add solutions week 279 in python

2 files changed, 55 insertions, 0 deletions

diff --git a/challenge-279/steven-wilson/python/ch-1.py b/challenge-279/steven-wilson/python/ch-1.py
new file mode 100644
index 0000000000..755c3b4141
--- /dev/null
+++ b/challenge-279/steven-wilson/python/ch-1.py
@@ -0,0 +1,20 @@
+#!/usr/bin/env python3
+
+
+def sort_letters(letters, weights):
+    """ Given two arrays, sort the given array letters based on the weights.
+    >>> sort_letters(('R', 'E', 'P', 'L'), (3, 2, 1, 4))
+    'PERL'
+    >>> sort_letters(('A', 'U', 'R', 'K'), (2, 4, 1, 3))
+    'RAKU'
+    >>> sort_letters(('O', 'H', 'Y', 'N', 'P', 'T'), (5, 4, 2, 6, 1, 3))
+    'PYTHON'
+    """
+    letters_sorted = (l for _, l in sorted(zip(weights, letters)))
+    return "".join(letters_sorted)
+
+
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod(verbose=True)
diff --git a/challenge-279/steven-wilson/python/ch-2.py b/challenge-279/steven-wilson/python/ch-2.py
new file mode 100644
index 0000000000..be2b25d38f
--- /dev/null
+++ b/challenge-279/steven-wilson/python/ch-2.py
@@ -0,0 +1,35 @@
+#!/usr/bin/env python3
+
+from pprint import pprint
+
+
+def split_string(string, print_strings=False):
+    """ Given a string, split the given string into two containing exactly same
+    number of vowels and return true if you can otherwise false.
+    >>> split_string("perl")
+    False
+    >>> split_string("book")
+    True
+    >>> split_string("good morning")
+    True
+    """
+    if len(string) < 2:
+        return False
+
+    position_vowels = [i for i, c in enumerate(string) if c.casefold() in 'aeiou']
+
+    if not len(position_vowels) % 2 == 0:
+        return False
+
+    if print_strings:
+        split_index = int(len(position_vowels)/2) - 1
+        (start, stop) = (position_vowels[split_index], position_vowels[split_index+1])
+        pprint([(string[:i+1], string[i+1:]) for i in range(start, stop)])
+
+    return True
+
+
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod(verbose=True)