pwc251 solution in python

2 files changed, 166 insertions, 0 deletions

diff --git a/challenge-251/pokgopun/python/ch-1.py b/challenge-251/pokgopun/python/ch-1.py
new file mode 100644
index 0000000000..41fd8c1c0c
--- /dev/null
+++ b/challenge-251/pokgopun/python/ch-1.py
@@ -0,0 +1,88 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-251/
+"""
+
+Task 1: Concatenation Value
+
+Submitted by: [52]Mohammad S Anwar
+     __________________________________________________________________
+
+   You are given an array of integers, @ints.
+
+   Write a script to find the concatenation value of the given array.
+
+   The concatenation of two numbers is the number formed by concatenating
+   their numerals.
+For example, the concatenation of 10, 21 is 1021.
+The concatenation value of @ints is initially equal to 0.
+Perform this operation until @ints becomes empty:
+
+If there exists more than one number in @ints, pick the first element
+and last element in @ints respectively and add the value of their
+concatenation to the concatenation value of @ints, then delete the
+first and last element from @ints.
+
+If one element exists, add its value to the concatenation value of
+@ints, then delete it.
+
+Example 1
+
+Input: @ints = (6, 12, 25, 1)
+Output: 1286
+
+1st operation: concatenation of 6 and 1 is 61
+2nd operation: concaternation of 12 and 25 is 1225
+
+Concatenation Value => 61 + 1225 => 1286
+
+Example 2
+
+Input: @ints = (10, 7, 31, 5, 2, 2)
+Output: 489
+
+1st operation: concatenation of 10 and 2 is 102
+2nd operation: concatenation of 7 and 2 is 72
+3rd operation: concatenation of 31 and 5 is 315
+
+Concatenation Value => 102 + 72 + 315 => 489
+
+Example 3
+
+Input: @ints = (1, 2, 10)
+Output: 112
+
+1st operation: concatenation of 1 and 10 is 110
+2nd operation: only element left is 2
+
+Concatenation Value => 110 + 2 => 112
+
+Task 2: Lucky Numbers
+"""
+### solution by pokgopun@gmail.com
+
+def concatenation(tup: tuple):
+    #print(tup)
+    l = len(tup)
+    sum = 0
+    for i in range(l//2):
+        #print(tup[i],tup[l-1-i],"=>",int(str(tup[i])+str(tup[l-1-i])))
+        sum += int(str(tup[i])+str(tup[l-1-i]))
+    if l % 2:
+        #print("addition",tup[l//2])
+        sum += tup[l//2]
+    return sum
+
+import unittest
+
+class TestConcatenation(unittest.TestCase):
+    def test(self):
+        for inpt,otpt in {
+                (6, 12, 25, 1): 1286,
+                (10, 7, 31, 5, 2, 2): 489,
+                (1, 2, 10): 112,
+                }.items():
+            self.assertEqual(concatenation(inpt),otpt)
+
+unittest.main()
+
+
+
diff --git a/challenge-251/pokgopun/python/ch-2.py b/challenge-251/pokgopun/python/ch-2.py
new file mode 100644
index 0000000000..c987d9f4df
--- /dev/null
+++ b/challenge-251/pokgopun/python/ch-2.py
@@ -0,0 +1,78 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-251/
+"""
+
+Task 2: Lucky Numbers
+
+Submitted by: [53]Mohammad S Anwar
+     __________________________________________________________________
+
+   You are given a m x n matrix of distinct numbers.
+
+   Write a script to return the lucky number, if there is one, or -1 if
+   not.
+A lucky number is an element of the matrix such that it is
+the minimum element in its row and maximum in its column.
+
+Example 1
+
+Input: $matrix = [ [ 3,  7,  8],
+                   [ 9, 11, 13],
+                   [15, 16, 17] ];
+Output: 15
+
+15 is the only lucky number since it is the minimum in its row
+and the maximum in its column.
+
+Example 2
+
+Input: $matrix = [ [ 1, 10,  4,  2],
+                   [ 9,  3,  8,  7],
+                   [15, 16, 17, 12] ];
+Output: 12
+
+Example 3
+
+Input: $matrix = [ [7 ,8],
+                   [1 ,2] ];
+Output: 7
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 14th January
+   2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def luckynumber(tup: list):
+    #print(tup)
+    res = -1
+    for i in range(len(tup)):
+        mn = min(tup[i])
+        #print("mn =",mn)
+        j = tup[i].index(mn)
+        if mn == max(e[j] for e in tup):
+            res = mn
+            break
+    return res
+
+import unittest
+
+class TestLuckynumber(unittest.TestCase):
+    def test(self):
+        for inpt,otpt in {
+                ( ( 3,  7,  8),
+                   ( 9, 11, 13),
+                   (15, 16, 17) ): 15,
+                ( ( 1, 10,  4,  2),
+                   ( 9,  3,  8,  7),
+                   (15, 16, 17, 12) ): 12,
+                ( (7 ,8),
+                   (1 ,2) ): 7,
+                }.items():
+            self.assertEqual(luckynumber(inpt),otpt)
+
+unittest.main()
+
+