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| author | Michael Firkins <michael@firkins> | 2023-10-10 13:45:39 +1100 |
|---|---|---|
| committer | Michael Firkins <michael@firkins> | 2023-10-10 13:45:39 +1100 |
| commit | 962c2aa4bebf9d52f59e1384e804fc620afa7cd6 (patch) | |
| tree | 7c2788cbef89fa73c87cbd997430a4412fac8d3a | |
| parent | de215720df537a15de474f0125f2994651be09c5 (diff) | |
| download | perlweeklychallenge-club-962c2aa4bebf9d52f59e1384e804fc620afa7cd6.tar.gz perlweeklychallenge-club-962c2aa4bebf9d52f59e1384e804fc620afa7cd6.tar.bz2 perlweeklychallenge-club-962c2aa4bebf9d52f59e1384e804fc620afa7cd6.zip | |
pwc238 solution in go
| -rw-r--r-- | challenge-238/pokgopun/go/ch-1.go | 59 | ||||
| -rw-r--r-- | challenge-238/pokgopun/go/ch-2.go | 82 |
2 files changed, 141 insertions, 0 deletions
diff --git a/challenge-238/pokgopun/go/ch-1.go b/challenge-238/pokgopun/go/ch-1.go new file mode 100644 index 0000000000..e429633daf --- /dev/null +++ b/challenge-238/pokgopun/go/ch-1.go @@ -0,0 +1,59 @@ +//# https://theweeklychallenge.org/blog/perl-weekly-challenge-238/ +/*# + +Task 1: Running Sum + +Submitted by: [43]Mohammad S Anwar + __________________________________________________________________ + + You are given an array of integers. + + Write a script to return the running sum of the given array. The + running sum can be calculated as sum[i] = num[0] + num[1] + …. + + num[i]. + +Example 1 + +Input: @int = (1, 2, 3, 4, 5) +Output: (1, 3, 6, 10, 15) + +Example 2 + +Input: @int = (1, 1, 1, 1, 1) +Output: (1, 2, 3, 4, 5) + +Example 3 + +Input: @int = (0, -1, 1, 2) +Output: (0, -1, 0, 2) + +Task 2: Persistence Sort +#*/ +//# solution by pokgopun@gmail.com + +package main + +import ( + "fmt" + "slices" +) + +func main() { + for _, data := range []struct { + input, output []int + }{ + {[]int{1, 2, 3, 4, 5}, []int{1, 3, 6, 10, 15}}, + {[]int{1, 1, 1, 1, 1}, []int{1, 2, 3, 4, 5}}, + {[]int{0, -1, 1, 2}, []int{0, -1, 0, 2}}, + } { + fmt.Println(slices.Equal(runningSum(data.input), data.output)) + } +} + +func runningSum(s []int) []int { + l := len(s) + for i := 1; i < l; i++ { + s[i] += s[i-1] + } + return s +} diff --git a/challenge-238/pokgopun/go/ch-2.go b/challenge-238/pokgopun/go/ch-2.go new file mode 100644 index 0000000000..b0cff2d66e --- /dev/null +++ b/challenge-238/pokgopun/go/ch-2.go @@ -0,0 +1,82 @@ +//# https://theweeklychallenge.org/blog/perl-weekly-challenge-238/ +/*# + +Task 2: Persistence Sort + +Submitted by: [44]Mohammad S Anwar + __________________________________________________________________ + + You are given an array of positive integers. + + Write a script to sort the given array in increasing order with respect + to the count of steps required to obtain a single-digit number by + multiplying its digits recursively for each array element. If any two + numbers have the same count of steps, then print the smaller number + first. + +Example 1 + +Input: @int = (15, 99, 1, 34) +Output: (1, 15, 34, 99) + +15 => 1 x 5 => 5 (1 step) +99 => 9 x 9 => 81 => 8 x 1 => 8 (2 steps) +1 => 0 step +34 => 3 x 4 => 12 => 1 x 2 => 2 (2 steps) + +Example 2 + +Input: @int = (50, 25, 33, 22) +Output: (22, 33, 50, 25) + +50 => 5 x 0 => 0 (1 step) +25 => 2 x 5 => 10 => 1 x 0 => 0 (2 steps) +33 => 3 x 3 => 9 (1 step) +22 => 2 x 2 => 4 (1 step) + __________________________________________________________________ + + Last date to submit the solution 23:59 (UK Time) Sunday 15th October + 2023. + __________________________________________________________________ + +SO WHAT DO YOU THINK ? +#*/ +//# solution by pokgopun@gmail.com + +package main + +import ( + "fmt" + "slices" + "sort" + "strconv" +) + +func main() { + for _, data := range []struct { + input, output []int + }{ + {[]int{15, 99, 1, 34}, []int{1, 15, 34, 99}}, + {[]int{50, 25, 33, 22}, []int{22, 33, 50, 25}}, + } { + sort.SliceStable(data.input, func(i, j int) bool { + return true + }) + sort.SliceStable(data.input, func(i, j int) bool { + return mk1dgt(data.input[i]) < mk1dgt(data.input[j]) + }) + fmt.Println(slices.Equal(data.input, data.output)) + } +} + +func mk1dgt(n int) (i int) { + for n > 9 { + i++ + r := 1 + for _, v := range strconv.Itoa(n) { + r *= int(v) - 48 + } + n = r + } + return i +} |
