Merge pull request #11931 from oWnOIzRi/week318

add solutions week 318 in python

2 files changed, 51 insertions, 0 deletions

diff --git a/challenge-318/steven-wilson/python/ch-1.py b/challenge-318/steven-wilson/python/ch-1.py
new file mode 100644
index 0000000000..078a5146cf
--- /dev/null
+++ b/challenge-318/steven-wilson/python/ch-1.py
@@ -0,0 +1,25 @@
+#!/usr/bin/env python3
+
+from itertools import groupby
+
+
+def group_position(string):
+    """ Given a string of lowercase letters, find the position of all groups in
+    the given string. Three or more consecutive letters form a group. Return "”
+    if none found.
+
+    >>> group_position("abccccd")
+    ('cccc',)
+    >>> group_position("aaabcddddeefff")
+    ('aaa', 'dddd', 'fff')
+    >>> group_position("abcdd")
+    ()
+    """
+    return tuple("".join(g) for g in (list(g) for _, g in
+                 groupby(string, key=None)) if len(g) >= 3)
+
+
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod(verbose=True)
diff --git a/challenge-318/steven-wilson/python/ch-2.py b/challenge-318/steven-wilson/python/ch-2.py
new file mode 100644
index 0000000000..9848edcac5
--- /dev/null
+++ b/challenge-318/steven-wilson/python/ch-2.py
@@ -0,0 +1,26 @@
+#!/usr/bin/env python3
+
+
+def reverse_equals(source, target):
+    """ Given two arrays of integers, each containing the same elements as the
+    other, return true if one array can be made to equal the other by reversing
+    exactly one contiguous subarray.
+
+    >>> reverse_equals([3, 2, 1, 4], [1, 2, 3, 4])
+    True
+    >>> reverse_equals([1, 3, 4], [4, 1, 3])
+    False
+    >>> reverse_equals([2], [2])
+    True
+    """
+    if source == target:
+        return True
+
+    (first, *middle, last) = [n for n, i in enumerate(source) if i != target[n]]
+    return source[first:last+1][::-1] == target[first:last+1]
+
+
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod(verbose=True)