Merge pull request #1444 from user-person/branch-for-challenge-052

User-person's solutions for challenge 052.

1 files changed, 128 insertions, 0 deletions

diff --git a/challenge-052/user-person/python/ch-2.py b/challenge-052/user-person/python/ch-2.py
new file mode 100755
index 0000000000..da402bb7db
--- /dev/null
+++ b/challenge-052/user-person/python/ch-2.py
@@ -0,0 +1,128 @@
+#!/usr/bin/env python3
+
+###########################################################################
+# script name: ch-2.py                                                    #
+#                                                                         #
+# https://github.com/user-person                                          #
+#                                                                         #
+# https://perlweeklychallenge.org/blog/perl-weekly-challenge-052/         #
+#                                                                         #
+# Lucky Winner                                                            #
+# Suppose there are following coins arranged on a table in a line in      #
+# random order                                                            #
+#                                                                         #
+# 1, 50p, 1p, 10p, 5p, 2, 2p                                              #
+#                                                                         #
+# Suppose you are playing against the computer. Player can only pick one  #
+# coin at a time from either ends. Find out the lucky winner, who has     #
+# the larger amounts in total?20p, order.                                 #
+#                                                                         #
+###########################################################################
+
+# Coins total 3.88. 2 > 1.88 . If a player gets the L2 coin they win the game.
+
+# Given sufficiently intelligent players, whoever gets the first turn wins the game.
+
+import random
+import readline
+
+coins = [ '1p', '2p', '5p', '10p', '20p', '50p', 'L1', 'L2' ]
+
+random.shuffle(coins)
+
+coinVal = { '1p' : 0.01, '2p' : 0.02, '5p' : 0.05, '10p' : 0.10, \
+                '20p' : 0.20, '50p' : 0.50, 'L1' : 1.00, 'L2' : 2.00 }
+
+bank = { 'player' : 0, 'computer' : 0 }
+
+turn = random.choice([True,False])
+
+def l2Index():
+    ret = -1
+    for i in range(len(coins)-1):
+        if coins[i] == 'L2':
+           ret = i
+           break
+    return ret
+
+def takeCoin(choice,who):
+    if choice == 'f':
+        bank[who] += coinVal[ coins.pop(0) ]
+    else:                                    # "If you ain't first, you're last."
+        bank[who] += coinVal[ coins.pop(-1) ]
+
+    print(who + ': ' + '{:.2f}'.format(bank[who]) + '\n')
+
+def playerChoice():
+    fl = ''
+    loop = True
+
+    prompt = "Type 'f' to choose the first coin. Type 'l' to choose the last coin. Type 'q' to quit:" ;
+    if len(coins) > 1:
+        print(prompt)
+
+    while loop:
+        
+        loop = False
+        
+        if len(coins) == 1:     # Don't ask when there's only one choice.
+            takeCoin( 'f', 'player')
+            continue
+
+        fl = input('> ')
+
+        if fl == 'f' or fl == 'l':
+            takeCoin( fl, 'player')
+        elif fl == 'q':
+            exit()
+        else:
+            print('Invalid choice')
+            loop = True
+
+def chooseGreater():
+    if coinVal[ coins[0] ] > coinVal[ coins[-1] ] :
+        takeCoin('f','computer')
+    else:
+        takeCoin('l','computer')
+
+def computerChoice():
+    
+    # Grabs L2 off the end when available
+    # Doesn't grab the item before L2 to free it up for player to win.
+    # Otherwise, grabs whichever end is greater.
+    # It doesn't always get the highest points, but it wins when that's possible.
+
+    ind = l2Index()
+
+    if len(coins) == 3:         # Without this statement computer always chooses last (third)
+        chooseGreater()         # when protecting L2 ( e.g. [first], L2, [last] )
+                                # even if first is greater.
+    else:
+
+        if ind == 0 or ind == len(coins)-2:
+            takeCoin('f','computer')
+
+        elif ind == len(coins)-1 or ind == 1:
+            takeCoin('l','computer')
+
+        else:
+            chooseGreater()
+
+while len(coins):
+    for c in coins:
+        print(c,end=' ')
+    print()
+    
+    if turn:
+        playerChoice()
+        turn = False
+    else:
+        computerChoice()
+        turn = True
+
+if bank['computer'] > bank['player']:
+    print('Computer Wins. Computer: L ' + '{:.2f}'.format(bank['computer']) \
+              + ' Player: L ' + '{:.2f}'.format(bank['player']) + '\n')
+else:
+    print('Player Wins. Player: L ' + '{:.2f}'.format(bank['player']) \
+                  + ' Computer: L ' + '{:.2f}'.format(bank['computer']) + '\n')