 solution in python

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diff --git a/challenge-273/pokgopun/python/ch-1.py b/challenge-273/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-273/
+"""
+
+Task 1: Percentage of Character
+
+Submitted by: [52]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a string, $str and a character $char.
+
+   Write a script to return the percentage, nearest whole, of given
+   character in the given string.
+
+Example 1
+
+Input: $str = "perl", $char = "e"
+Output: 25
+
+Example 2
+
+Input: $str = "java", $char = "a"
+Output: 50
+
+Example 3
+
+Input: $str = "python", $char = "m"
+Output: 0
+
+Example 4
+
+Input: $str = "ada", $char = "a"
+Output: 67
+
+Example 5
+
+Input: $str = "ballerina", $char = "l"
+Output: 22
+
+Example 6
+
+Input: $str = "analitik", $char = "k"
+Output: 13
+
+Task 2: B After A
+"""
+### solution by pokgopun@gmail.com
+
+def poc(string, char):
+    res = 1000 * string.count(char) / len(string)
+    return res // 10 if res % 10 < 5 else 1 + res // 10
+
+import unittest
+
+class TestPoc(unittest.TestCase):
+    def test(self):
+        for (string, char), otpt in {
+                ("perl", "e"): 25,
+                ("java", "a"): 50,
+                ("python", "m"): 0,
+                ("ada", "a"): 67,
+                ("ballerina", "l"): 22,
+                ("analitik", "k"): 13,
+                }.items():
+            self.assertEqual(poc(string, char), otpt)
+
+unittest.main()
diff --git a/challenge-273/pokgopun/python/ch-2.py b/challenge-273/pokgopun/python/ch-2.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-273/
+"""
+
+Task 2: B After A
+
+Submitted by: [53]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a string, $str.
+
+   Write a script to return true if there is at least one b, and no a
+   appears after the first b.
+
+Example 1
+
+Input: $str = "aabb"
+Output: true
+
+Example 2
+
+Input: $str = "abab"
+Output: false
+
+Example 3
+
+Input: $str = "aaa"
+Output: false
+
+Example 4
+
+Input: $str = "bbb"
+Output: true
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 16th June 2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def bAfterA(string):
+    i = string.find("b")
+    if i == -1:
+        return False
+    return string[i+1:].find("a") == -1
+
+import unittest
+
+class TestBAfterA(unittest.TestCase):
+    def test(self):
+        for string, otpt in {
+                "aabb": True,
+                "abab": False,
+                "aaa": False,
+                "bbb": True,
+                }.items():
+            self.assertEqual(bAfterA(string),otpt)
+
+unittest.main()