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| author | Abigail <abigail@abigail.be> | 2020-11-06 23:52:10 +0100 |
|---|---|---|
| committer | Abigail <abigail@abigail.be> | 2020-11-06 23:52:10 +0100 |
| commit | efe40d5b692e19806f2a039a8553b24d88b640ff (patch) | |
| tree | 011be9a179c3867c34c22244e82059e86aa5f934 | |
| parent | 9128eabe9a14da6cdfb0339edb15e0df9fcce1ed (diff) | |
| download | perlweeklychallenge-club-efe40d5b692e19806f2a039a8553b24d88b640ff.tar.gz perlweeklychallenge-club-efe40d5b692e19806f2a039a8553b24d88b640ff.tar.bz2 perlweeklychallenge-club-efe40d5b692e19806f2a039a8553b24d88b640ff.zip | |
Fix line widths
| -rw-r--r-- | challenge-085/abigail/c/ch-1.c | 15 |
1 files changed, 8 insertions, 7 deletions
diff --git a/challenge-085/abigail/c/ch-1.c b/challenge-085/abigail/c/ch-1.c index 60daa6c0a5..edfcc8fa03 100644 --- a/challenge-085/abigail/c/ch-1.c +++ b/challenge-085/abigail/c/ch-1.c @@ -51,8 +51,9 @@ int cmp (const void * a, const void * b) { * The numbers in array are sorted. */ ssize_t bin_search (float * array, float target, size_t min, size_t max) { - size_t mid = (min + max) / 2; /* In C, dividing integers yields an integer * - * so there is no need for flooring. */ + size_t mid = (min + max) / 2; /* In C, dividing integers yields an * + * integer, so there is no need for * + * flooring. */ return min >= max || array [min] >= target ? NOT_FOUND @@ -83,7 +84,7 @@ int main (void) { * Iterate over the input, reading one line at a time */ while ((length = getline (&line, &len, stdin)) != -1) { - size_t size = 0; /* Number of floats in array. */ + size_t size = 0; /* Number of floats in array. */ int offset; float input; char * line_ptr = line; @@ -104,8 +105,8 @@ int main (void) { if (++ size >= buf_size) { /* Get some more memory. */ buf_size = (size_t) floorf (buf_size * BUF_INCREMENT); - if ((array = (float *) - realloc (array, buf_size * sizeof (float))) == NULL) { + if ((array = (float *) realloc (array, + buf_size * sizeof (float))) == NULL) { fprintf (stderr, "Out of memory\n"); return (1); } @@ -126,8 +127,8 @@ int main (void) { * We will iterate over all i, j, with i < j, and for each * such pair, use binary search to find whether there is a k. * - * We can stop searching if we either have a winning triplet (duh), - * or if 3 * array [i] >= MAX, since array [i] <= array [j] <= array [k]. + * We can stop searching if we either have a winning triplet (duh), or + * if 3 * array [i] >= MAX, since array [i] <= array [j] <= array [k]. * For a given i, we can stop searching for a pair j, k when * array [i] + 2 * array [j] >= MAX, for the same reason. */ |
