Add dot challenge for 145

Adds answer for dot challenge

2 files changed, 40 insertions, 0 deletions

diff --git a/challenge-145/morayj/README b/challenge-145/morayj/README
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index 0000000000..1f63642b40
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+++ b/challenge-145/morayj/README
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+Solution by Moray Jones
diff --git a/challenge-145/morayj/raku/ch-1.raku b/challenge-145/morayj/raku/ch-1.raku
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index 0000000000..f797812988
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+++ b/challenge-145/morayj/raku/ch-1.raku
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+my Int @a = (1,2,3,10);
+my Int @b = (3,4,3,2);
+
+# I saw the challenge and thought 'Z' the zip operator
+# Wanted to give it a go
+
+# First created a separate array with the zipped original arrays
+# This creates an array of 2 member lists
+
+my List @c = @a Z @b;
+
+# Tried a raku pointy block to unpack the pairs
+
+my Int $total = 0;
+for @c -> ($i, $j) {
+    $total = $total + ($i * $j);
+}
+say $total;
+
+# But could also use flat to flatten the lists
+# I like the 'reduction metaoperators' so use that
+# for the multiplication
+
+$total = 0;
+for @c {
+    $total = $total + ([*] flat $_);
+}
+say $total;
+
+# But then if using a loop, could use a map
+# Dispense with the @c array step
+# Can also use flat as a method on implied topic
+
+say [+] (@a Z @b).map: {([*] .flat)};
+
+# But checking the 'Z' documentation again
+# Z can do the map work itself it turns out
+
+say [+] @a Z* @b;