Perl & Raku solutions to Tasks 1 & 2 of the Perl Weekly Challenge #138

4 files changed, 694 insertions, 0 deletions

diff --git a/challenge-138/athanasius/perl/ch-1.pl b/challenge-138/athanasius/perl/ch-1.pl
new file mode 100644
index 0000000000..8fa92eca9a
--- /dev/null
+++ b/challenge-138/athanasius/perl/ch-1.pl
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+#!perl
+
+###############################################################################
+=comment
+
+Perl Weekly Challenge 138
+=========================
+
+TASK #1
+-------
+*Workdays*
+
+Submitted by: Mohammad S Anwar
+
+You are given a year, $year in 4-digits form.
+
+Write a script to calculate the total number of workdays in the given year.
+
+    For the task, we consider, Monday - Friday as workdays.
+
+Example 1
+
+ Input: $year = 2021
+ Output: 261
+
+Example 2
+
+ Input: $year = 2020
+ Output: 262
+
+=cut
+###############################################################################
+
+#--------------------------------------#
+# Copyright © 2021 PerlMonk Athanasius #
+#--------------------------------------#
+
+#==============================================================================
+=comment
+
+Algorithm
+---------
+A common year has 365 days, a leap year 366. 52 weeks is 364 days, and those 52
+weeks are guaranteed to contain (52 * 5) = 260 "workdays". So the total number
+of workdays in the year is determined by whether the extra days -- 1 in a
+common year, or 2 in a leap year -- fall on or between weekends.
+
+If a year begins on a Monday, then the final day of the 52-week block of days
+must be a Sunday: in which case, the following day(s) fall between weekends. A
+similar reasoning is easily applied to the other days of the week. For example,
+if the year begins on a Sunday, then the final day of the 52-week block of days
+must be a Saturday, and therefore the following day falls on a Sunday, and does
+NOT add to the total of workdays; but the day after that (if this is a leap
+year) falls on a Monday and DOES add to the total.
+
+In the solution below, these extra days have been pre-computed and stored in
+the constant arrays @COMMON and @LEAP_Y. The CPAN DateTime module is used to
+determine the day of the week on which the first day of the year falls, and
+also whether or not the year is a leap year. (Note the use of DateTime's
+day_of_week_0() method, which returns weekdays in 0-based order beginning with
+Monday.)
+
+=cut
+#==============================================================================
+
+use strict;
+use warnings;
+use Const::Fast;
+use DateTime;
+use Regexp::Common qw( number );
+
+const my $BASE   => 260;                      # 52 * 5
+const my @COMMON => ( 1, 1, 1, 1, 1, 0, 0 );  # Extra workday for a common year
+const my @LEAP_Y => ( 1, 1, 1, 1, 0, 0, 1 );  # Extra workday for a leap   year
+const my $USAGE  =>
+"Usage:
+  perl $0 <year>
+
+    <year>    Year in 4-digits form\n";
+
+#------------------------------------------------------------------------------
+BEGIN
+#------------------------------------------------------------------------------
+{
+    $| = 1;
+    print "\nChallenge 138, Task #1: Workdays (Perl)\n\n";
+}
+
+#==============================================================================
+MAIN:
+#==============================================================================
+{
+    my ($year) = parse_command_line();
+
+    print "Input:  \$year = $year\n";
+
+    my $dt_jan_1  = DateTime->new( year => $year, month => 1, day => 1 );
+    my $day_of_wk = $dt_jan_1->day_of_week_0;               # 0-6 (Monday is 0)
+    my $workdays  = $COMMON[ $day_of_wk ] + $BASE;
+       $workdays += $LEAP_Y[ $day_of_wk ] if $dt_jan_1->is_leap_year;
+
+    print "Output: $workdays\n";
+}
+
+#------------------------------------------------------------------------------
+sub parse_command_line
+#------------------------------------------------------------------------------
+{
+    my $args = scalar @ARGV;
+       $args == 1 or error( "Expected 1 command line argument, found $args" );
+
+    my $year = $ARGV[ 0 ];
+
+    $year =~ / ^ $RE{num}{int} $ /x
+                  or error( qq["$year" is not a valid integer] );
+
+    1 <= $year <= 9999
+                  or error( qq["$year" is not in 4-digit form] );
+
+    return $year + 0;                                               # Normalize
+}
+
+#------------------------------------------------------------------------------
+sub error
+#------------------------------------------------------------------------------
+{
+    my ($message) = @_;
+
+    die "ERROR: $message\n$USAGE";
+}
+
+###############################################################################
diff --git a/challenge-138/athanasius/perl/ch-2.pl b/challenge-138/athanasius/perl/ch-2.pl
new file mode 100644
index 0000000000..9690ccb3a3
--- /dev/null
+++ b/challenge-138/athanasius/perl/ch-2.pl
@@ -0,0 +1,239 @@
+#!perl
+
+###############################################################################
+=comment
+
+Perl Weekly Challenge 138
+=========================
+
+TASK #2
+-------
+*Split Number*
+
+Submitted by: Mohammad S Anwar
+
+You are given a perfect square.
+
+Write a script to figure out if the square root the given number is same as sum
+of 2 or more splits of the given number.
+
+Example 1
+
+ Input: $n = 81
+ Output: 1
+
+ Since, sqrt(81) = 8 + 1
+
+Example 2
+
+ Input: $n = 9801
+ Output: 1
+
+Since, sqrt(9801) = 98 + 0 + 1
+
+ Example 3
+
+ Input: $n = 36
+ Output: 0
+
+ Since, sqrt(36) != 3 + 6
+
+=cut
+###############################################################################
+
+#--------------------------------------#
+# Copyright © 2021 PerlMonk Athanasius #
+#--------------------------------------#
+
+#==============================================================================
+=comment
+
+Interface
+---------
+Output is as per the Examples, except that $n's square root is also given. If a
+simpler output (with no square root and no explanation) is desired, set the
+constant $VERBOSE to a false value.
+
+Algorithm
+---------
+The partitioning of "$n" into its possible substrings is accomplished by the
+recursive subroutine _get_splits_recursive(), which is adapted from the C++
+implementation in "Print all ways to break a string in bracket form" at:
+https://www.geeksforgeeks.org/print-ways-break-string-bracket-form/.
+
+Performance
+-----------
+A string of length s may be partitioned in 2 ^ (s - 1) different ways. For long
+strings (i.e., high values of $n), it may be expected that this will incur
+significant memory usage. In practice (by which I mean: by my observations
+using the Windows Task Manager), memory usage begins to become noticeably large
+only when $n reaches 19 digits in length.
+
+=cut
+#==============================================================================
+
+use strict;
+use warnings;
+use Const::Fast;
+use Regexp::Common qw( number );
+
+const my $VERBOSE => 1;
+const my $USAGE   =>
+"Usage:
+  perl $0 <n>
+
+    <n>    A perfect square\n";
+
+#------------------------------------------------------------------------------
+BEGIN
+#------------------------------------------------------------------------------
+{
+    $| = 1;
+    print "\nChallenge 138, Task #2: Split Number (Perl)\n\n";
+}
+
+#==============================================================================
+MAIN:
+#==============================================================================
+{
+    my ($n)   = parse_command_line();
+    my  $root = sqrt $n;
+
+    printf "Input:  \$n = %d%s\n", $n, $VERBOSE ? " (sqrt $root)" : '';
+
+    my @splits   = get_splits( $n );
+    my @solution = find_solution( $root, \@splits );
+
+    printf "Output: %d\n", scalar @solution > 0 ? 1 : 0;
+
+    if ($VERBOSE)
+    {
+        if (scalar @solution > 0)
+        {
+            printf qq[\nSince "%d" can be split into %s = %d\n],
+                      $n, join( ' + ', @solution ), $root;
+        }
+        else
+        {
+            print  qq[\nSince no split of "$n" sums to $root\n];
+        }
+    }
+}
+
+#------------------------------------------------------------------------------
+sub find_solution
+#------------------------------------------------------------------------------
+{
+    my ($root, $splits) = @_;
+    my  @solution;
+
+    for my $split (@$splits)
+    {
+        my $sum  = 0;
+           $sum += $_ for @$split;
+
+        if ($sum == $root)
+        {
+            @solution = @$split;
+            last;
+        }
+    }
+
+    return @solution;   # The first partition of $n (if any) that sums to $root
+}
+
+#==============================================================================
+# Partition a number
+#==============================================================================
+{
+    my @partitions;
+
+    #--------------------------------------------------------------------------
+    sub get_splits
+    #--------------------------------------------------------------------------
+    {
+        my ($n) = @_;
+
+        # (1) Find all possible unique partitions of the string "$n"
+
+        _get_splits_recursive( $n, 0, [] );
+
+        # (2) Weed out multi-digit numbers beginning with zero
+
+        my @splits;
+
+        OUTER:
+        for my $comb (@partitions)
+        {
+            for my $seg (@$comb)
+            {
+                next OUTER if $seg =~ / ^ 0 \d /x;
+            }
+
+            push @splits, $comb;
+        }
+
+        return @splits;
+    }
+
+    #--------------------------------------------------------------------------
+    # Adapted from "Print all ways to break a string in bracket form",
+    # https://www.geeksforgeeks.org/print-ways-break-string-bracket-form/
+    # (C++ implementation)
+    #
+    sub _get_splits_recursive
+    #--------------------------------------------------------------------------
+    {
+        my ($str, $index, $out) = @_;
+
+        if ($index == length $str)                            # Base case
+        {
+            push @partitions, $out;
+        }
+        else                                                  # Recursive cases
+        {
+            for my $i ($index .. length( $str ) - 1)
+            {
+                _get_splits_recursive
+                (
+                    $str,
+                    $i + 1,
+                    [ @$out, substr( $str, $index, $i + 1 - $index ) ]
+                );
+            }
+        }
+    }
+} # End partition block
+
+#------------------------------------------------------------------------------
+sub parse_command_line
+#------------------------------------------------------------------------------
+{
+    my $args = scalar @ARGV;
+       $args == 1 or error( "Expected 1 command line argument, found $args" );
+
+    my $n = $ARGV[ 0 ];
+
+    $n =~ / ^ $RE{num}{int} $ /x
+                  or error( qq["$n" is not a valid integer] );
+
+    $n >= 0       or error( 'A negative number cannot be a perfect square' );
+
+    my $root = int sqrt $n;
+
+    $root * $root == $n
+                  or error( "$n is not a perfect square" );
+
+    return $n;
+}
+
+#------------------------------------------------------------------------------
+sub error
+#------------------------------------------------------------------------------
+{
+    my ($message) = @_;
+
+    die "ERROR: $message\n$USAGE";
+}
+
+###############################################################################
diff --git a/challenge-138/athanasius/raku/ch-1.raku b/challenge-138/athanasius/raku/ch-1.raku
new file mode 100644
index 0000000000..2df6653ef3
--- /dev/null
+++ b/challenge-138/athanasius/raku/ch-1.raku
@@ -0,0 +1,106 @@
+use v6d;
+
+###############################################################################
+=begin comment
+
+Perl Weekly Challenge 138
+=========================
+
+TASK #1
+-------
+*Workdays*
+
+Submitted by: Mohammad S Anwar
+
+You are given a year, $year in 4-digits form.
+
+Write a script to calculate the total number of workdays in the given year.
+
+    For the task, we consider, Monday - Friday as workdays.
+
+Example 1
+
+ Input: $year = 2021
+ Output: 261
+
+Example 2
+
+ Input: $year = 2020
+ Output: 262
+
+=end comment
+###############################################################################
+
+#--------------------------------------#
+# Copyright © 2021 PerlMonk Athanasius #
+#--------------------------------------#
+
+#==============================================================================
+=begin comment
+
+Algorithm
+---------
+A common year has 365 days, a leap year 366. 52 weeks is 364 days, and those 52
+weeks are guaranteed to contain (52 * 5) = 260 "workdays". So the total number
+of workdays in the year is determined by whether the extra days -- 1 in a
+common year, or 2 in a leap year -- fall on or between weekends.
+
+If a year begins on a Monday, then the final day of the 52-week block of days
+must be a Sunday: in which case, the following day(s) fall between weekends. A
+similar reasoning is easily applied to the other days of the week. For example,
+if the year begins on a Sunday, then the final day of the 52-week block of days
+must be a Saturday, and therefore the following day falls on a Sunday, and does
+NOT add to the total of workdays; but the day after that (if this is a leap
+year) falls on a Monday and DOES add to the total.
+
+In the solution below, these extra days have been pre-computed and stored in
+the constant arrays @COMMON and @LEAP-Y. The inbuilt Raku Date class is used to
+determine the day of the week on which the first day of the year falls, and
+also whether or not the year is a leap year. (Note that Date's day-of-week()
+method returns an Int in the range 1 to 7, with 1 being Monday. This number is
+decremented to facilitate its use as an index into the @COMMON and @LEAP-Y
+arrays.)
+
+=end comment
+#==============================================================================
+
+my UInt constant $BASE   = 260;                                        # 52 * 5
+my      constant @COMMON = Array[Int].new: 1, 1, 1, 1, 1, 0, 0;
+my      constant @LEAP-Y = Array[Int].new: 1, 1, 1, 1, 0, 0, 1;
+
+#------------------------------------------------------------------------------
+BEGIN
+#------------------------------------------------------------------------------
+{
+    "\nChallenge 138, Task #1: Workdays (Raku)\n".put;
+}
+
+#==============================================================================
+sub MAIN
+(
+    UInt:D $year where 1 <= $year <= 9999              #= Year in 4-digits form
+)
+#==============================================================================
+{
+    "Input:  \$year = %d\n".printf: $year.UInt;                     # Normalize
+
+    my Date $dt-jan1   = Date.new: $year, 1, 1;
+    my UInt $day-of-wk = $dt-jan1.day-of-week - 1;
+    my UInt $workdays  = @COMMON[ $day-of-wk ] + $BASE;
+            $workdays += @LEAP-Y[ $day-of-wk ] if $dt-jan1.is-leap-year;
+
+    "Output: $workdays".put;
+}
+
+#------------------------------------------------------------------------------
+sub USAGE()
+#------------------------------------------------------------------------------
+{
+    my Str $usage = $*USAGE;
+
+    $usage ~~ s/ ($*PROGRAM-NAME) /raku $0/;
+
+    $usage.put;
+}
+
+##############################################################################
diff --git a/challenge-138/athanasius/raku/ch-2.raku b/challenge-138/athanasius/raku/ch-2.raku
new file mode 100644
index 0000000000..39b7167d6e
--- /dev/null
+++ b/challenge-138/athanasius/raku/ch-2.raku
@@ -0,0 +1,217 @@
+use v6d;
+
+###############################################################################
+=begin comment
+
+Perl Weekly Challenge 138
+=========================
+
+TASK #2
+-------
+*Split Number*
+
+Submitted by: Mohammad S Anwar
+
+You are given a perfect square.
+
+Write a script to figure out if the square root the given number is same as sum
+of 2 or more splits of the given number.
+
+Example 1
+
+ Input: $n = 81
+ Output: 1
+
+ Since, sqrt(81) = 8 + 1
+
+Example 2
+
+ Input: $n = 9801
+ Output: 1
+
+Since, sqrt(9801) = 98 + 0 + 1
+
+ Example 3
+
+ Input: $n = 36
+ Output: 0
+
+ Since, sqrt(36) != 3 + 6
+
+=end comment
+###############################################################################
+
+#--------------------------------------#
+# Copyright © 2021 PerlMonk Athanasius #
+#--------------------------------------#
+
+#==============================================================================
+=begin comment
+
+Interface
+---------
+Output is as per the Examples, except that $n's square root is also given. If a
+simpler output (with no square root and no explanation) is desired, set the
+constant $VERBOSE to False.
+
+Algorithm
+---------
+The partitioning of "$n" into its possible substrings is accomplished by the
+recursive subroutine get_splits_recursive(), which is adapted from the C++
+implementation in "Print all ways to break a string in bracket form" at:
+https://www.geeksforgeeks.org/print-ways-break-string-bracket-form/.
+
+Performance
+-----------
+A string of length s may be partitioned in 2 ^ (s - 1) different ways. For long
+strings (i.e., high values of $n), it may be expected that this will incur
+significant memory usage. In practice (by which I mean: by my observations
+using the Windows Task Manager), memory usage begins to become noticeably large
+only when $n reaches 13 digits in length.
+
+=end comment
+#==============================================================================
+
+my Bool constant $VERBOSE = True;
+
+#------------------------------------------------------------------------------
+BEGIN
+#------------------------------------------------------------------------------
+{
+    "\nChallenge 138, Task #2: Split Number (Raku)\n".put;
+}
+
+#==============================================================================
+sub MAIN
+(
+    UInt:D $n where is-square( $n )                         #= A perfect square
+)
+#==============================================================================
+{
+    my UInt $root = $n.sqrt.Int;
+
+    "Input:  \$n = %d%s\n".printf: $n, $VERBOSE ?? " (sqrt $root)" !! '';
+
+    my Array[UInt] @splits   = Partition::get-splits( $n );
+    my UInt        @solution = find-solution( $root, @splits );
+
+    "Output: %d\n".printf: @solution.elems > 0 ?? 1 !! 0;
+
+    if $VERBOSE
+    {
+        if @solution.elems > 0
+        {
+            qq[\nSince "%d" can be split into %s = %d\n].printf:
+                $n, @solution.join( ' + ' ), $root;
+        }
+        else
+        {
+            qq[\nSince no split of "$n" sums to $root].put;
+        }
+    }
+}
+
+#------------------------------------------------------------------------------
+sub find-solution
+(
+    UInt:D                   $root,
+    Array:D[Array:D[UInt:D]] $splits
+--> Array:D[UInt:D]
+)
+#------------------------------------------------------------------------------
+{
+    my UInt @solution;
+
+    for @$splits -> Array[UInt] $split
+    {
+        my UInt $sum = [+] @$split;
+
+        if $sum == $root
+        {
+            @solution = @$split;
+            last;
+        }
+    }
+
+    return @solution;   # The first partition of $n (if any) that sums to $root
+}
+
+#==============================================================================
+package Partition
+#==============================================================================
+{
+    my Array[Str] @partitions;
+
+    #--------------------------------------------------------------------------
+    our sub get-splits( UInt:D $n --> Array:D[Array:D[UInt:D]] )
+    #--------------------------------------------------------------------------
+    {
+        # (1) Find all possible unique partitions of the string "$n"
+
+        get-splits-recursive( $n, 0, [] );
+
+        # (2) Weed out multi-digit numbers beginning with zero
+
+        my Array[UInt] @splits;
+
+        L-OUTER:
+        for @partitions -> Array[Str] $comb
+        {
+            for @$comb -> Str $seg
+            {
+                next L-OUTER if $seg ~~ / ^ 0 \d /;
+            }
+
+            @splits.push: Array[UInt].new: $comb.map: { .Int };
+        }
+
+        # (3) Return the valid partitions as integer arrays
+
+        return @splits;
+    }
+
+    #--------------------------------------------------------------------------
+    # Adapted from "Print all ways to break a string in bracket form",
+    # https://www.geeksforgeeks.org/print-ways-break-string-bracket-form/
+    # (C++ implementation)
+    #
+    sub get-splits-recursive( Str:D $str, UInt:D $index, Array:D[Str:D] $out )
+    #--------------------------------------------------------------------------
+    {
+        if $index == $str.chars                               # Base case
+        {
+            @partitions.push: $out;
+        }
+        else                                                  # Recursive cases
+        {
+            for $index .. $str.chars - 1 -> UInt $i
+            {
+                my Str @new-out = Array[Str].new:
+                    |$out, $str.substr: $index, $i + 1 - $index;
+
+                get-splits-recursive( $str, $i + 1, @new-out );
+            }
+        }
+    }
+} # End package Partition
+
+#------------------------------------------------------------------------------
+sub is-square( UInt:D $n --> Bool:D )
+#------------------------------------------------------------------------------
+{
+    my UInt $root = $n.sqrt.floor;
+
+    return $root * $root == $n;
+}
+
+#------------------------------------------------------------------------------
+sub USAGE()
+#------------------------------------------------------------------------------
+{
+    my Str $usage = $*USAGE;
+
+    $usage ~~ s/ ($*PROGRAM-NAME) /raku $0/;
+    $usage.put;
+}
+
+##############################################################################