new file: challenge-282/mattneleigh/perl/ch-1.pl

new file:   challenge-282/mattneleigh/perl/ch-2.pl

2 files changed, 135 insertions, 0 deletions

diff --git a/challenge-282/mattneleigh/perl/ch-1.pl b/challenge-282/mattneleigh/perl/ch-1.pl
new file mode 100755
index 0000000000..baa4a90011
--- /dev/null
+++ b/challenge-282/mattneleigh/perl/ch-1.pl
@@ -0,0 +1,75 @@
+#!/usr/bin/perl
+
+use strict;
+use warnings;
+use English;
+
+################################################################################
+# Begin main execution
+################################################################################
+
+my @ints = (
+    12344456,
+    1233334,
+    10020003
+);
+
+print("\n");
+foreach my $int (@ints){
+    printf(
+        "Input: \$int = %d\nOutput: \"%s\"\n\n",
+        $int,
+        find_good_digit($int)
+    );
+}
+
+exit(0);
+################################################################################
+# End main execution; subroutines follow
+################################################################################
+
+
+
+################################################################################
+# Given a positive integer with three or more digits, find the first Good
+# Integer within- that is, a block of exactly three repeating digits
+# Takes one argument:
+# * The positive integer to examine (e.g. 12344456 )
+# Returns on success
+# * The first Good Integer found within the number (e.g. 444 )
+# Returns on failure
+# * -1 if there was no Good Integer within the number
+################################################################################
+sub find_good_digit{
+
+    my $prev_digit = "";
+    my $count = 1;
+
+    # Loop over each digit
+    foreach my $digit (split(//, shift())){
+        if($digit eq $prev_digit){
+            # This digit matches the previous digit-
+            # increment the count
+            $count++;
+        } else{
+            # This digit does not match the previous
+            # digit- if the count for the previus digit
+            # was 3, return a block of three of that
+            # digit
+            return($prev_digit x 3)
+                if($count == 3);
+
+            # Store the new digit and reset the
+            # count
+            $prev_digit = $digit;
+            $count = 1;
+        }
+    }
+
+    # If we got here, there was no Good Integer
+    return(-1);
+
+}
+
+
+
diff --git a/challenge-282/mattneleigh/perl/ch-2.pl b/challenge-282/mattneleigh/perl/ch-2.pl
new file mode 100755
index 0000000000..8869d0e39e
--- /dev/null
+++ b/challenge-282/mattneleigh/perl/ch-2.pl
@@ -0,0 +1,60 @@
+#!/usr/bin/perl
+
+use strict;
+use warnings;
+use English;
+
+################################################################################
+# Begin main execution
+################################################################################
+
+my @strings = (
+    "pPeERrLl",
+    "rRr",
+    "GoO"
+);
+
+print("\n");
+foreach my $string (@strings){
+    printf(
+        "Input: \$str = '%s'\nOuput: %d\n\n",
+        $string,
+        count_key_changes($string)
+    );
+}
+
+exit(0);
+################################################################################
+# End main execution; subroutines follow
+################################################################################
+
+
+
+################################################################################
+# Given an alphabetic string, determine the number of times the user who typed
+# it had to change keys on their keyboard- not counting shift or caps lock- to
+# input it
+# Takes one argument:
+# * The string to examine (e.g. "pPeERrLl")
+# Returns:
+# * The number of key changes requires to input the string (e.g. 3 )
+################################################################################
+sub count_key_changes{
+
+    my @chars = split(//, lc(shift()));
+    my $changes = 0;
+
+    # Loop over each lower-cased character
+    foreach my $i (1 .. $#chars){
+        # Increment the change count if this character
+        # differs from the previous one
+        $changes++
+            unless($chars[$i - 1] eq $chars[$i]);
+    }
+
+    return($changes);
+
+}
+
+
+