Added solution for challenge-001.

4 files changed, 42 insertions, 0 deletions

diff --git a/challenge-001/adam-russell/README b/challenge-001/adam-russell/README
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+Solution by Adam Russell
diff --git a/challenge-001/adam-russell/blog.txt b/challenge-001/adam-russell/blog.txt
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+https://adamcrussell.livejournal.com/269.html
diff --git a/challenge-001/adam-russell/perl5/ch-1.pl b/challenge-001/adam-russell/perl5/ch-1.pl
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+++ b/challenge-001/adam-russell/perl5/ch-1.pl
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+use strict;
+use warnings; 
+##
+# Challenge #1
+# Write a script to replace the character 'e' with 'E' in the string 'Perl Weekly Challenge'. 
+# Also print the number of times the character 'e' is found in the string.
+##
+my $challenge_string="Perl Weekly Challenge";
+my $number=do{
+    $challenge_string=~tr/e/E/
+};
+print "$number $challenge_string\n"; 
diff --git a/challenge-001/adam-russell/perl5/ch-2.pl b/challenge-001/adam-russell/perl5/ch-2.pl
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+use strict;
+use warnings; 
+##
+# Challenge #2
+# Write one-liner to solve FizzBuzz problem and print number 1-20. 
+# However, any number divisible by 3 should be replaced by the word fizz 
+# and any divisible by 5 by the word buzz. Numbers divisible by both become fizz buzz.
+##
+use experimental q/switch/;   
+my $i = 1;
+{
+    given($i){
+        when($i % 3 == 0 && $i % 5 == 0){ 
+            print "fizz buzz\n";  
+        } 
+        when($i % 5 == 0){
+            print "buzz\n"; 
+        }  
+        when($i % 3 == 0){
+            print "fizz\n"; 
+        }  
+        default{
+            print "$i\n";  
+        } 
+    }  
+    $i++;  
+    redo until ($i > 20);
+}