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| author | Mohammad Sajid Anwar <Mohammad.Anwar@yahoo.com> | 2024-09-18 19:59:32 +0100 |
|---|---|---|
| committer | GitHub <noreply@github.com> | 2024-09-18 19:59:32 +0100 |
| commit | 85073f31dae3decce780d1fd66cdcb79c82c7f65 (patch) | |
| tree | 318d3bc02836f4cde215f7f15e9ec875c74a1490 /challenge-060/paulo-custodio/python | |
| parent | bfe139d559d498bcf1ae48cc08520bfc99ee9b85 (diff) | |
| parent | 51c035e04c5ae5f9f02555206f57eb675a737617 (diff) | |
| download | perlweeklychallenge-club-85073f31dae3decce780d1fd66cdcb79c82c7f65.tar.gz perlweeklychallenge-club-85073f31dae3decce780d1fd66cdcb79c82c7f65.tar.bz2 perlweeklychallenge-club-85073f31dae3decce780d1fd66cdcb79c82c7f65.zip | |
Merge pull request #10860 from pauloscustodio/master
Add Python solutions
Diffstat (limited to 'challenge-060/paulo-custodio/python')
| -rw-r--r-- | challenge-060/paulo-custodio/python/ch-1.py | 43 | ||||
| -rw-r--r-- | challenge-060/paulo-custodio/python/ch-2.py | 50 |
2 files changed, 93 insertions, 0 deletions
diff --git a/challenge-060/paulo-custodio/python/ch-1.py b/challenge-060/paulo-custodio/python/ch-1.py new file mode 100644 index 0000000000..10efd3a1fc --- /dev/null +++ b/challenge-060/paulo-custodio/python/ch-1.py @@ -0,0 +1,43 @@ +#!/usr/bin/env python3 + +# Challenge 060 +# +# TASK #1 > Excel Column +# Reviewed by: Ryan Thompson +# Write a script that accepts a number and returns the Excel Column Name it +# represents and vice-versa. +# +# Excel columns start at A and increase lexicographically using the 26 letters +# of the English alphabet, A..Z. After Z, the columns pick up an extra "digit", +# going from AA, AB, etc., which could (in theory) continue to an arbitrary +# number of digits. In practice, Excel sheets are limited to 16,384 columns. +# +# Example +# Input Number: 28 +# Output: AB +# +# Input Column Name: AD +# Output: 30 + +import re +import sys + +def col2num(col): + num = 0 + for digit in col: + num = 26*num + ord(digit)-ord('A') + 1 + return num + +def num2col(num): + col = "" + while num > 0: + digit = (num-1) % 26 + num = int((num-1) / 26) + col = chr(ord('A')+digit) + col + return col + +arg = sys.argv[1] +if re.search(r'^\d+$', arg): + print(num2col(int(arg))) +else: + print(col2num(arg)) diff --git a/challenge-060/paulo-custodio/python/ch-2.py b/challenge-060/paulo-custodio/python/ch-2.py new file mode 100644 index 0000000000..5a159ce266 --- /dev/null +++ b/challenge-060/paulo-custodio/python/ch-2.py @@ -0,0 +1,50 @@ +#!/usr/bin/env python3 + +# Challenge 060 +# +# TASK #2 > Find Numbers +# Reviewed by: Ryan Thompson +# Write a script that accepts list of positive numbers (@L) and two positive +# numbers $X and $Y. +# +# The script should print all possible numbers made by concatenating the numbers +# from @L, whose length is exactly $X but value is less than $Y. +# +# Example +# Input: +# +# @L = (0, 1, 2, 5); +# $X = 2; +# $Y = 21; +# Output: +# +# 10, 11, 12, 15, 20 + +import sys + +def combine1(combin, prefix, n, digits): + if len(prefix) == n: + num = int(prefix) + if not num in combin: + combin.add(num) + else: + for digit in digits: + combine1(combin, prefix+digit, n, digits) + +def combine(digits): + combin = set() + for n in range(1, len(digits)+1): + combine1(combin, "", n, digits) + nums = sorted(list(combin)) + return nums + +def numbers(X, Y, L): + nums = combine(L) + nums = list(filter(lambda x:len(str(x))==X and x<Y, nums)) + return nums + +X = int(sys.argv[1]) +Y = int(sys.argv[2]) +L = sys.argv[3:] +nums = numbers(X, Y, L) +print(", ".join(map(str, nums))) |
