Merge pull request #10220 from pokgopun/pwc272

Pwc272

4 files changed, 286 insertions, 0 deletions

diff --git a/challenge-272/pokgopun/go/ch-1.go b/challenge-272/pokgopun/go/ch-1.go
new file mode 100644
index 0000000000..10a9c05be0
--- /dev/null
+++ b/challenge-272/pokgopun/go/ch-1.go
@@ -0,0 +1,59 @@
+//# https://theweeklychallenge.org/blog/perl-weekly-challenge-272/
+/*#
+
+Task 1: Defang IP Address
+
+Submitted by: [45]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a valid IPv4 address.
+
+   Write a script to return the defanged version of the given IP address.
+
+     A defanged IP address replaces every period “.” with “[.]".
+
+Example 1
+
+Input: $ip = "1.1.1.1"
+Output: "1[.]1[.]1[.]1"
+
+Example 2
+
+Input: $ip = "255.101.1.0"
+Output: "255[.]101[.]1[.]0"
+
+Task 2: String Score
+#*/
+//# solution by pokgopun@gmail.com
+
+package main
+
+import (
+	"io"
+	"os"
+
+	"github.com/google/go-cmp/cmp"
+)
+
+func dfip(str string) string {
+	var rs []rune
+	for _, v := range str {
+		if v == '.' {
+			rs = append(rs, '[', '.', ']')
+		} else {
+			rs = append(rs, v)
+		}
+	}
+	return string(rs)
+}
+
+func main() {
+	for _, data := range []struct {
+		input, output string
+	}{
+		{"1.1.1.1", "1[.]1[.]1[.]1"},
+		{"255.101.1.0", "255[.]101[.]1[.]0"},
+	} {
+		io.WriteString(os.Stdout, cmp.Diff(dfip(data.input), data.output)) // blank if ok, otherwise show the difference
+	}
+}
diff --git a/challenge-272/pokgopun/go/ch-2.go b/challenge-272/pokgopun/go/ch-2.go
new file mode 100644
index 0000000000..a66313e197
--- /dev/null
+++ b/challenge-272/pokgopun/go/ch-2.go
@@ -0,0 +1,98 @@
+//# https://theweeklychallenge.org/blog/perl-weekly-challenge-272/
+/*#
+
+Task 2: String Score
+
+Submitted by: [46]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a string, $str.
+
+   Write a script to return the score of the given string.
+
+     The score of a string is defined as the sum of the absolute
+     difference between the ASCII values of adjacent characters.
+
+Example 1
+
+Input: $str = "hello"
+Output: 13
+
+ASCII values of characters:
+h = 104
+e = 101
+l = 108
+l = 108
+o = 111
+
+Score => |104 - 101| + |101 - 108| + |108 - 108| + |108 - 111|
+      => 3 + 7 + 0 + 3
+      => 13
+
+Example 2
+
+Input: "perl"
+Output: 30
+
+ASCII values of characters:
+p = 112
+e = 101
+r = 114
+l = 108
+
+Score => |112 - 101| + |101 - 114| + |114 - 108|
+      => 11 + 13 + 6
+      => 30
+
+Example 3
+
+Input: "raku"
+Output: 37
+
+ASCII values of characters:
+r = 114
+a = 97
+k = 107
+u = 117
+
+Score => |114 - 97| + |97 - 107| + |107 - 117|
+      => 17 + 10 + 10
+      => 37
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 9th June 2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+#*/
+//# solution by pokgopun@gmail.com
+
+package main
+
+import (
+	"io"
+	"os"
+
+	"github.com/google/go-cmp/cmp"
+)
+
+func ss(str string) int {
+	var c int
+	for i := range len(str) - 1 {
+		c += int(max(str[i], str[i+1]) - min(str[i], str[i+1]))
+	}
+	return c
+}
+
+func main() {
+	for _, data := range []struct {
+		input  string
+		output int
+	}{
+		{"hello", 13},
+		{"perl", 30},
+		{"raku", 37},
+	} {
+		io.WriteString(os.Stdout, cmp.Diff(ss(data.input), data.output)) // blank if ok, otherwise show the difference
+	}
+}
diff --git a/challenge-272/pokgopun/python/ch-1.py b/challenge-272/pokgopun/python/ch-1.py
new file mode 100644
index 0000000000..2b328144e9
--- /dev/null
+++ b/challenge-272/pokgopun/python/ch-1.py
@@ -0,0 +1,42 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-272/
+"""
+
+Task 1: Defang IP Address
+
+Submitted by: [45]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a valid IPv4 address.
+
+   Write a script to return the defanged version of the given IP address.
+
+     A defanged IP address replaces every period “.” with “[.]".
+
+Example 1
+
+Input: $ip = "1.1.1.1"
+Output: "1[.]1[.]1[.]1"
+
+Example 2
+
+Input: $ip = "255.101.1.0"
+Output: "255[.]101[.]1[.]0"
+
+Task 2: String Score
+"""
+### solution by pokgopun@gmail.com
+
+def dfip(string: str):
+    return string.replace(".","[.]")
+
+import unittest
+
+class TestDfip (unittest.TestCase):
+    def test(self):
+        for inpt, otpt in {
+                "1.1.1.1": "1[.]1[.]1[.]1",
+                "255.101.1.0": "255[.]101[.]1[.]0",
+                }.items():
+            self.assertEqual(dfip(inpt),otpt)
+
+unittest.main()
diff --git a/challenge-272/pokgopun/python/ch-2.py b/challenge-272/pokgopun/python/ch-2.py
new file mode 100644
index 0000000000..065e0b1609
--- /dev/null
+++ b/challenge-272/pokgopun/python/ch-2.py
@@ -0,0 +1,87 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-272/
+"""
+
+Task 2: String Score
+
+Submitted by: [46]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a string, $str.
+
+   Write a script to return the score of the given string.
+
+     The score of a string is defined as the sum of the absolute
+     difference between the ASCII values of adjacent characters.
+
+Example 1
+
+Input: $str = "hello"
+Output: 13
+
+ASCII values of characters:
+h = 104
+e = 101
+l = 108
+l = 108
+o = 111
+
+Score => |104 - 101| + |101 - 108| + |108 - 108| + |108 - 111|
+      => 3 + 7 + 0 + 3
+      => 13
+
+Example 2
+
+Input: "perl"
+Output: 30
+
+ASCII values of characters:
+p = 112
+e = 101
+r = 114
+l = 108
+
+Score => |112 - 101| + |101 - 114| + |114 - 108|
+      => 11 + 13 + 6
+      => 30
+
+Example 3
+
+Input: "raku"
+Output: 37
+
+ASCII values of characters:
+r = 114
+a = 97
+k = 107
+u = 117
+
+Score => |114 - 97| + |97 - 107| + |107 - 117|
+      => 17 + 10 + 10
+      => 37
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 9th June 2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def ss(string: str):
+    return sum(
+            abs(ord(p[0])-ord(p[1])) for p in
+            (string[i:i+2] for i in range(len(string)-1))
+            )
+
+import unittest
+
+class TestSs(unittest.TestCase):
+    def test(self):
+        for inpt, otpt in {
+                "hello": 13,
+                "perl": 30,
+                "raku": 37,
+                }.items():
+            self.assertEqual(ss(inpt),otpt)
+
+unittest.main()