Merge pull request #10353 from pokgopun/pwc276

Pwc276

4 files changed, 303 insertions, 0 deletions

diff --git a/challenge-276/pokgopun/go/ch-1.go b/challenge-276/pokgopun/go/ch-1.go
new file mode 100644
index 0000000000..ba9885236e
--- /dev/null
+++ b/challenge-276/pokgopun/go/ch-1.go
@@ -0,0 +1,83 @@
+//# https://theweeklychallenge.org/blog/perl-weekly-challenge-276/
+/*#
+
+Task 1: Complete Day
+
+Submitted by: [41]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given an array of integers, @hours.
+
+   Write a script to return the number of pairs that forms a complete day.
+
+     A complete day is defined as a time duration that is an exact
+     multiple of 24 hours.
+
+Example 1
+
+Input: @hours = (12, 12, 30, 24, 24)
+Output: 2
+
+Pair 1: (12, 12)
+Pair 2: (24, 24)
+
+Example 2
+
+Input: @hours = (72, 48, 24, 5)
+Output: 3
+
+Pair 1: (72, 48)
+Pair 2: (72, 24)
+Pair 3: (48, 24)
+
+Example 3
+
+Input: @hours = (12, 18, 24)
+Output: 0
+
+Task 2: Maximum Frequency
+#*/
+//# solution by pokgopun@gmail.com
+
+package main
+
+import (
+	"io"
+	"os"
+
+	"github.com/google/go-cmp/cmp"
+)
+
+type hour int
+
+func (hr hour) isCompleteDay() bool {
+	return hr%24 == 0
+}
+
+type hours []hour
+
+func (hrs hours) countCompleteDayPair() int {
+	c := 0
+	l := len(hrs)
+	for i := 0; i < l-1; i++ {
+		for j := i + 1; j < l; j++ {
+			if (hrs[i] + hrs[j]).isCompleteDay() {
+				c++
+			}
+		}
+	}
+	return c
+}
+
+func main() {
+	for _, data := range []struct {
+		input  hours
+		output int
+	}{
+		{hours{12, 12, 30, 24, 24}, 2},
+		{hours{72, 48, 24, 5}, 3},
+		{hours{12, 18, 24}, 0},
+	} {
+		io.WriteString(os.Stdout, cmp.Diff(data.input.countCompleteDayPair(), data.output)) // blank if ok, otherwise show the difference
+	}
+}
diff --git a/challenge-276/pokgopun/go/ch-2.go b/challenge-276/pokgopun/go/ch-2.go
new file mode 100644
index 0000000000..38f9f25037
--- /dev/null
+++ b/challenge-276/pokgopun/go/ch-2.go
@@ -0,0 +1,105 @@
+//# https://theweeklychallenge.org/blog/perl-weekly-challenge-276/
+/*#
+
+Task 2: Maximum Frequency
+
+Submitted by: [42]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given an array of positive integers, @ints.
+
+   Write a script to return the total number of elements in the given
+   array which have the highest frequency.
+
+Example 1
+
+Input: @ints = (1, 2, 2, 4, 1, 5)
+Ouput: 4
+
+The maximum frequency is 2.
+The elements 1 and 2 has the maximum frequency.
+
+Example 2
+
+Input: @ints = (1, 2, 3, 4, 5)
+Ouput: 5
+
+The maximum frequency is 1.
+The elements 1, 2, 3, 4 and 5 has the maximum frequency.
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 7th July 2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+#*/
+//# solution by pokgopun@gmail.com
+
+package main
+
+import (
+	"io"
+	"os"
+
+	"github.com/google/go-cmp/cmp"
+)
+
+type intCount struct {
+	int, count int
+}
+
+type ints []int
+
+func (is ints) uniqInts() ints {
+	seen := make(map[int]bool)
+	var s ints
+	for _, v := range is {
+		if seen[v] {
+			continue
+		}
+		seen[v] = true
+		s = append(s, v)
+	}
+	return s
+}
+
+func (is ints) intCounts() []intCount {
+	var s []intCount
+	for _, v := range is.uniqInts() {
+		c := 0
+		for _, e := range is {
+			if e == v {
+				c++
+			}
+		}
+		s = append(s, intCount{v, c})
+	}
+	return s
+}
+
+func (is ints) maxFreq() int {
+	intCounts := is.intCounts()
+	mx := intCounts[0].count
+	for _, v := range intCounts[1:] {
+		mx = max(mx, v.count)
+	}
+	c := 0
+	for _, v := range intCounts {
+		if v.count == mx {
+			c += mx
+		}
+	}
+	return c
+}
+
+func main() {
+	for _, data := range []struct {
+		input  ints
+		output int
+	}{
+		{ints{1, 2, 2, 4, 1, 5}, 4},
+		{ints{1, 2, 3, 4, 5}, 5},
+	} {
+		io.WriteString(os.Stdout, cmp.Diff(data.input.maxFreq(), data.output)) // blank if ok, otherwise show the difference
+	}
+}
diff --git a/challenge-276/pokgopun/python/ch-1.py b/challenge-276/pokgopun/python/ch-1.py
new file mode 100644
index 0000000000..9e9f3c784f
--- /dev/null
+++ b/challenge-276/pokgopun/python/ch-1.py
@@ -0,0 +1,62 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-276/
+"""
+
+Task 1: Complete Day
+
+Submitted by: [41]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given an array of integers, @hours.
+
+   Write a script to return the number of pairs that forms a complete day.
+
+     A complete day is defined as a time duration that is an exact
+     multiple of 24 hours.
+
+Example 1
+
+Input: @hours = (12, 12, 30, 24, 24)
+Output: 2
+
+Pair 1: (12, 12)
+Pair 2: (24, 24)
+
+Example 2
+
+Input: @hours = (72, 48, 24, 5)
+Output: 3
+
+Pair 1: (72, 48)
+Pair 2: (72, 24)
+Pair 3: (48, 24)
+
+Example 3
+
+Input: @hours = (12, 18, 24)
+Output: 0
+
+Task 2: Maximum Frequency
+"""
+### solution by pokgopun@gmail.com
+
+def completeDay(hours: tuple):
+    c = 0
+    l = len(hours)
+    for i in range(l-1):
+        for j in range(i+1, l):
+            if (hours[i] + hours[j]) % 24 == 0:
+                c += 1
+    return c
+
+import unittest
+
+class TestCompleteDay(unittest.TestCase):
+    def test(self):
+        for inpt, otpt in {
+                (12, 12, 30, 24, 24): 2,
+                (72, 48, 24, 5): 3,
+                (12, 18, 24): 0,
+                }.items():
+            self.assertEqual(completeDay(inpt),otpt)
+
+unittest.main()
diff --git a/challenge-276/pokgopun/python/ch-2.py b/challenge-276/pokgopun/python/ch-2.py
new file mode 100644
index 0000000000..358fed0eb9
--- /dev/null
+++ b/challenge-276/pokgopun/python/ch-2.py
@@ -0,0 +1,53 @@
+### https://theweeklychallenge.org/blog/perl-weekly-challenge-276/
+"""
+
+Task 2: Maximum Frequency
+
+Submitted by: [42]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given an array of positive integers, @ints.
+
+   Write a script to return the total number of elements in the given
+   array which have the highest frequency.
+
+Example 1
+
+Input: @ints = (1, 2, 2, 4, 1, 5)
+Ouput: 4
+
+The maximum frequency is 2.
+The elements 1 and 2 has the maximum frequency.
+
+Example 2
+
+Input: @ints = (1, 2, 3, 4, 5)
+Ouput: 5
+
+The maximum frequency is 1.
+The elements 1, 2, 3, 4 and 5 has the maximum frequency.
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 7th July 2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def maxFreq(ints: tuple):
+    ic = tuple((e, ints.count(e)) for e in set(ints))
+    mf = max(e[1] for e in ic)
+    return sum( mf for e in ic if e[1]==mf)
+
+import unittest
+
+class TestMaxFreq(unittest.TestCase):
+    def test(self):
+        for inpt,otpt in {
+                (1, 2, 2, 4, 1, 5): 4,
+                (1, 2, 3, 4, 5): 5,
+                }.items():
+            self.assertEqual(maxFreq(inpt),otpt)
+
+unittest.main()