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authorSteven <steven1170@zoho.eu>2024-05-27 12:01:17 +0100
committerSteven <steven1170@zoho.eu>2024-05-27 12:01:17 +0100
commit4a3514afd078df234f7acc68eed0b893fc639ccb (patch)
tree695880853ef2bacd18ff1564ed9b3ab534db48b8
parent6316d6f47ce102f090a6ba18c5d5b4ac52bc2a82 (diff)
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add solution week 271 task 1 in python
-rw-r--r--challenge-271/steven-wilson/python/ch-1.py23
1 files changed, 23 insertions, 0 deletions
diff --git a/challenge-271/steven-wilson/python/ch-1.py b/challenge-271/steven-wilson/python/ch-1.py
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+++ b/challenge-271/steven-wilson/python/ch-1.py
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+#!/usr/bin/env python3
+
+from operator import itemgetter
+
+
+def maximum_ones(matrix):
+ ''' Given a m x n binary matrix, return the row number containing maximum
+ ones, in case of more than one rows then return smallest row number.
+ >>> maximum_ones([ [0, 1],[1, 0],])
+ 1
+ >>> maximum_ones([ [0, 0, 0],[1, 0, 1],])
+ 2
+ >>> maximum_ones([ [0, 0],[1, 1],[0, 0],])
+ 2
+ '''
+ row_sum = ((n, sum(row)) for n, row in enumerate(matrix, start=1))
+ return sorted(row_sum, key=itemgetter(1), reverse=True)[0][0]
+
+
+if __name__ == "__main__":
+ import doctest
+
+ doctest.testmod(verbose=True)