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authorMichael Manring <michael@manring>2024-03-12 13:50:16 +1100
committerMichael Manring <michael@manring>2024-03-12 13:50:16 +1100
commit867127a74fe3c558a20cba4b1cd609f8e987e4ba (patch)
tree622b1d475075e28e88374dde104db08a5b0b57b1
parent87dfd7b9a9b717fa6847ee0e0710e2798ea76ce6 (diff)
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pwc260 solution in go
-rw-r--r--challenge-260/pokgopun/go/ch-1.go104
-rw-r--r--challenge-260/pokgopun/go/ch-2.go98
2 files changed, 202 insertions, 0 deletions
diff --git a/challenge-260/pokgopun/go/ch-1.go b/challenge-260/pokgopun/go/ch-1.go
new file mode 100644
index 0000000000..a401e1588a
--- /dev/null
+++ b/challenge-260/pokgopun/go/ch-1.go
@@ -0,0 +1,104 @@
+//# https://theweeklychallenge.org/blog/perl-weekly-challenge-260/
+/*#
+
+Task 1: Unique Occurrences
+
+Submitted by: [42]Mohammad Sajid Anwar
+ __________________________________________________________________
+
+ You are given an array of integers, @ints.
+
+ Write a script to return 1 if the number of occurrences of each value
+ in the given array is unique or 0 otherwise.
+
+Example 1
+
+Input: @ints = (1,2,2,1,1,3)
+Output: 1
+
+The number 1 occurred 3 times.
+The number 2 occurred 2 times.
+The number 3 occurred 1 time.
+
+All occurrences are unique, therefore the output is 1.
+
+Example 2
+
+Input: @ints = (1,2,3)
+Output: 0
+
+Example 3
+
+Input: @ints = (-2,0,1,-2,1,1,0,1,-2,9)
+Output: 1
+
+Task 2: Dictionary Rank
+#*/
+//# solution by pokgopun@gmail.com
+
+package main
+
+import (
+ "io"
+ "os"
+
+ "github.com/google/go-cmp/cmp"
+)
+
+type ints []int
+
+type myMap map[int]int
+
+func newMyMap() myMap {
+ return make(myMap)
+}
+
+func (mm myMap) proc(is ints) {
+ clear(mm)
+ for _, v := range is {
+ mm[v]++
+ }
+}
+
+func (mm myMap) keys() ints {
+ var s ints
+ for k := range mm {
+ s = append(s, k)
+ }
+ return s
+}
+
+func (mm myMap) values() ints {
+ var s ints
+ for _, v := range mm {
+ s = append(s, v)
+ }
+ return s
+}
+
+func (mm myMap) uo(is ints) bool {
+ mm.proc(is)
+ //fmt.Println("mm = ", mm)
+ count_uniq_elem := len(mm.keys())
+ //fmt.Println("count_uniq_elem =", count_uniq_elem)
+ mm.proc(mm.values())
+ //fmt.Println("mm = ", mm)
+ count_uniq_occur := len(mm.keys())
+ //fmt.Println("count_uniq_occur =", count_uniq_occur)
+ return count_uniq_elem == count_uniq_occur
+}
+
+func main() {
+ mm := newMyMap()
+ for _, data := range []struct {
+ input ints
+ output bool
+ }{
+ {ints{1, 2, 2, 1, 1, 3}, true},
+ {ints{1, 2, 3}, false},
+ {ints{-2, 0, 1, -2, 1, 1, 0, 1, -2, 9}, true},
+ } {
+ //fmt.Println(data.input)
+ io.WriteString(os.Stdout, cmp.Diff(mm.uo(data.input), data.output)) // blank if ok, otherwise show the differences
+ }
+}
diff --git a/challenge-260/pokgopun/go/ch-2.go b/challenge-260/pokgopun/go/ch-2.go
new file mode 100644
index 0000000000..aba232c3e9
--- /dev/null
+++ b/challenge-260/pokgopun/go/ch-2.go
@@ -0,0 +1,98 @@
+//# https://theweeklychallenge.org/blog/perl-weekly-challenge-260/
+/*#
+
+Task 2: Dictionary Rank
+
+Submitted by: [43]Mark Anderson
+ __________________________________________________________________
+
+ You are given a word, $word.
+
+ Write a script to compute the dictionary rank of the given word.
+
+Example 1
+
+Input: $word = 'CAT'
+Output: 3
+
+All possible combinations of the letters:
+CAT, CTA, ATC, TCA, ACT, TAC
+
+Arrange them in alphabetical order:
+ACT, ATC, CAT, CTA, TAC, TCA
+
+CAT is the 3rd in the list.
+Therefore the dictionary rank of CAT is 3.
+
+Example 2
+
+Input: $word = 'GOOGLE'
+Output: 88
+
+Example 3
+
+Input: $word = 'SECRET'
+Output: 255
+ __________________________________________________________________
+
+ Last date to submit the solution 23:59 (UK Time) Sunday 17th March
+ 2024.
+ __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+#*/
+//# solution by pokgopun@gmail.com
+
+package main
+
+import (
+ "io"
+ "os"
+ "slices"
+ "strings"
+
+ "github.com/google/go-cmp/cmp"
+)
+
+func dc(word string) int {
+ var res string
+ s := strings.Split(permute(word, "", &res), " ")
+ slices.Sort(s)
+ l := len(s)
+ i, j := 0, l
+ for j > 1 {
+ if s[i] == s[i+1] {
+ copy(s[i:], s[i+1:])
+ l--
+ } else {
+ i++
+ }
+ j--
+ }
+ return slices.Index(s, word) + 1
+}
+
+func permute(s, t string, res *string) string {
+ if len(s) > 0 {
+ for i, v := range []byte(s) {
+ permute(s[:i]+s[i+1:], t+string(v), res)
+ }
+ } else {
+ *res += " " + t
+ return ""
+ }
+ return (*res)[1:]
+}
+
+func main() {
+ for _, data := range []struct {
+ input string
+ output int
+ }{
+ {"CAT", 3},
+ {"GOOGLE", 88},
+ {"SECRET", 255},
+ } {
+ io.WriteString(os.Stdout, cmp.Diff(dc(data.input), data.output)) // blank if ok, otherwise show the differences
+ }
+}