aboutsummaryrefslogtreecommitdiff
diff options
context:
space:
mode:
authorMohammad S Anwar <Mohammad.Anwar@yahoo.com>2022-12-05 01:16:33 +0000
committerGitHub <noreply@github.com>2022-12-05 01:16:33 +0000
commit933c2e39f0f3d32bae6bdb765157a85f8db9a454 (patch)
tree79a9e37a567e531fec6b4ae9a19692591c005fc3
parent18bc7b98f8463db53b61fd2d68125e24c9cb6bb1 (diff)
parent56f9787695c9913d9dcaeac567c687a1c5a1484a (diff)
downloadperlweeklychallenge-club-933c2e39f0f3d32bae6bdb765157a85f8db9a454.tar.gz
perlweeklychallenge-club-933c2e39f0f3d32bae6bdb765157a85f8db9a454.tar.bz2
perlweeklychallenge-club-933c2e39f0f3d32bae6bdb765157a85f8db9a454.zip
Merge pull request #7206 from dcw803/master
added my late solutions to challenge 192 (Perl x 2 + C x 2) and..
-rw-r--r--challenge-192/duncan-c-white/C/Makefile19
-rw-r--r--challenge-192/duncan-c-white/C/README9
-rw-r--r--challenge-192/duncan-c-white/C/args.c207
-rw-r--r--challenge-192/duncan-c-white/C/args.h11
-rw-r--r--challenge-192/duncan-c-white/C/ch-1.c37
-rw-r--r--challenge-192/duncan-c-white/C/ch-2.c142
-rw-r--r--challenge-192/duncan-c-white/C/parseints.c114
-rw-r--r--challenge-192/duncan-c-white/C/parseints.h1
-rw-r--r--challenge-192/duncan-c-white/C/printarray.c39
-rw-r--r--challenge-192/duncan-c-white/C/printarray.h1
-rw-r--r--challenge-192/duncan-c-white/README121
-rwxr-xr-xchallenge-192/duncan-c-white/perl/ch-1.pl62
-rwxr-xr-xchallenge-192/duncan-c-white/perl/ch-2.pl154
-rw-r--r--challenge-193/duncan-c-white/C/.cbuild2
-rw-r--r--challenge-193/duncan-c-white/C/Makefile14
-rw-r--r--challenge-193/duncan-c-white/C/README7
-rw-r--r--challenge-193/duncan-c-white/C/args.c207
-rw-r--r--challenge-193/duncan-c-white/C/args.h11
-rw-r--r--challenge-193/duncan-c-white/C/ch-1.c61
-rw-r--r--challenge-193/duncan-c-white/README108
-rwxr-xr-xchallenge-193/duncan-c-white/perl/ch-1.pl46
-rwxr-xr-xchallenge-193/duncan-c-white/perl/ch-2.pl116
22 files changed, 1371 insertions, 118 deletions
diff --git a/challenge-192/duncan-c-white/C/Makefile b/challenge-192/duncan-c-white/C/Makefile
new file mode 100644
index 0000000000..0e674ee7dd
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/Makefile
@@ -0,0 +1,19 @@
+# Makefile rules generated by CB
+CC = gcc
+CFLAGS = -Wall -g
+BUILD = ch-1 ch-2
+
+all: $(BUILD)
+
+clean:
+ /bin/rm -f $(BUILD) *.o core a.out
+
+args.o: args.c
+ch-1: ch-1.o args.o
+ch-1.o: ch-1.c args.h
+ch-2: ch-2.o args.o nextintperm.o parseints.o printarray.o
+ch-2.o: ch-2.c args.h nextintperm.h parseints.h printarray.h
+nextintperm.o: nextintperm.c nextintperm.h
+parseints.o: parseints.c args.h parseints.h printarray.h
+printarray.o: printarray.c
+
diff --git a/challenge-192/duncan-c-white/C/README b/challenge-192/duncan-c-white/C/README
new file mode 100644
index 0000000000..31e5ebdb28
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/README
@@ -0,0 +1,9 @@
+Thought I'd also have a go at translating ch-1.pl and ch-2.pl into C..
+
+Both produce near-identical (non-debugging and even debugging) output to my
+Perl originals.
+
+They use several of my regular support modules:
+- a command-line argument processing module args.[ch],
+- a csvlist-of-int parsing module parseints.[ch], and
+- an int-array printing module printarray.[ch].
diff --git a/challenge-192/duncan-c-white/C/args.c b/challenge-192/duncan-c-white/C/args.c
new file mode 100644
index 0000000000..d4a2d38b9a
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/args.c
@@ -0,0 +1,207 @@
+#include <stdio.h>
+#include <stdlib.h>
+#include <stdbool.h>
+#include <string.h>
+#include <ctype.h>
+#include <assert.h>
+
+
+bool debug = false;
+
+
+// process_flag_noarg( name, argc, argv );
+// Process the -d flag, and check that there are no
+// remaining arguments.
+void process_flag_noarg( char *name, int argc, char **argv )
+{
+ int arg=1;
+ if( argc>1 && strcmp( argv[arg], "-d" ) == 0 )
+ {
+ debug = true;
+ arg++;
+ }
+
+ int left = argc-arg;
+ if( left != 0 )
+ {
+ fprintf( stderr, "Usage: %s [-d]\n", name );
+ exit(1);
+ }
+}
+
+
+// int argno = process_flag_n_args( name, argc, argv, n, argmsg );
+// Process the -d flag, and check that there are exactly
+// n remaining arguments, return the index position of the first
+// argument. If not, generate a fatal Usage error using the argmsg.
+//
+int process_flag_n_args( char *name, int argc, char **argv, int n, char *argmsg )
+{
+ int arg=1;
+ if( argc>1 && strcmp( argv[arg], "-d" ) == 0 )
+ {
+ debug = true;
+ arg++;
+ }
+
+ int left = argc-arg;
+ if( left != n )
+ {
+ fprintf( stderr, "Usage: %s [-d] %s\n Exactly %d "
+ "arguments needed\n", name, argmsg, n );
+ exit(1);
+ }
+ return arg;
+}
+
+
+// int argno = process_flag_n_m_args( name, argc, argv, min, max, argmsg );
+// Process the -d flag, and check that there are between
+// min and max remaining arguments, return the index position of the first
+// argument. If not, generate a fatal Usage error using the argmsg.
+//
+int process_flag_n_m_args( char *name, int argc, char **argv, int min, int max, char *argmsg )
+{
+ int arg=1;
+ if( argc>1 && strcmp( argv[arg], "-d" ) == 0 )
+ {
+ debug = true;
+ arg++;
+ }
+
+ int left = argc-arg;
+ if( left < min || left > max )
+ {
+ fprintf( stderr, "Usage: %s [-d] %s\n Between %d and %d "
+ "arguments needed\n", name, argmsg, min, max );
+ exit(1);
+ }
+ return arg;
+}
+
+
+// process_onenumarg_default( name, argc, argv, defvalue, &n );
+// Process the -d flag, and check that there is a single
+// remaining numeric argument (or no arguments, in which case
+// we use the defvalue), putting it into n
+void process_onenumarg_default( char *name, int argc, char **argv, int defvalue, int *n )
+{
+ char argmsg[100];
+ sprintf( argmsg, "[int default %d]", defvalue );
+ int arg = process_flag_n_m_args( name, argc, argv, 0, 1, argmsg );
+
+ *n = arg == argc ? defvalue : atoi( argv[arg] );
+}
+
+
+// process_onenumarg( name, argc, argv, &n );
+// Process the -d flag, and check that there is a single
+// remaining numeric argument, putting it into n
+void process_onenumarg( char *name, int argc, char **argv, int *n )
+{
+ int arg = process_flag_n_args( name, argc, argv, 1, "int" );
+
+ // argument is in argv[arg]
+ *n = atoi( argv[arg] );
+}
+
+
+// process_twonumargs( name, argc, argv, &m, &n );
+// Process the -d flag, and check that there are 2
+// remaining numeric arguments, putting them into m and n
+void process_twonumargs( char *name, int argc, char **argv, int *m, int *n )
+{
+ int arg = process_flag_n_args( name, argc, argv, 2, "int" );
+
+ // arguments are in argv[arg] and argv[arg+1]
+ *m = atoi( argv[arg++] );
+ *n = atoi( argv[arg] );
+}
+
+
+// process_twostrargs() IS DEPRECATED: use process_flag_n_m_args() instead
+
+
+// int arr[100];
+// int nel = process_listnumargs( name, argc, argv, arr, 100 );
+// Process the -d flag, and check that there are >= 2
+// remaining numeric arguments, putting them into arr[0..nel-1]
+// and returning nel.
+int process_listnumargs( char *name, int argc, char **argv, int *arr, int maxel )
+{
+ int arg=1;
+ if( argc>1 && strcmp( argv[arg], "-d" ) == 0 )
+ {
+ debug = true;
+ arg++;
+ }
+
+ int left = argc-arg;
+ if( left < 2 )
+ {
+ fprintf( stderr, "Usage: %s [-d] list_of_numeric_args\n", name );
+ exit(1);
+ }
+ if( left > maxel )
+ {
+ fprintf( stderr, "%s: more than %d args\n", name, maxel );
+ exit(1);
+ }
+
+ // elements are in argv[arg], argv[arg+1]...
+
+ if( debug )
+ {
+ printf( "debug: remaining arguments are in arg=%d, "
+ "firstn=%s, secondn=%s..\n",
+ arg, argv[arg], argv[arg+1] );
+ }
+
+ int nel = 0;
+ for( int i=arg; i<argc; i++ )
+ {
+ arr[nel++] = atoi( argv[i] );
+ }
+ arr[nel] = -1;
+ return nel;
+}
+
+
+//
+// bool isint = check_unsigned_int( char *val, int *n );
+// Given an string val, check that there's an unsigned integer
+// in it (after optional whitespace). If there is a valid
+// unsigned integer value, store that integer value in *n and
+// return true; otherwise return false (and don't alter *n).
+bool check_unsigned_int( char *val, int *n )
+{
+ // skip whitespace in val
+ char *p;
+ for( p=val; isspace(*p); p++ )
+ {
+ /*EMPTY*/
+ }
+ if( ! isdigit(*p) ) return false;
+ *n = atoi(p);
+ return true;
+}
+
+
+//
+// bool ok = check_unsigned_real( char *val, double *n );
+// Given an string val, check that there's an unsigned real
+// in it (after optional whitespace). If there is a valid
+// unsigned real value, store that value in *n and
+// return true; otherwise return false (and don't alter *n).
+bool check_unsigned_real( char *val, double *n )
+{
+ // skip whitespace in val
+ char *p;
+ for( p=val; isspace(*p); p++ )
+ {
+ /*EMPTY*/
+ }
+ if( ! isdigit(*p) ) return false;
+ *n = atof(p);
+ return true;
+}
diff --git a/challenge-192/duncan-c-white/C/args.h b/challenge-192/duncan-c-white/C/args.h
new file mode 100644
index 0000000000..8844a8f9c4
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/args.h
@@ -0,0 +1,11 @@
+extern bool debug;
+
+extern void process_flag_noarg( char * name, int argc, char ** argv );
+extern int process_flag_n_args( char * name, int argc, char ** argv, int n, char * argmsg );
+extern int process_flag_n_m_args( char * name, int argc, char ** argv, int min, int max, char * argmsg );
+extern void process_onenumarg_default( char * name, int argc, char ** argv, int defvalue, int * n );
+extern void process_onenumarg( char * name, int argc, char ** argv, int * n );
+extern void process_twonumargs( char * name, int argc, char ** argv, int * m, int * n );
+extern int process_listnumargs( char * name, int argc, char ** argv, int * arr, int maxel );
+extern bool check_unsigned_int( char * val, int * n );
+extern bool check_unsigned_real( char * val, double * n );
diff --git a/challenge-192/duncan-c-white/C/ch-1.c b/challenge-192/duncan-c-white/C/ch-1.c
new file mode 100644
index 0000000000..d9f6d1cd22
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/ch-1.c
@@ -0,0 +1,37 @@
+//
+// Task 1: Binary Flip
+//
+// C version.
+//
+
+#include <stdio.h>
+#include <stdlib.h>
+#include <stdbool.h>
+#include <string.h>
+#include <ctype.h>
+#include <assert.h>
+
+#include "args.h"
+
+
+int main( int argc, char **argv )
+{
+ int n;
+ process_onenumarg_default( "binary-flip", argc, argv, 100, &n );
+
+ if( debug )
+ {
+ printf( "debug: n=%d\n", n );
+ }
+
+ int p = 1;
+ while( p < n )
+ {
+ p *= 2;
+ }
+
+ n = (~ n) & (p-1);
+ printf( "%d\n", n );
+
+ return 0;
+}
diff --git a/challenge-192/duncan-c-white/C/ch-2.c b/challenge-192/duncan-c-white/C/ch-2.c
new file mode 100644
index 0000000000..0b604739e1
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/ch-2.c
@@ -0,0 +1,142 @@
+//
+// Task 2: Equal Distribution
+//
+// C version.
+//
+
+#include <stdio.h>
+#include <stdlib.h>
+#include <stdbool.h>
+#include <string.h>
+#include <ctype.h>
+#include <assert.h>
+
+#include "args.h"
+#include "parseints.h"
+#include "printarray.h"
+
+
+//
+// int pos = find_pair_diff_gt_1(nel, list[]);
+// Find the position pos of the first element of the first pair in list
+// where the absolute difference between list[pos] and list[pos+1] is > 1.
+// Return -1 if none.
+//
+int find_pair_diff_gt_1( int nel, int *list )
+{
+ for( int pos=0; pos<nel-1; pos++ )
+ {
+ if( abs( list[pos] - list[pos+1] ) > 1 ) return pos;
+ }
+ return -1;
+}
+
+
+//
+// int pos = find_pair_f_lt_s(nel, list[]);
+// Find the position pos of the first element of a pair in @list
+// where list[$pos] < list[pos+1]. Return -1 if none.
+//
+int find_pair_f_lt_s( int nel, int *list )
+{
+ for( int pos=0; pos<nel-1; pos++ )
+ {
+ if( list[pos] < list[pos+1] ) return pos;
+ }
+ return -1;
+}
+
+
+int main( int argc, char **argv )
+{
+ int argno = process_flag_n_m_args( "equal-distribution", argc, argv,
+ 1, 1000, "intlist" );
+
+ int nel;
+ int *list = parse_int_args( argc, argv, argno, &nel );
+
+ if( nel < 2 )
+ {
+ fprintf( stderr, "equal-distribution: need a list of > 1 elements\n" );
+ exit(1);
+ }
+
+ if( debug )
+ {
+ printf( "debug: initial list: " );
+ print_int_array( 60, nel, list, ',', stdout );
+ putchar( '\n' );
+ }
+
+ int nmoves = 0;
+
+ if( debug )
+ {
+ printf( "starting first pass\n" );
+ }
+
+ // first pass: repeatedly find two adjacent cells whose absolute
+ // difference > 1 and transfer one from the bigger to the smaller.
+ int pos;
+ while( (pos = find_pair_diff_gt_1(nel, list)) != -1 )
+ {
+ if( debug )
+ {
+ printf( "debug: found pos %d, list=", pos );
+ print_int_array( 60, nel, list, ',', stdout );
+ putchar( '\n' );
+ }
+ if( list[pos] < list[pos+1] )
+ {
+ list[pos]++;
+ list[pos+1]--;
+ } else
+ {
+ list[pos]--;
+ list[pos+1]++;
+ }
+ nmoves++;
+ }
+
+ if( debug )
+ {
+ printf( "starting second pass\n" );
+ }
+
+ // second pass: repeatedly find 2 adjacent cells where
+ // firstvalue < secondvalue and transfer one from secondvalue
+ // to firstvalue
+ while( (pos = find_pair_f_lt_s(nel, list)) != -1 )
+ {
+ if( debug )
+ {
+ printf( "debug: found pos %d, list=", pos );
+ print_int_array( 60, nel, list, ',', stdout );
+ putchar( '\n' );
+ }
+ list[pos]++;
+ list[pos+1]--;
+ nmoves++;
+ }
+
+ int firstel = list[0];
+ int nsame = 0;
+ for( pos=0; pos<nel; pos++ )
+ {
+ if( list[pos] == firstel ) nsame++;
+ }
+ bool success = nsame == nel;
+
+ if( debug )
+ {
+ printf( "debug: after %d moves, nsame=%d, success=%d, "
+ "final list=", nmoves, nsame, success );
+ print_int_array( 60, nel, list, ',', stdout );
+ putchar( '\n' );
+ }
+ printf( "%d\n", success ? nmoves : -1 );
+
+ free( list );
+
+ return 0;
+}
diff --git a/challenge-192/duncan-c-white/C/parseints.c b/challenge-192/duncan-c-white/C/parseints.c
new file mode 100644
index 0000000000..0fb9985633
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/parseints.c
@@ -0,0 +1,114 @@
+// Simple routine to parse one or more arguments,
+// looking for individual +ints or comma-separated
+// lists of +ints.
+//
+
+#include <stdio.h>
+#include <stdlib.h>
+#include <stdbool.h>
+#include <string.h>
+#include <ctype.h>
+#include <assert.h>
+
+#include "args.h"
+#include "printarray.h"
+#include "parseints.h"
+
+typedef struct
+{
+ int nel; // current number of elements
+ int maxel; // maximum number of elements allocated
+ int *list; // malloc()d list of integers
+} intlist;
+
+
+//
+// intlist il.. then initialize il.. then:
+// add_one( element, &il );
+//
+static void add_one( int x, intlist *p )
+{
+ if( p->nel > p->maxel )
+ {
+ p->maxel += 128;
+ p->list = realloc( p->list, p->maxel );
+ assert( p->list );
+ }
+ #if 0
+ if( debug )
+ {
+ printf( "PIA: appending %d to result at "
+ "pos %d\n", x, p->nel );
+ }
+ #endif
+ p->list[p->nel++] = x;
+}
+
+
+//
+// intlist il.. then initialize il.. then:
+// add_one_arg( argstr, &il );
+//
+static void add_one_arg( char *argstr, intlist *p )
+{
+ int x;
+ if( !check_unsigned_int(argstr,&x) )
+ {
+ fprintf( stderr, "PIA: arg %s must be +int\n", argstr );
+ exit(1);
+ }
+ add_one( x, p );
+}
+
+
+//
+// int nel;
+// int *ilist = parse_int_args( argc, argv, argno, &nel );
+// process all arguments argv[argno..argc-1], extracting either
+// single ints or comma-separated lists of ints from those arguments,
+// accumulate all integers in a dynarray list, storing the total number
+// of elements in nel. This list must be freed by the caller.
+// Note that the list of elements used to be terminated by a -1 value,
+// but I've commented this out from now on.
+//
+int *parse_int_args( int argc, char **argv, int argno, int *nel )
+{
+ int *result = malloc( 128 * sizeof(int) );
+ assert( result );
+ intlist il = { 0, 128, result };
+
+ #if 0
+ if( debug )
+ {
+ printf( "PIA: parsing ints from args %d..%d\n", argno, argc-1 );
+ }
+ #endif
+ for( int i=argno; i<argc; i++ )
+ {
+ assert( strlen(argv[i]) < 1024 );
+ char copy[1024];
+ strcpy( copy, argv[i] );
+ char *com;
+ char *s;
+ for( s=copy; (com = strchr(s,',')) != NULL; s=com+1 )
+ {
+ *com = '\0';
+ add_one_arg( s, &il );
+ }
+ add_one_arg( s, &il );
+ }
+
+ //add_one( -1, &il );
+
+ #if 0
+ if( debug )
+ {
+ printf( "PIA: final list is " );
+ print_int_array( 80, il.nel, il.list, ',', stdout );
+ putchar( '\n' );
+ }
+ #endif
+
+ *nel = il.nel;
+ return il.list;
+}
diff --git a/challenge-192/duncan-c-white/C/parseints.h b/challenge-192/duncan-c-white/C/parseints.h
new file mode 100644
index 0000000000..da5e145a86
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/parseints.h
@@ -0,0 +1 @@
+extern int * parse_int_args( int argc, char ** argv, int argno, int * nel );
diff --git a/challenge-192/duncan-c-white/C/printarray.c b/challenge-192/duncan-c-white/C/printarray.c
new file mode 100644
index 0000000000..ddee597df3
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/printarray.c
@@ -0,0 +1,39 @@
+#include <stdio.h>
+#include <string.h>
+
+
+// print_int_array( maxw, nelements, results[], sep, outfile );
+// format results[0..nelements-1] as a <sep> separated
+// list onto outfile with lines <= maxw chars long.
+// produces a whole number of lines of output - without the trailing '\n'
+void print_int_array( int maxw, int nel, int *results, char sep, FILE *out )
+{
+ int linelen = 0;
+ for( int i=0; i<nel; i++ )
+ {
+ char buf[100];
+ sprintf( buf, "%d", results[i] );
+ int len = strlen(buf);
+ if( linelen + len + 2 > maxw )
+ {
+ fputc( '\n', out );
+ linelen = 0;
+ } else if( i>0 )
+ {
+ fputc( ' ', out );
+ linelen++;
+ }
+
+ linelen += len;
+ fprintf( out, "%s", buf );
+ if( i<nel-1 )
+ {
+ fputc( sep, out );
+ linelen++;
+ }
+ }
+ //if( linelen>0 )
+ //{
+ // fputc( '\n', out );
+ //}
+}
diff --git a/challenge-192/duncan-c-white/C/printarray.h b/challenge-192/duncan-c-white/C/printarray.h
new file mode 100644
index 0000000000..40efb83277
--- /dev/null
+++ b/challenge-192/duncan-c-white/C/printarray.h
@@ -0,0 +1 @@
+extern void print_int_array( int maxw, int nel, int * results, char sep, FILE * out );
diff --git a/challenge-192/duncan-c-white/README b/challenge-192/duncan-c-white/README
index d51cea2c1e..4b7a727129 100644
--- a/challenge-192/duncan-c-white/README
+++ b/challenge-192/duncan-c-white/README
@@ -1,89 +1,98 @@
-Task 1: Task 1: Twice Largest
+Task 1: Binary Flip
-You are given list of integers, @list.
-
-Write a script to find out whether the largest item in the list is at
-least twice as large as each of the other items.
+You are given a positive integer, $n.
+Write a script to find the binary flip.
Example 1
-Input: @list = (1,2,3,4)
-Output: -1
+Input: $n = 5
+Output: 2
-The largest in the given list is 4.
-However 4 is not greater than (dcw:OR EQUAL TO) twice remaining element 3:
-2 x 3 > 4
+First find the binary equivalent of the given integer, 101.
+Then flip the binary digits 0 -> 1 and 1 -> 0 and we get 010.
+So Binary 010 => Decimal 2.
Example 2
-Input: @list = (1,2,0,5)
-Output: 1
+Input: $n = 4
+Output: 3
-The largest in the given list is 5.
-Also 5 is greater than (dcw:OR EQUAL TO) twice of every remaining element.
-1 x 2 <= 5
-2 x 2 <= 5
-0 x 2 <= 5
+Decimal 4 = Binary 100
+Flip 0 -> 1 and 1 -> 0, we get 011.
+Binary 011 = Decimal 3
Example 3
-Input: @list = (2,6,3,1)
+Input: $n = 6
Output: 1
-The largest in the given list is 6.
-Also 6 is greater than (dcw:OR EQUAL TO) twice of every remaining element.
-2 x 2 <= 6
-3 x 2 <= 6
-1 x 2 <= 6
-
-Example 4
-
-Input: @list = (4,5,2,3)
-Output: -1
+Decimal 6 = Binary 110
+Flip 0 -> 1 and 1 -> 0, we get 001.
+Binary 001 = Decimal 1
-The largest in the given list is 5.
-Also 5 is not greater than (dcw:OR EQUAL TO) twice of every remaining element.
-4 x 2 > 5
-2 x 2 <= 5
-3 x 2 > 5
-MY NOTES: very easy, although there's an error in the wording of the examples
-above - to get eg3 to "succeed" (have result 1) it's got to be "max element
-is >= every other element * 2"...
+MY NOTES: very easy. That's ones complement with a bit of range-fixing!
GUEST LANGUAGE: As a bonus, I also had a go at translating ch-1.pl
into C (look in the C directory for the translation)
-Task 2: Cute List
+Task 2: Equal Distribution
+
+You are given a list of integers greater than or equal to zero, @list.
+
+Write a script to distribute the number so that each members are same. If you succeed then print the total moves otherwise print -1.
+
+Please follow the rules (as suggested by Neils van Dijke [2022-11-21 13:00]
+
+1) You can only move a value of '1' per move
+2) You are only allowed to move a value of '1' to a direct neighbor/adjacent cell
-You are given an integer, 0 < $n <= 15.
-Write a script to find the number of orderings of numbers that form a cute list.
+Example 1:
+
+Input: @list = (1, 0, 5)
+Output: 4
+
+Move #1: 1, 1, 4
+(2nd cell gets 1 from the 3rd cell)
+
+Move #2: 1, 2, 3
+(2nd cell gets 1 from the 3rd cell)
+
+Move #3: 2, 1, 3
+(1st cell get 1 from the 2nd cell)
+
+Move #4: 2, 2, 2
+(2nd cell gets 1 from the 3rd cell)
+
+Example 2:
+
+Input: @list = (0, 2, 0)
+Output: -1
+
+It is not possible to make each same.
-With an input @list = (1, 2, 3, .. $n) for positive integer $n, an
-ordering of @list is cute if for every entry, indexed with a base index of
-1, either
+Example 3:
-1) $list[$i] is evenly divisible by $i
-or
-2) $i is evenly divisible by $list[$i]
+Input: @list = (0, 3, 0)
+Output: 2
-Example
+Move #1: 1, 2, 0
+(1st cell gets 1 from the 2nd cell)
-Input: $n = 2
-Ouput: 2
+Move #2: 1, 1, 1
+(3rd cell gets 1 from the 2nd cell)
-Since $n = 2, the list can be made up of two integers only i.e. 1 and 2.
-Therefore we can have two list i.e. (1,2) and (2,1).
-@list = (1,2) is cute since $list[1] = 1 is divisible by 1 and $list[2]
-= 2 is divisible by 2.
+MY NOTES: Hmm.. If I'm understanding that right, it's two passes:
+1. repeatedly find two adjacent cells whose absolute difference > 1
+and transfer one from the bigger cell to the smaller cell.
+2. repeatedly find 2 adjacent cells where firstvalue < secondvalue
+and transfer one from secondvalue to firstvalue
-MY NOTES: Hmm.. isn't every number divisible by 1, doesn't that mean that
-the list[1] check is unnecessary? Looks weird but otherwise reasonably
-straightforward. Obviously need a "next permutation of the list" iterator,
-reusing the one from Challenge 134, adapted slightly.
+Note also that I'm pretty sure that all lists whose sum is divisible
+by 3 can be balanced, and no list whose sum is NOT divisible by 3 can be.
GUEST LANGUAGE: As a bonus, I also had a go at translating ch-2.pl
into C (look in the C directory for the translation)
diff --git a/challenge-192/duncan-c-white/perl/ch-1.pl b/challenge-192/duncan-c-white/perl/ch-1.pl
new file mode 100755
index 0000000000..c7a408b460
--- /dev/null
+++ b/challenge-192/duncan-c-white/perl/ch-1.pl
@@ -0,0 +1,62 @@
+#!/usr/bin/perl
+#
+# Task 1: Binary Flip
+#
+# You are given a positive integer, $n.
+#
+# Write a script to find the binary flip.
+#
+# Example 1
+#
+# Input: $n = 5
+# Output: 2
+#
+# First find the binary equivalent of the given integer, 101.
+# Then flip the binary digits 0 -> 1 and 1 -> 0 and we get 010.
+# So Binary 010 => Decimal 2.
+#
+# Example 2
+#
+# Input: $n = 4
+# Output: 3
+#
+# Decimal 4 = Binary 100
+# Flip 0 -> 1 and 1 -> 0, we get 011.
+# Binary 011 = Decimal 3
+#
+# Example 3
+#
+# Input: $n = 6
+# Output: 1
+#
+# Decimal 6 = Binary 110
+# Flip 0 -> 1 and 1 -> 0, we get 001.
+# Binary 001 = Decimal 1
+#
+# MY NOTES: very easy. That's ones complement with a bit of range-fixing!
+#
+# GUEST LANGUAGE: As a bonus, I also had a go at translating ch-1.pl
+# into C (look in the C directory for the translation)
+#
+
+use strict;
+use warnings;
+use feature 'say';
+use Getopt::Long;
+use Data::Dumper;
+
+my $debug=0;
+die "Usage: binary-flip [--debug] N\n"
+ unless GetOptions( "debug"=>\$debug ) && @ARGV==1;
+
+my $n = shift;
+$n += 0;
+
+my $p = 1;
+while( $p < $n )
+{
+ $p *= 2;
+}
+
+$n = (~ $n) & ($p-1);
+say "$n";
diff --git a/challenge-192/duncan-c-white/perl/ch-2.pl b/challenge-192/duncan-c-white/perl/ch-2.pl
new file mode 100755
index 0000000000..0d2a76c5fb
--- /dev/null
+++ b/challenge-192/duncan-c-white/perl/ch-2.pl
@@ -0,0 +1,154 @@
+#!/usr/bin/perl
+#
+# Task 2: Equal Distribution
+#
+# You are given a list of integers greater than or equal to zero, @list.
+#
+# Write a script to distribute the number so that each members are
+# same. If you succeed then print the total moves otherwise print -1.
+#
+# Please follow the rules (as suggested by Neils van Dijke [2022-11-21 13:00]
+#
+# 1) You can only move a value of '1' per move
+# 2) You are only allowed to move a value of '1' to a direct neighbor/adjacent cell
+#
+# Example 1:
+#
+# Input: @list = (1, 0, 5)
+# Output: 4
+#
+# Move #1: 1, 1, 4
+# (2nd cell gets 1 from the 3rd cell)
+#
+# Move #2: 1, 2, 3
+# (2nd cell gets 1 from the 3rd cell)
+#
+# Move #3: 2, 1, 3
+# (1st cell get 1 from the 2nd cell)
+#
+# Move #4: 2, 2, 2
+# (2nd cell gets 1 from the 3rd cell)
+#
+# Example 2:
+#
+# Input: @list = (0, 2, 0)
+# Output: -1
+#
+# It is not possible to make each same.
+#
+# Example 3:
+#
+# Input: @list = (0, 3, 0)
+# Output: 2
+#
+# Move #1: 1, 2, 0
+# (1st cell gets 1 from the 2nd cell)
+#
+# Move #2: 1, 1, 1
+# (3rd cell gets 1 from the 2nd cell)
+#
+# MY NOTES: Hmm.. If I'm understanding that right, it's two passes:
+# 1. repeatedly find two adjacent cells whose absolute difference > 1
+# and transfer one from the bigger cell to the smaller cell.
+# 2. repeatedly find 2 adjacent cells where firstvalue < secondvalue
+# and transfer one from secondvalue to firstvalue
+#
+# GUEST LANGUAGE: As a bonus, I also had a go at translating ch-2.pl
+# into C (look in the C directory for the translation)
+#
+
+use strict;
+use warnings;
+use feature 'say';
+use Getopt::Long;
+use Function::Parameters;
+use Data::Dumper;
+
+
+my $debug=0;
+die "Usage: same-list [--debug] intlist\n"
+ unless GetOptions( "debug"=>\$debug ) && @ARGV>0;
+
+my @list = split(/,/, join( ',', @ARGV ));
+
+die "same-list: need a list of > 1 elements\n" if @list<2;
+
+
+=pod
+
+=head2 my $pos = find_pair_diff_gt_1(@list);
+
+Find the position $pos of the first element of the first pair in @list
+where the absolute difference between list[$pos] and list[pos+1] is > 1.
+Return -1 if none.
+
+=cut
+fun find_pair_diff_gt_1( @list )
+{
+ for( my $pos=0; $pos<@list-1; $pos++ )
+ {
+ return $pos if abs( $list[$pos] - $list[$pos+1] ) > 1;
+ }
+ return -1;
+}
+
+
+
+=pod
+
+=head2 my $pos = find_pair_f_lt_s(@list);
+
+Find the position $pos of the first element of a pair in @list
+where list[$pos] < list[pos+1]. Return -1 if none.
+
+=cut
+fun find_pair_f_lt_s( @list )
+{
+ for( my $pos=0; $pos<@list-1; $pos++ )
+ {
+ return $pos if $list[$pos] < $list[$pos+1];
+ }
+ return -1;
+}
+
+
+my $nmoves = 0;
+
+say "starting first pass" if $debug;
+
+# first pass: repeatedly find two adjacent cells whose absolute difference > 1
+# and transfer one from the bigger cell to the smaller cell.
+while( (my $pos = f