new file: challenge-347/mattneleigh/perl/ch-1.pl

new file:   challenge-347/mattneleigh/perl/ch-2.pl

2 files changed, 155 insertions, 0 deletions

diff --git a/challenge-347/mattneleigh/perl/ch-1.pl b/challenge-347/mattneleigh/perl/ch-1.pl
new file mode 100755
index 0000000000..cab99d6036
--- /dev/null
+++ b/challenge-347/mattneleigh/perl/ch-1.pl
@@ -0,0 +1,71 @@
+#!/usr/bin/perl
+
+use strict;
+use warnings;
+use English;
+
+################################################################################
+# Begin main execution
+################################################################################
+
+my @dates = (
+    "1st Jan 2025",
+    "22nd Feb 2025",
+    "15th Apr 2025",
+    "23rd Oct 2025",
+    "31st Dec 2025"
+);
+
+print("\n");
+foreach my $date (@dates){
+    printf(
+        "Input: \$str = \"%s\"\nOutput: \"%s\"\n\n",
+        $date,
+        date_to_iso_format($date)
+    );
+}
+
+exit(0);
+################################################################################
+# End main execution; subroutines follow
+################################################################################
+
+
+
+################################################################################
+# Given a date in the form of an ordinal day, capitalized three-letter
+# abbreviation of the month, and a four-digit year (e.g. "10th Nov 2025")
+# convert it to ISO 8601 date format, i.e. "2025-11-10"
+# Takes one argument:
+# * The date string to convert (see above for example)
+# Returns:
+# * The supplied date in ISO 8601 format (see above for example)
+################################################################################
+sub date_to_iso_format{
+    my @day_month_year = split(" ", shift());
+
+    my %months = (
+        Jan => "01", Feb => "02", Mar => "03", Apr => "04",
+        May => "05", Jun => "06", Jul => "06", Aug => "08",
+        Sep => "09", Oct => "10", Nov => "11", Dec => "12"
+    );
+
+    # Strip the ordinal suffix from the day
+    $day_month_year[0] =~ s/\D//g;
+
+    return(
+        $day_month_year[2]
+        .
+        "-"
+        .
+        $months{$day_month_year[1]}
+        .
+        "-"
+        .
+        sprintf("%02d", $day_month_year[0])
+    );
+
+}
+
+
+
diff --git a/challenge-347/mattneleigh/perl/ch-2.pl b/challenge-347/mattneleigh/perl/ch-2.pl
new file mode 100755
index 0000000000..e42bc78ff5
--- /dev/null
+++ b/challenge-347/mattneleigh/perl/ch-2.pl
@@ -0,0 +1,84 @@
+#!/usr/bin/perl
+
+use strict;
+use warnings;
+use English;
+
+################################################################################
+# Begin main execution
+################################################################################
+
+my @phone_numbers = (
+    "1-23-45-6",
+    "1234",
+    "12 345-6789",
+    "123 4567",
+    "123 456-78"
+);
+
+print("\n");
+foreach my $phone_number (@phone_numbers){
+    printf(
+        "Input: \$phone = \"%s\"\nOutput: \"%s\"\n\n",
+        $phone_number,
+        reformat_telephone_number($phone_number)
+    );
+}
+
+exit(0);
+################################################################################
+# End main execution; subroutines follow
+################################################################################
+
+
+
+################################################################################
+# Given a telephone number consisting only of digits, spaces, or dashes,
+# reformat it into dash-separated blocks according to the following rules:
+# 1) All digits will be grouped into blocks of three (3) except...
+# 2) The final four (4) or fewer digits, if any, will be...
+#     2a) ...presented as a single block of digits if fewer than four digits
+#         remain
+#     2b) ...presented as two blocks of two digits if four digits remain
+# Takes one argument:
+# * The phone number to process (e.g. "123 4567")
+# Returns:
+# * The phone number reformatted as described above (e.g. "123-45-67")
+################################################################################
+sub reformat_telephone_number{
+    # Grab only the digits from the input
+    my @digits = grep(/\d/, split("", shift()));
+
+    my $reformatted = "";
+
+    # Create blocks of three digits, leaving only the
+    # last four or fewer digits for later processing
+    while(scalar(@digits) > 4){
+        $reformatted .= "-"
+            if(length($reformatted));
+        $reformatted .= join("", splice(@digits, 0, 3));
+    }
+
+    # Handle remaining digits, if necessary
+    if(scalar(@digits)){
+        if(scalar(@digits) == 4){
+            # 4 digits
+            for(0 .. 1){
+                $reformatted .= "-"
+                    if(length($reformatted));
+                $reformatted .= join("", splice(@digits, 0, 2));
+            }
+        } else{
+            # 1-3 digits
+            $reformatted .= "-"
+                if(length($reformatted));
+            $reformatted .= join("", splice(@digits, 0));
+        }
+    }
+
+    return($reformatted);
+
+}
+
+
+