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| author | Mohammad Sajid Anwar <Mohammad.Anwar@yahoo.com> | 2024-09-11 20:37:50 +0100 |
|---|---|---|
| committer | GitHub <noreply@github.com> | 2024-09-11 20:37:50 +0100 |
| commit | 2b1abf52154959807ae50fbd9266a2de475c519a (patch) | |
| tree | 3412387fc1eb6522deb0726ba6b0fb375bc94356 | |
| parent | cbf28e6e924b7cd24d1614a5ad28d801f0e85dea (diff) | |
| parent | 96f4b7c0a062a00bf2aba6098d8b703991510458 (diff) | |
| download | perlweeklychallenge-club-2b1abf52154959807ae50fbd9266a2de475c519a.tar.gz perlweeklychallenge-club-2b1abf52154959807ae50fbd9266a2de475c519a.tar.bz2 perlweeklychallenge-club-2b1abf52154959807ae50fbd9266a2de475c519a.zip | |
Merge pull request #10823 from pauloscustodio/master
Add Python solutions
| -rw-r--r-- | challenge-056/paulo-custodio/python/ch-1.py | 29 | ||||
| -rw-r--r-- | challenge-056/paulo-custodio/python/ch-2.py | 81 |
2 files changed, 110 insertions, 0 deletions
diff --git a/challenge-056/paulo-custodio/python/ch-1.py b/challenge-056/paulo-custodio/python/ch-1.py new file mode 100644 index 0000000000..38a1c8f8b8 --- /dev/null +++ b/challenge-056/paulo-custodio/python/ch-1.py @@ -0,0 +1,29 @@ +#!/usr/bin/env python3 + +# Challenge 056 +# +# TASK #1 +# Diff-K +# You are given an array @N of positive integers (sorted) and another non +# negative integer k. +# +# Write a script to find if there exists 2 indices i and j such that +# A[i] - A[j] = k and i != j. +# +# It should print the pairs of indices, if any such pairs exist. +# +# Example: +# +# @N = (2, 7, 9) +# $k = 2 +# Output : 2,1 + +import sys + +k = int(sys.argv[1]) +n = [int(x) for x in sys.argv[2:]] + +for i in range(0, len(n)-1): + for j in range(i+1, len(n)): + if abs(n[i]-n[j]) == k: + print(str(i)+","+str(j)) diff --git a/challenge-056/paulo-custodio/python/ch-2.py b/challenge-056/paulo-custodio/python/ch-2.py new file mode 100644 index 0000000000..5ce29d26b9 --- /dev/null +++ b/challenge-056/paulo-custodio/python/ch-2.py @@ -0,0 +1,81 @@ +#!/usr/bin/env python3 + +# Challenge 056 +# +# TASK #2 +# Path Sum +# You are given a binary tree and a sum, write a script to find if the tree has +# a path such that adding up all the values along the path equals the given sum. +# Only complete paths (from root to leaf node) may be considered for a sum. +# +# Example +# Given the below binary tree and sum = 22, +# +# 5 +# / \ +# 4 8 +# / / \ +# 11 13 9 +# / \ \ +# 7 2 1 +# For the given binary tree, the partial path sum 5 ? 8 ? 9 = 22 is not valid. +# +# The script should return the path 5 ? 4 ? 11 ? 2 whose sum is 22. + +import fileinput +import re +import sys + +class Node: + def __init__(self, value): + self.value = value + self.left = None + self.right = None + + def __repr__(self): + return "Node(value: {}, left: {}, right: {})" \ + .format(self.value, self.left, self.right) + +def read_input(): + lines = [] + for line in fileinput.input(): + lines.append(line) + return lines + +def parse_subtree(lines, row, col): + def ch(row, col): + if row < 0 or row >= len(lines) or \ + col < 0 or col >= len(lines[row]): + return ' ' + else: + return lines[row][col] + + tree = Node(int(lines[row][col])) + if ch(row + 1, col - 1) == '/': + tree.left = parse_subtree(lines, row + 2, col - 2) + if ch(row + 1, col + 1) == '\\': + tree.right = parse_subtree(lines, row + 2, col + 2) + + return tree + +def parse_tree(lines): + found = re.search(r'^[ ]+\d', lines[0]) + col = found.span()[1] - 1 + return parse_subtree(lines, 0, col) + + +def path_sum(path, sum1, tree): + path1 = path+[tree.value] + if not tree.left and not tree.right: + if sum(path1) == sum1: + print(" ".join([str(x) for x in path1])) + else: + if tree.left: + path_sum(path1, sum1, tree.left) + if tree.right: + path_sum(path1, sum1, tree.right) + +sum1 = int(sys.argv[1]) +sys.argv.pop() +tree = parse_tree(read_input()) +path_sum([], sum1, tree) |
