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| author | Jörg Sommrey <28217714+jo-37@users.noreply.github.com> | 2022-04-04 18:45:50 +0200 |
|---|---|---|
| committer | Jörg Sommrey <28217714+jo-37@users.noreply.github.com> | 2022-04-08 15:34:13 +0200 |
| commit | 41e99f11d4d91ffa5f40e5f0f171cc406b1fb055 (patch) | |
| tree | a572586b3504ef7acfd5dc969dab72190538a38f | |
| parent | 7a219f03ce9b654277078bfb906cbc0741c9e3ba (diff) | |
| download | perlweeklychallenge-club-41e99f11d4d91ffa5f40e5f0f171cc406b1fb055.tar.gz perlweeklychallenge-club-41e99f11d4d91ffa5f40e5f0f171cc406b1fb055.tar.bz2 perlweeklychallenge-club-41e99f11d4d91ffa5f40e5f0f171cc406b1fb055.zip | |
Solution to task 2
| -rwxr-xr-x | challenge-159/jo-37/perl/ch-2.pl | 95 |
1 files changed, 95 insertions, 0 deletions
diff --git a/challenge-159/jo-37/perl/ch-2.pl b/challenge-159/jo-37/perl/ch-2.pl new file mode 100755 index 0000000000..e5e1313189 --- /dev/null +++ b/challenge-159/jo-37/perl/ch-2.pl @@ -0,0 +1,95 @@ +#!/usr/bin/perl -s + +use v5.16; +use Test2::V0; +use Math::Utils qw(fsum gcd ceil); +use Math::Trig 'pi2'; + +# For testing only: +use Math::Prime::Util; + +use experimental 'signatures'; + +our ($tests, $examples); + +run_tests() if $tests || $examples; # does not return + +die <<EOS unless @ARGV; +usage: $0 [-examples] [-tests] [N] + +-examples + run the examples from the challenge + +-tests + run some tests + +N + Print µ(N). + +EOS + + +### Input and Output + +# Round to integer. +printf "%.0f\n", moebius(shift); + + +### Implementation + +# The Möbius function is provided by the awesome Math::Prime::Util. +# Using it for cross-checking another implementation taken from +# Wikipedia: +# +# µ(n) equals the sum of all primitive n-th roots of unity. +# Though this is really funny, it's rather inefficient. +# +# Some considerations: +# - There are no primitive roots with a zero imaginary part for n > 2. +# - If a number z is a n-th root, then the conjugate number z* is a root, +# too. And it is a different number for nonzero imaginary parts. +# - From +# z + z* = 2 Re z +# it follows, that positive and negative imaginary parts cancel out +# and the real parts double. +# Thus it is sufficient to take twice the sum of the real parts of +# primitive roots with a positive imaginary part. No complex arithmetic +# is required. +# +# Remember: +# exp(2πi k/n) are the n-th roots of unity and +# exp(iϑ) = cos(ϑ) + i sin(ϑ) + +sub moebius ($n) { + # Treat the special cases + return 1 if $n == 1; + return -1 if $n == 2; + + 2 * fsum map cos(pi2 * $_ / $n), + grep gcd($_, $n) == 1, 1 .. ceil($n / 2) - 1; +} + + +### Examples and tests + +sub run_tests { + SKIP: { + skip "examples" unless $examples; + + is moebius(5), float(-1), 'example 1'; + is moebius(10), float(1), 'example 2'; + is moebius(20), float(0), 'example 3'; + } + + SKIP: { + skip "tests" unless $tests; + + for my $n (1 .. 128) { + is moebius($n), + float(Math::Prime::Util::moebius($n)), "n=$n"; + } + } + + done_testing; + exit; +} |
