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authorMohammad S Anwar <Mohammad.Anwar@yahoo.com>2020-06-01 17:26:02 +0100
committerGitHub <noreply@github.com>2020-06-01 17:26:02 +0100
commit3cd13a75427c426df87fc4e7395ad59d3c9e0e0d (patch)
tree2c88f09090da9612f53d3ee2e827d42bf89c286b
parentd67822d626374fde369ee19ba98553661df3c3b3 (diff)
parent2b822785f85321c29d4d9e6a55b797ab9140afd0 (diff)
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Merge pull request #1782 from fluca1978/pwc63
Pwc63
-rw-r--r--challenge-063/luca-ferrari/blog-1.txt1
-rw-r--r--challenge-063/luca-ferrari/blog-2.txt1
-rw-r--r--challenge-063/luca-ferrari/raku/ch-1.p646
-rw-r--r--challenge-063/luca-ferrari/raku/ch-2.p645
4 files changed, 93 insertions, 0 deletions
diff --git a/challenge-063/luca-ferrari/blog-1.txt b/challenge-063/luca-ferrari/blog-1.txt
new file mode 100644
index 0000000000..fea9d92892
--- /dev/null
+++ b/challenge-063/luca-ferrari/blog-1.txt
@@ -0,0 +1 @@
+https://fluca1978.github.io/2020/06/01/PerlWeeklyChallenge63.html#task1
diff --git a/challenge-063/luca-ferrari/blog-2.txt b/challenge-063/luca-ferrari/blog-2.txt
new file mode 100644
index 0000000000..99bc798d26
--- /dev/null
+++ b/challenge-063/luca-ferrari/blog-2.txt
@@ -0,0 +1 @@
+https://fluca1978.github.io/2020/06/01/PerlWeeklyChallenge63.html#task2
diff --git a/challenge-063/luca-ferrari/raku/ch-1.p6 b/challenge-063/luca-ferrari/raku/ch-1.p6
new file mode 100644
index 0000000000..e96cf8c939
--- /dev/null
+++ b/challenge-063/luca-ferrari/raku/ch-1.p6
@@ -0,0 +1,46 @@
+#!env raku
+
+
+# Define sub last_word($string, $regexp) that returns the last word matching $regexp found in the given string, or undef if the string does not contain a word matching $regexp.
+#
+# For this challenge, a “word” is defined as any character sequence consisting of non-whitespace characters (\S) only. That means punctuation and other symbols are part of the word.
+#
+# The $regexp is a regular expression. Take care that the regexp can only match individual words! See the Examples for one way this can break if you are not careful.
+# Examples
+#
+# last_word(' hello world', qr/[ea]l/); # 'hello'
+# last_word("Don't match too much, Chet!", qr/ch.t/i); # 'Chet!'
+# last_word("spaces in regexp won't match", qr/in re/); # undef
+# last_word( join(' ', 1..1e6), qr/^(3.*?){3}/); # '399933'
+#
+
+
+
+sub last_word( $string, $regexp ){
+ my $last-word = Nil;
+ for $string.split( " " ) {
+ $last-word = $_ if $_ ~~ $regexp;
+ }
+
+ return $last-word;
+}
+
+
+sub last_word_shorter( $string, $regexp ){
+ for $string.split( " " ).reverse {
+ return $_ if $_ ~~ $regexp;
+ }
+}
+
+
+sub MAIN(){
+ say last_word(' hello world', rx/<[ea]>l/); # 'hello'
+ say last_word("Don't match too much, Chet!", rx:i/ch.t/); # 'Chet!'
+ say last_word("spaces in regexp won't match", rx:s/ in re / ); # undef
+ say last_word( join(' ', 1..1e6), rx/ ^ (3.*?) ** 3 / ); # '399933'
+
+ say last_word_shorter(' hello world', rx/<[ea]>l/); # 'hello'
+ say last_word_shorter("Don't match too much, Chet!", rx:i/ch.t/); # 'Chet!'
+ say last_word_shorter("spaces in regexp won't match", rx:s/ in re / ); # undef
+ say last_word_shorter( join(' ', 1..1e6), rx/ ^ (3.*?) ** 3 / ); # '399933'
+}
diff --git a/challenge-063/luca-ferrari/raku/ch-2.p6 b/challenge-063/luca-ferrari/raku/ch-2.p6
new file mode 100644
index 0000000000..e80cf66f58
--- /dev/null
+++ b/challenge-063/luca-ferrari/raku/ch-2.p6
@@ -0,0 +1,45 @@
+#!env raku
+
+
+# Given a word made up of an arbitrary number of x and y characters, that word can be rotated as follows: For the ith rotation (starting at i = 1), i % length(word) characters are moved from the front of the string to the end. Thus, for the string xyxx, the initial (i = 1) % 4 = 1 character (x) is moved to the end, forming yxxx. On the second rotation, (i = 2) % 4 = 2 characters (yx) are moved to the end, forming xxyx, and so on. See below for a complete example.
+#
+# Your task is to write a function that takes a string of xs and ys and returns the maximum non-zero number of rotations required to obtain the original string. You may show the individual rotations if you wish, but that is not required.
+# Example
+#
+# Input: $word = 'xyxx';
+#
+# Rotation 1: you get yxxx by moving x to the end.
+# Rotation 2: you get xxyx by moving yx to the end.
+# Rotation 3: you get xxxy by moving xxy to the end.
+# Rotation 4: you get xxxy by moving nothing as 4 % length(xyxx) == 0.
+# Rotation 5: you get xxyx by moving x to the end.
+# Rotation 6: you get yxxx by moving xx to the end.
+# Rotation 7: you get xyxx by moving yxxx to the end which is same as the given word.
+#
+# Output: 7
+
+sub rotate( $string where { $string.split( '', :skip-empty ).chars > 1 }, $verbose = False ){
+ my $step = 1;
+ my @chars = $string.split( '', :skip-empty );
+
+
+ while ( $step == 1 || $string ne @chars.join( '' ) ) {
+ say "Rotation $step the string is: {@chars}" if $verbose;
+
+ # move the first character to the end
+ @chars.push: @chars.shift for 0 ..^ ( $step % $string.chars );
+
+
+ say "After step $step the string is: { @chars }" if $verbose;
+
+ $step++;
+ }
+
+ return $step - 1;
+}
+
+
+sub MAIN(){
+ say rotate( 'xyxx' );
+ say rotate( 'xyxx', True );
+}