Add python solution to challenge 004

2 files changed, 53 insertions, 0 deletions

diff --git a/challenge-004/paulo-custodio/python/ch-1.py b/challenge-004/paulo-custodio/python/ch-1.py
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+++ b/challenge-004/paulo-custodio/python/ch-1.py
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+#!/usr/bin/env python3
+
+# Challenge 004
+#
+# Challenge #1
+# Write a script to output the same number of PI digits as the size of your script.
+# Say, if your script size is 10, it should print 3.141592653.
+
+import math_pi                      # pip install math-pi
+import os;
+
+size = os.path.getsize(__file__)
+print(math_pi.pi(b=size-1))         # -1 to account for "3."
diff --git a/challenge-004/paulo-custodio/python/ch-2.py b/challenge-004/paulo-custodio/python/ch-2.py
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+++ b/challenge-004/paulo-custodio/python/ch-2.py
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+#!/usr/bin/env python3
+
+# Challenge 004
+#
+# Challenge #2
+# You are given a file containing a list of words (case insensitive 1 word per
+# line) and a list of letters. Print each word from the file that can be made
+# using only letters from the list. You can use each letter only once (though
+# there can be duplicates and you can use each of them once), you don't have to
+# use all the letters.
+# (Disclaimer: The challenge was proposed by Scimon Proctor)
+
+import sys
+import re
+
+def isalpha(word):
+    if re.fullmatch(r"[a-zA-Z]+", word):
+        return True
+    else:
+        return False
+
+def matches_letters(word, letters):
+    for c in letters:
+        word = re.sub(c, "", word, 1)
+        if word == "":
+            return True
+    return False
+
+def print_matching(file, letters):
+    letters = letters.lower()
+    fp = open(file, 'r')
+    for line in fp.readlines():
+        word = line.strip()
+        if isalpha(word) and len(word) >= 2 and matches_letters(word, letters):
+            print(word)
+
+if len(sys.argv) != 2:
+    print("Usage: ch-2.py letters")
+else:
+    print_matching("words.txt", sys.argv[1])