pwc242 solution in python

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diff --git a/challenge-242/pokgopun/python/ch-1.py b/challenge-242/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-242/
+"""
+
+Task 1: Missing Members
+
+Submitted by: [42]Mohammad S Anwar
+     __________________________________________________________________
+
+   You are given two arrays of integers.
+
+   Write a script to find out the missing members in each other arrays.
+
+Example 1
+
+Input: @arr1 = (1, 2, 3)
+       @arr2 = (2, 4, 6)
+Output: ([1, 3], [4, 6])
+
+(1, 2, 3) has 2 members (1, 3) missing in the array (2, 4, 6).
+(2, 4, 6) has 2 members (4, 6) missing in the array (1, 2, 3).
+
+Example 2
+
+Input: @arr1 = (1, 2, 3, 3)
+       @arr2 = (1, 1, 2, 2)
+Output: ([3])
+
+(1, 2, 3, 3) has 2 members (3, 3) missing in the array (1, 1, 2, 2). Since they
+are same, keep just one.
+(1, 1, 2, 2) has 0 member missing in the array (1, 2, 3, 3).
+
+Task 2: Flip Matrix
+"""
+### solution by pokgopun@gmail.com
+
+def findMissing(tup1, tup2):
+    return tuple(
+            filter(lambda x: len(x) > 0,
+                (
+                    set(tup1).difference(set(tup2)),
+                    set(tup2).difference(set(tup1)),
+                    )
+                )
+            )
+
+
+
+for (inpt1,inpt2),otpt in {
+        ((1, 2, 3),(2, 4, 6)): ({1, 3}, {4, 6}),
+        ((1, 2, 3, 3),(1, 1, 2, 2)): ({3},),
+        }.items():
+    print(findMissing(inpt1,inpt2)==otpt)
+
+
+
diff --git a/challenge-242/pokgopun/python/ch-2.py b/challenge-242/pokgopun/python/ch-2.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-242/
+"""
+
+Task 2: Flip Matrix
+
+Submitted by: [43]Mohammad S Anwar
+     __________________________________________________________________
+
+   You are given n x n binary matrix.
+
+   Write a script to flip the given matrix as below.
+1 1 0
+0 1 1
+0 0 1
+
+a) Reverse each row
+
+0 1 1
+1 1 0
+1 0 0
+
+b) Invert each member
+
+1 0 0
+0 0 1
+0 1 1
+
+Example 1
+
+Input: @matrix = ([1, 1, 0], [1, 0, 1], [0, 0, 0])
+Output: ([1, 0, 0], [0, 1, 0], [1, 1, 1])
+
+Example 2
+
+Input: @matrix = ([1, 1, 0, 0], [1, 0, 0, 1], [0, 1, 1, 1], [1, 0, 1, 0])
+Output: ([1, 1, 0, 0], [0, 1, 1, 0], [0, 0, 0, 1], [1, 0, 1, 0])
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 12th November
+   2023.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def flipMatrix(tup):
+    return tuple(
+            map(lambda x: tuple( i ^ 1 for i in reversed(x)) , tup)
+            )
+
+
+for inpt,otpt in {
+        ((1, 1, 0), (1, 0, 1), (0, 0, 0)): ((1, 0, 0), (0, 1, 0), (1, 1, 1)),
+        ((1, 1, 0, 0), (1, 0, 0, 1), (0, 1, 1, 1), (1, 0, 1, 0)): ((1, 1, 0, 0), (0, 1, 1, 0), (0, 0, 0, 1), (1, 0, 1, 0)),
+        }.items():
+    print(flipMatrix(inpt)==otpt)