pwc275 solution in python

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diff --git a/challenge-275/pokgopun/python/ch-1.py b/challenge-275/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-275/
+"""
+
+Task 1: Broken Keys
+
+Submitted by: [45]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a sentence, $sentence and list of broken keys @keys.
+
+   Write a script to find out how many words can be typed fully.
+
+Example 1
+
+Input: $sentence = "Perl Weekly Challenge", @keys = ('l', 'a')
+Output: 0
+
+Example 2
+
+Input: $sentence = "Perl and Raku", @keys = ('a')
+Output: 1
+
+Only Perl since the other word two words contain 'a' and can't be typed fully.
+
+Example 3
+
+Input: $sentence = "Well done Team PWC", @keys = ('l', 'o')
+Output: 2
+
+Example 4
+
+Input: $sentence = "The joys of polyglottism", @keys = ('T')
+Output: 2
+
+Task 2: Replace Digits
+"""
+### solution by pokgopun@gmail.com
+
+def bk(sentence: str, keys: tuple):
+    keys = set(e.lower() for e in keys)
+    return sum(
+            1 for e in sentence.split() if set(e.lower()).intersection(keys) == set()
+            )
+
+import unittest
+
+class TestBk(unittest.TestCase):
+    def test(self):
+        for (sentence, keys), otpt in {
+                ("Perl Weekly Challenge", ('l', 'a')): 0,
+                ("Perl and Raku", ('a',)): 1,
+                ("Well done Team PWC", ('l', 'o')): 2,
+                ("The joys of polyglottism", ('T',)): 2,
+                }.items():
+            self.assertEqual(bk(sentence,keys),otpt)
+
+unittest.main()
+
+
diff --git a/challenge-275/pokgopun/python/ch-2.py b/challenge-275/pokgopun/python/ch-2.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-275/
+"""
+
+Task 2: Replace Digits
+
+Submitted by: [46]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given an alphanumeric string, $str, where each character is
+   either a letter or a digit.
+
+   Write a script to replace each digit in the given string with the value
+   of the previous letter plus (digit) places.
+
+Example 1
+
+Input: $str = 'a1c1e1'
+Ouput: 'abcdef'
+
+shift('a', 1) => 'b'
+shift('c', 1) => 'd'
+shift('e', 1) => 'f'
+
+Example 2
+
+Input: $str = 'a1b2c3d4'
+Output: 'abbdcfdh'
+
+shift('a', 1) => 'b'
+shift('b', 2) => 'd'
+shift('c', 3) => 'f'
+shift('d', 4) => 'h'
+
+Example 3
+
+Input: $str = 'b2b'
+Output: 'bdb'
+
+Example 4
+
+Input: $str = 'a16z'
+Output: 'abgz'
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 30th June 2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def replaceDigits1(string: str):
+    r = list(string)
+    for i in range(len(r)):
+        if r[i].isalpha():
+            prv = r[i]
+        else:
+            r[i] = chr(ord(prv)+int(r[i]))
+    return "".join(r)
+
+def replaceDigits2(string: str):
+    r = ""
+    for c in string:
+        if c.isalpha():
+            prv = c
+            r += c
+        else:
+            r += chr(ord(prv)+int(c))
+    return r
+
+import unittest
+
+class TestReplaceDigits(unittest.TestCase):
+    def test1(self):
+        for inpt,otpt in {
+                'a1c1e1': 'abcdef',
+                'a1b2c3d4': 'abbdcfdh',
+                'b2b': 'bdb',
+                'a16z': 'abgz',
+                }.items():
+            self.assertEqual(replaceDigits1(inpt),otpt)
+    def test2(self):
+        for inpt,otpt in {
+                'a1c1e1': 'abcdef',
+                'a1b2c3d4': 'abbdcfdh',
+                'b2b': 'bdb',
+                'a16z': 'abgz',
+                }.items():
+            self.assertEqual(replaceDigits2(inpt),otpt)
+
+unittest.main()