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authordrbaggy <js5@sanger.ac.uk>2021-08-16 10:55:39 +0100
committerdrbaggy <js5@sanger.ac.uk>2021-08-16 10:55:39 +0100
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first submit - working on better solution for ch-1.pl - there is some pattern in 9^n coming here which I need to get my head round 10^n has 9^n-1 numbers, 2.10^n had 2.9^n numbers, 9.10^n has 8.9^n numbers etc - so should be an easy way to get arbitrary large numbers without a scan!
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